i have a data set with repeated measures on same people, structure like
below:
id x1 x2 ...
001 10 20 ...
001 8 45 ...
001 4 2 ...
002
002 ...
002
002
003
...
what is the easist way to show how many observations for each subject id?
[[alternative HTML version
gallon li wrote:
i have a data set with repeated measures on same people, structure like
below:
id x1 x2 ...
001 10 20 ...
001 8 45 ...
001 4 2 ...
002
002 ...
002
002
003
...
what is the easist way to show how many observations for each subject id?
If
actually there are too many subjects.
is there a way that i can make a table such that it can tell me the
frequency of number of observations?
Like
3 4 5
30 40 60
which means there are 30 subjects which each has 3 obs., 40 which each has 4
obs.
On 1/27/07, Chuck Cleland
Dear Lalitha,
On 1/26/07, lalitha viswanath [EMAIL PROTECTED] wrote:
Hi
I am looking for a package that
1. reads in a phylogenetic tree in NEXUS format
2. given two members/nodes on the tree, can return the
distance between the two using the tree.
I came across the following packages on
i have a large longitudinal data set. The number of observations for each
subject is not the same across the sample. The largest number of a subject
is 5 and the smallest number is 1.
now i want to make each subject to have the same number of observations by
filling zero, e.g., my original sample
gallon li wrote:
i have a large longitudinal data set. The number of observations for each
subject is not the same across the sample. The largest number of a subject
is 5 and the smallest number is 1.
now i want to make each subject to have the same number of observations by
filling zero,
merge.zoo in the zoo package has an n-way merge supporting zero fill:
library(zoo)
DF - data.frame(id = c(1, 1, 1, 2, 2, 2, 2, 2, 3, 3), x = c(10,
30, 20, 10, 20, 40, 80, 70, 20, 40))
as.data.frame(do.call(merge, c(lapply(unstack(DF, x ~ id), zoo), fill = 0)))
# last line can alternately be
f
Two questions:
1. How do I replace NA with 0?
2. How can I sort the observations by their id instead of by time? (actually
i can see what you produced is automatically sorted by id; but in my case,
the output data is sorted by time)
On 1/27/07, Chuck Cleland [EMAIL PROTECTED] wrote:
gallon li
gallon li wrote:
Two questions:
1. How do I replace NA with 0?
df.long2$x - replace(df.long2$x, is.na(df.long2$x), 0)
?replace
2. How can I sort the observations by their id instead of by time? (actually
i can see what you produced is automatically sorted by id; but in my case,
the
what if i want to order within each id by their time? is there such an
option? (right now some observation at time 100 were placed before 50 b/c R
treated 1 first)
On 1/27/07, Chuck Cleland [EMAIL PROTECTED] wrote:
gallon li wrote:
Two questions:
1. How do I replace NA with 0?
Hi,
I wrote a simple derivative program
(ftest=deriv(y~x^2, c(x), function(x){} ))
I put (ftest=deriv(y~x^2, c(x), function(x){} ))(1) which return 2
which is correct.
however, if I want the output to be 0 and hopefully a new inverse
function can take in output (2) and return x=1. Can this
configure: error: --with-readline=yes (default) and headers/libs are not
available
then i cannot make.
why?
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Eric schrieb:
library(R2HTML, verbose = FALSE)
Dear Eric,
thanks - I tried that, but that does not work for me. And it does not
depend whether R2HTML is loaded via script/ batch job (- webserver,
cgi) or directly within R.
The same happens (of course) by using
require(R2HTML, quietly=TRUE)
Inverting a linear function is easy, and more generally functions need not
be invertible. But uniroot() is very helpful in finding an inverse of a
monotonic function, and the idea is used in some of the qx functions.
On Fri, 26 Jan 2007, [EMAIL PROTECTED] wrote:
Hi,
I wrote a simple
This is done by .onLoad, so your settings are irrelevant.
We have no information here on your platform, version of R, R2HTML or
anything else. But almost certainly the problem is the command given by
getOption(unzip), which looks like an unzip clone not respecting the -q
flag.
Try using the
On 1/27/07, gallon li [EMAIL PROTECTED] wrote:
actually there are too many subjects.
is there a way that i can make a table such that it can tell me the
frequency of number of observations?
Like
3 4 5
30 40 60
which means there are 30 subjects which each has 3 obs., 40
Dear r-helpers,
I am looking at a designed experiment in which one predictor variable
has 5 levels (0, ..., 4) and the other has 6 levels (1.1, ..., 1.6),
with 33 observations per cell. This design was given to 13 subjects.
0 1 2 3 4
1.1 32 33 0 0 0
1.2 33 33 33 0 0
I want to plot variation of more than one variable in
single plot with different point types and points
sizes . Can someone help me to do that,
Thanks in advance.
vinod
Now that's room service! Choose from
try:
plot(1:10,pch=1:10,cex=1:10)
pch specifies the types and cex specifies the sizes of symbols.
On 1/28/07, vinod gullu [EMAIL PROTECTED] wrote:
I want to plot variation of more than one variable in
single plot with different point types and points
sizes . Can someone help me to do that,
try this
x1 - rnorm(10); y1 - rnorm(10)
x2 - rnorm(10); y2 - rnorm(10)
x3 - rnorm(10); y3 - rnorm(10)
#
plot(range(x1, x2, x3), range(y1, y2, y3), type = n)
points(x1, y1, pch = 1, cex = 1, col = 1)
points(x2, y2, pch = 2, cex = 2, col = 2)
points(x3, y3, pch = 3, cex = 3, col =
Dear Wizards -
Thank you so much for your help. That was exactly what I was looking
for. Now, I have been working on conditional selection of columns in a
data frame. My goal is to calculate the total revenue per sales
representative per status in a table. I have come to a complete
Try these:
aggregate(DF[4], DF[c(3,5)], sum)
xtabs(revenue ~ status + name, DF)
library(doBy)
summaryBy(revenue ~ status + name, data = DF, FUN = sum)
On 1/27/07, Mark Hempelmann [EMAIL PROTECTED] wrote:
Dear Wizards -
Thank you so much for your help. That was exactly what I was
Dear R Users,
I am trying to users gsub to remove multiple cases of square brackets and their
different contents in a character string. A sample of such a string is shown
below. However, I am having great difficulty understanding regexp syntax. Any
help is greatly appreciated.
Ally
tree
Prof Brian Ripley schrieb:
Dear Prof Ripley,
thanks for your information, in my first email I mentioned that I use
Version 2.3.1 (2006-06-01) on ubuntu edgy. Sorry for leaving out the
version-no. 1.1.2.3-13ubuntu2, together with R2HTML 1.58, installed
directly from R via 'install.packages()'.
On Jan 27, 2007, at 3:41 PM, Phillimore, Albert wrote:
Dear R Users,
I am trying to users gsub to remove multiple cases of square
brackets and their different contents in a character string. A
sample of such a string is shown below. However, I am having great
difficulty understanding
I would not try uninstalling anything. The binary used is set via
getOption(unzip), and that in turn is set at R configure time and
recorded in R_HOME/etc/Renviron. I have
R_UNZIPCMD=${R_UNZIPCMD-'/usr/bin/unzip'}
there. So you can alter that or set the environment variable in some
other
On 27 January 2007 at 22:12, Leo Gürtler wrote:
| Prof Brian Ripley schrieb:
|
| Dear Prof Ripley,
|
| thanks for your information, in my first email I mentioned that I use
| Version 2.3.1 (2006-06-01) on ubuntu edgy. Sorry for leaving out the
| version-no. 1.1.2.3-13ubuntu2, together with
Hi Martin,
Thanks for your detailed answer.
x - Matrix(1:12, 3,4, sparse = TRUE)
I hope that you are aware of the fact that it's not efficient at
all to store a dense matrix (it has *no* 0 entry) as a sparse one..
and your posting is indeed an incentive for the Matrix developers
to improve that
I am using xYplot to plot data and CIs. How do I add several lines to
the figure?
_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
I am running R2.4.1 under Windows.
version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major 2
minor 4.1
year 2006
month 12
day18
svn rev40228
language
Dear All,
I am a beginner in learning the package of Biostrings currently and for
practice doing an example.
library(Biostrings);
dnaAlph-new(BioPatternAlphabet,DNAAlphabet(),c(N=AGCT,
+ B=CGT,D=AGT,H=ACT,K=GT,M=AC,R=AG,S=CG,
+ V=ACG,W=AT,Y=CT));
Error in getClass(Class, where =
Am 27 Jan 2007 um 20:13 hat Michael Kubovy geschrieben:
To: r-help@stat.math.ethz.ch list r-
[EMAIL PROTECTED]
From: Michael Kubovy [EMAIL PROTECTED]
Date sent: Sat, 27 Jan 2007 20:13:15 -0500
Subject:[R] Adding lines to xYplot
Hi, All
I have a function
f(y) = (x'Ax + 2yx'a_i+y^2*a_ii)/(x'Bx + 2yx'b_i+y^2*b_ii),
where A and B are known square matrix, a_i are the ith row of matrix A,
a_ii are the ith row/column element of matrix A.
what can I do to find a y to minize/maximize the ratio?
Do optimize function? can I do
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