Hi,
I am simply asking about coefficient od determination(R square), is its
value more than 1 also posiible.
Because it ranges from 0-1. So I want to know that R squre may be more
than one. If yes what is its interpretation.
Thanking to all of You(R help group).
--
Nitish Kumar Mishra
Junior
Hi,
I am simply asking about coefficient od determination(R square), is its
value more than 1 also posiible.
Because it ranges from 0-1. So I want to know that R squre may be more
than one. If yes what is its interpretation.
Thanking to all of You(R help group).
--
Nitish Kumar Mishra
Junior
Hi,
I am simply asking about coefficient od determination(R square), is its
value more than 1 also posiible.
Because it ranges from 0-1. So I want to know that R squre may be more
than one. If yes what is its interpretation.
Thanking to all of You(R help group).
--
Nitish Kumar Mishra
Junior
Dear Help Desk,
Is there any way to change some of the labels on R diagrams?
Specifically in histograms, I would like to:
1. change the word frequency to count.
2. Make the font of the title (Histogram of
) smaller.
3. Have a different
Dear useRs,
I am pretty sure the answer to my question is out there if I would just
take the time to cross-correlate information that's scattered among
different email exchanges, useR! presentations, Paul Murrel's website
and assorted posters, but would some charitable soul be so kind as to
Hello,
I have an elementary question (for which I couldn't find the answer on the
web or the help): how can I extract the mode (modal score) of a vector?
Thanks in advance for your help.
[[alternative HTML version deleted]]
__
Bonjours monsieurs
Je suis un étudient en 4eme année informatique a luniversite djilali liabes
SBA ALGERIE.
Je suis entrain de préparer un exposé sur lAFD et jai besoin dun exemple
sous R pour bien présenter mon travail.
__
Ey!
Tienes q echarle un ojo a mi nuevo vicio en internet...estoy tan
seguro de q te va a gustar q te he registrado...sólo falta tu
confirmación! ya me cuentas! ;)
http://eu1.badoo.com/01738976/in/82997
Esta invitación ha sido enviada con fecha 22/04/07 16:09 a
r-help@stat.math.ethz.ch; a
First of all, this is not a Help Desk.
Second, please make sure that you put an informative subject line: I thought
this was spam and was going to delete it.
Thanks,
Ranjan
On Sat, 21 Apr 2007 12:03:24 -0700 (PDT) Nima Tehrani [EMAIL PROTECTED] wrote:
Dear Help Desk,
Is there any
Hi
Can anyone help me? I am not an experienced R user (or statistician!). If I
use rmultinom to generate random outcomes of a multinomial distribution, how
do i use these in a way to help conduct an exact chi-squared test?
woozles48
--
View this message in context:
I am trying to cluster some binary data using k-means . As the regular kmeans
available from stats package in R does'nt provide the option to change the
distance method. I was wondering there is any package available to specify type
of distance measure to be used in k means clustering in R.
Chandra
You could try clustan graphics, cheap and awesome with plenty of
preprocessing capabilities of matrices.
Given this is one of R's strengths (matrix programming) I would imagine
there is code out there that would enable you to generate a matrix for use
in k-means.
Typically, what I
Hi all,
a problem I encounter again and again: I plot a zoo object using plot
and then want to add lines or points to this plot.
I usually circumvent this problem by adding artificial coloumns to the
zoo object before plotting, but I am sure there's a better solution.
To be specific: Assume I
You need to use the panel= argument. There are examples in ?plot.zoo
For your example its like this (make sure you are using the latest version
of zoo, 1.3-0, for this):
x - as.Date(c(2002-01-01,2003-01-01,2004-01-01))
y.zoo - zoo(cbind(y1 = c(1,2,3),y2=c(3,4,3)),order.by=x)
pnl - function(x,
On Sat, 2007-04-21 at 12:03 -0700, Nima Tehrani wrote:
Dear Help Desk,
Is there any way to change some of the labels on R diagrams?
Specifically in histograms, I would like to:
1. change the word frequency to count.
2. Make the font of the
Hi,
Is anyone able to give me references or explain how the decision
boundary is calculated by the LDA function in MASS. e.g. p 335-336 of
MASS 4th Ed. Since it's curved I'm assuming they're doing something like
fitting 2-D Gaussians to the groups and plotting the contour line
describing the
Hello, I would like to add to axis labels special caracters. Instead of writing
:plot(simul, xlab=beta, ylab=sigma11) It would be great if I could write
something as in LaTeX :plot(simul, xlab=\beta, ylab=\sigma_{11}) Is there a
way to do that ? Thank you
Hi, try this:
plot(simul, ylab=expression(beta), xlab=expression(sigma))
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22
Ohttp://maps.google.com/maps?f=qhl=enq=Curitiba,+Brazillayer=ie=UTF8z=18ll=-25.448315,-49.276916spn=0.002054,0.005407t=kom=1
On 4/22/07, [EMAIL
hist(rnorm(100),xlab=Data,ylab=Count,main=)
title(main=Histogram of ...,cex=0.5)
see ?par for details on xlab, ylab, main, and cex arguments.
You can call these from title() or include them in hist().
I called title(main=..) separately to control its size separately
from the rest of the text
I read the reply earlier in which Nima was naughty-naughty'd for calling
us a Help Desk. And, I have to admit that I agree.
But then, an open-source listserv is, in essence, a help deskwell, maybe
not a desk, but we do help each other. My conflicting feelings about this
are better left for a
Hello r-help!
My name is Dan McGoldrick, I am a statistical geneticist and I work with
ontologies, AI and general genetic data analysis.
I was wondering aabout the tryCatch function -- don't really understand the
implimentation...
What I would like to do is within an R API, test a mysql
On Fri, 20-Apr-2007 at 11:10PM -0500, Jeffrey Horner wrote:
| workdir - '/tmp/data'
| for (x in dir(workdir,pattern='.csv$')){
|d - read.table(paste(workdir,'/',x,sep=''), sep=\t, header=TRUE)
If they're CSV files, I don't think sep = \t will be correct. Try ,
best
--
My apologies. Second line should be
title(main=Histogram of ...,cex.main=0.5)
Actually I just realized you can also do
hist(rnorm(100),xlab=Data,ylab=Count,cex.main=0.5)
...this way you don't have to call title() separately.
--- Stephen Tucker [EMAIL PROTECTED] wrote:
dear R wizards --- would it make sense for names(d$columnname) to be
columnname? I can preserve the columnname through x=subset(dataset,
select=columnname), of course, but it would seem that x=d$columnname
could also do this. No? Sincerely, /iaw
__
On 4/22/2007 5:46 PM, ivo welch wrote:
dear R wizards --- would it make sense for names(d$columnname) to be
columnname? I can preserve the columnname through x=subset(dataset,
select=columnname), of course, but it would seem that x=d$columnname
could also do this. No? Sincerely, /iaw
If
Hi,
I am trying to print out my confusion matrix after having created my random
forest.
I have put in this command:
fit-randomForest(MMS_ENABLED_HANDSET~.,data=dat,ntree=500,mtry=14,
na.action=na.omit,confusion=TRUE)
but I can't get it to give me the confusion matrix, anyone know how this
works?
yes, this was what I was asking for. I had the notion that one could
tag almost anything with a name, and did not appreciate the scope for
confusion. thank you for the explanation. regards, /ivo
On 4/22/07, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 4/22/2007 5:46 PM, ivo welch wrote:
dear
Hi R-experts,
I have a large set of weekly data in this format:
2007-01-05 -1.52377151
2007-01-12 1.04787390
2007-01-19 0.61647047
2007-01-26 1.87864283
2007-02-02 0.54992405
2007-02-09 1.96850069
2007-02-16 0.26850159
2007-02-23 1.56305144
2007-03-02 -4.19500573
2007-03-09
On Sun, 22 Apr 2007, ivo welch wrote:
yes, this was what I was asking for. I had the notion that one could
tag almost anything with a name, and did not appreciate the scope for
confusion. thank you for the explanation. regards, /ivo
You haven't told us why you want this behavior.
If what
Hi All,
Here 's what I got using dgamma function :
nu-.2
nu*log(nu)-log(gamma(nu))+(nu-1)*log(1)-nu*(1)
[1] -2.045951
dgamma(1,nu,nu,1)
[1] 0.0801333
dgamma(1,nu,nu,0)
[1] NaN
Warning message:
NaNs produced in: dgamma(x, shape, scale, log)
Could anyone tell me what is wrong here ?
I am trying to maximise a complicated loglikelihood function with the optim
command. Is there some way to get to know the estiamtes at each iteration? When
I put control=list(trace=TRUE) as an option in optim, I just got the
initial and final values of the loglikelihood, number of iterations
Do you mean you want to return the first row for each mont for
which the value 0?
In that case try this. The first group of lines recreates your
data frame and calls it DF. by causes f to operate on a subset of
rows comprising one month extracting the first row for which
the value is positive
dgamma(x=1, shape=nu, rate=nu, log=TRUE)
[1] -2.045951
This is a good example of why you should call parameters by name.
Ted.
Tong Wang wrote on 04/23/2007 01:59 PM:
Hi All,
Here 's what I got using dgamma function :
nu-.2
nu*log(nu)-log(gamma(nu))+(nu-1)*log(1)-nu*(1)
Jeff's code works beautifully with a couple changes to my dataset. I must
change my data column MB/s to MBs. R seems to think that the s is another
column if I try to use MB/s. Is there a way that I can make R allow special
characters in the column names?
The second step to getting this to
Rubin,
just type fit or print(fit). confusion = TRUE will not be recognized by
randomForest.
If you are not seeing the confusion matrix, MMS_ENABLED_HANDSET is not a
factor and, thus, a regression fit is being done, not classification as you
apparently desire.
On 4/22/07, Ruben Feldman [EMAIL
Dear List,
I want to let R calculate the time (run-time) it
requires to run a self-written simulation function. I
tried as follows: it
enables me to see the starting and finishing time
points.
#
sim.result - function(nsim, ...){
Starting - date()
... #
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