I am having a problem with the package SSPIR. The code below
illustrates it. I keep getting the message: Error in y - f :
non-conformable arrays.
I tried to tweak the code below in many different ways, for example,
substituting rbind for cbind, and sometimes I get a different error
message, but I
Hello,
I´m looking for a way to measure the goodness of fit of my model with Cohen´s
Kappa (scaling between 0 and 1).
The kappa function does not give the results I´m looking for. Heres the code:
z-glm(x~y,binomial)
kappa(z, exact = T)
Does anyone know more?
many thanks
Christian
--
kappa(base) is used to Estimate the Condition Number,so it is NOT
what you want.
And several packages have function related to your question:
cohen.kappa(concord)kappa reliability coefficient for nominal data
kappa2(irr) Cohen's Kappa and weighted Kappa for two raters
Hi all.
I have a doubt with weighted linear regression. I've noted that supplying
integer weights gives different residuals df than giving 'double' weights.
Here an example:
x - 1:5
y - -1 + 2*x + rnorm(length(x))*0.1
y - c(y, x + rnorm(length(x))*0.1)
dat - data.frame(x=rep(x,2), y = y)
Hi,
likely it's not the most elegant way, but it's straight-forward and the
first which popped in my mind:
a - rnorm(100)
# either
boxplot(a, col=white, border=white)
my.grid - seq(-4, 4, 0.5)
abline(h=my.grid, col=grey, lty=2)
boxplot(a, col=red, add = TRUE)
# or
boxplot(a, col=white,
Simply add the same boxplot over your first graph using par(new=TRUE)
x -1:10
y -1:5
boxplot(x, y,col=blue)
grid(nx=NA, ny=NULL) #grid over boxplot
par(new=TRUE)
boxplot(x, y,col=blue)#grid behind boxplot
Neuro
From: Toby Popenfoose [EMAIL PROTECTED]
Reply-To: Toby Popenfoose [EMAIL
Marc == Marc Schwartz (via MN) [EMAIL PROTECTED]
on Fri, 28 Apr 2006 14:38:53 -0500 writes:
Marc Sachin, I don't have a definitive thought, but some
Marc possibilities might be a conflict somewhere in your
Marc environment with a local function or with one in the
Marc
Dear R experts here,
I am considering a new PC mainly to run R simulation. I will buy a
double core machine as I regularly run several R sessions at a time. I
am choosing between Core Duo and Athlon X2. I would like your input. I
also need to hook up R with a Fortran 90 subroutine of about 1000
On Sat, 2006-04-29 at 16:21 +0200, Martin Maechler wrote:
Marc == Marc Schwartz (via MN) [EMAIL PROTECTED]
on Fri, 28 Apr 2006 14:38:53 -0500 writes:
Marc Sachin, I don't have a definitive thought, but some
Marc possibilities might be a conflict somewhere in your
Marc
Dear Xuemei Bian,
This is, I guess, the box.tidwell() function in the car package.
To know exactly what happened, it would help to see the data, but I suspect
that you have negative values among the predictors. The log of a negative
number is not defined, producing NaN (which means not a
Hello!
I would like to use a classification tree as a species modelling method. The
dependent variable is binary (0,1),the independent variables are numeric. So I
have to surround the dependent variable with factor(). That tells tree() that I
want a logistic, or classification, tree rather
Hi,
i have a dataframe like this,
SourceTreatDrugReplicate
control0A1
control10A2
control30A3
10A1
And i want to rep this dataframe 3 times by row,the resulting matrix as
follow,
SourceTreatDrugReplicate
control
Try this where DF is your data frame:
DF[rep(seq(nrow(DF)), each = 3), ]
On 4/29/06, Jiantao Shi [EMAIL PROTECTED] wrote:
Hi,
i have a dataframe like this,
SourceTreatDrugReplicate
control0A1
control10A2
control30A3
10A1
Hello!
I would like to use a classification tree as a species modelling method. The
dependent variable is binary (0,1),the independent variables are numeric. So I
have to surround the dependent variable with factor(). That tells tree() that I
want a logistic, or classification, tree rather than
Hi,
I searched for this in the mailing list, but found no results.
I have a large dataframe ( dim(mydata)= 1297059 16, object.size(mydata=
145280576) ) , and I want to perform some calculations which can be done by
a factor's levels, say, mydata$myfactor. So what I want is to split this
Dear Roman,
I've attached the latex file for the copy-edited version of your manuscript
-- correcting English grammar and style, and making the paper conform more
closely to the R News style. Can you check this over to confirm that I've
not altered the meaning of your text and to approve the
I'm back!
I've just learned that, on a fully updated Fedora Core Linux5 sytem,
the working solution to access Winbugs under wine via the R package
rbugs no longer works. Here was my last post on this topic (with
the formerly working solution) from January.
Gabor Grothendieck ggrothendieck at gmail.com writes:
http://news.gmane.org/gmane.comp.lang.r.general
or one of these:
http://dir.gmane.org/gmane.comp.lang.r.general
Yes but when I hit Post this article it send something to gMane (I think)
but not to R-help@stat.math.ethz.ch
A while back Gabor Grothendieck suggested that I try
http://news.gmane.org/gmane.comp.lang.r.general. This was after I asked how
to easily reply to posts on the listserve. Ideally I would like the
functionality that I find in Microsoft Outlook Express newsreader for usenet
groups or what I find in
I agree that conflicts() belongs in the posting guide. I devoted
a small section in my book to that very topic. Here is the lead paragraph
which you are welcome to use
Inexplicable Error Messages
In general, weird and inexplicable errors mean that there are masked
function names. That's the
That did the job.
thanks,
akn
Suppose your data frames are A and B:
AB - merge(A, B, c(Doc, Query), all=TRUE)
AB[order(AB$Query, AB$Doc),]
gets the answer you are asking for. (Not sure why you want to sort it to
use a correlation test, as those are indifferent to ordering.)
On Sun, 23
You might want to check the double check the list archives
https://www.stat.math.ethz.ch/pipermail/r-help/
to see if your posts got through or not just in case its just
some problem in displaying your own posts.
On 4/29/06, Farrel Buchinsky [EMAIL PROTECTED] wrote:
Gabor Grothendieck
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