Hi all,
I have managed to get the r-scale usage algorithm to work, but I need to obtain
the final results from this. As I understand it, this code is designed to
generate a matrix after processing and store it somewhere?
Here is the code.
I get this part of the code, it all makes
Hello R Users,
How to convert decimal date to date as .mm.dd.hr.min.sec
For example, I have decimal date in one column , and want to convert and
write it in equivalent date(.mm.dd.hr.min.sec) in another next six
columns.
1979.00
1979.020833
1979.041667
1979.062500
Is it
Shao wrote:
Hi,everyone.
I have a problem when using the grep.
for example:
a - c(aa,aba,abac)
b- c(ab,aba)
I want to match the whole word,so
grep(^aba$,a)
it returns 2
but when I used it a more useful way:
grep(^b[2]$,a),
it doesn't work at all, it can't find it, returning
On 07-Aug-07 04:20:27, Shao wrote:
Hi,everyone.
I have a problem when using the grep.
for example:
a - c(aa,aba,abac)
b- c(ab,aba)
I want to match the whole word,so
grep(^aba$,a)
it returns 2
but when I used it a more useful way:
grep(^b[2]$,a),
it doesn't work at all, it can't
paulandpen at optusnet.com.au writes:
I get this part of the code, it all makes sense.
##
if(nchar(Sys.getenv(LONG_TEST)) != 0) {R=1000} else {R=5}
{
data(customerSat)
surveydat = list(k=10,x=as.matrix(customerSat))
Mcmc1 = list(R=R)
set.seed(66)
Hello,
I want to plot a time series and add lines to the plot later on.
However, this seems to work only as long as I plot the series against
the default index. As soon as I plot against an object
of class chron or POSIXt (i.e. I want to add a date/time axis), the
lines do not appear anymore.
Hello!
I am using glmmML for a logitic regression with random effect.
I use the posterior.mode as an estimate for the random effects.
These can be very different from the estimates obtained using SAS , NLMIXED
in the random with out= option. (all the fixed and standard error of random
effect
On Tue, 7 Aug 2007, Zeno Adams wrote:
Hello,
I want to plot a time series and add lines to the plot later on.
However, this seems to work only as long as I plot the series against
the default index. As soon as I plot against an object
of class chron or POSIXt (i.e. I want to add a
Does ?Rscript help?
Christopher Green [EMAIL PROTECTED] 06/08/2007 23:13:47
On Fri, 3 Aug 2007, Duncan Murdoch wrote:
On 03/08/2007 7:16 PM, Christopher Green wrote:
Is there an easy way to open an R script file in the R Editor found in
more recent versions of R on Windows via a file
Hi
Im pretty new to R and I have run in to a problem. How do I name all the
levels in this list.
Lev1 - c(A1,A2)
Lev2 - c(B1,B2)
Lev3 - c(C1,C2)
MyList - lapply(TEST1,function(x){
assign(x,x,where=1)
lapply(TEST2,function(y){
assign(y,y,where=1)
lapply(TEST3,function(z){
On Tue, 7 Aug 2007, Zeno Adams wrote:
Hello,
I want to plot a time series and add lines to the plot later on.
However, this seems to work only as long as I plot the series against
the default index. As soon as I plot against an object
of class chron or POSIXt (i.e. I want to add a
Dear experts,
I have in all 14 matrices which stands for gene expression divergence and 14
matrices which stands for gene sequence divergence. I have tried joining them
by using the concatanation function giving
SequenceDivergence - c(X1,X2,X3,X4,X5,X6,X7,X8,X9,X10,X11,X12,X13,X14)
On Wed, 1 Aug 2007, Upasna Sharma [EMAIL PROTECTED] wrote:
From: Upasna Sharma [EMAIL PROTECTED]
Subject: [R] Goodman Kruskal's tau
I need to know which package in R calculates the Goodman Kruskal's
tau statistic for nominal data. Also is there any implementation for
multiple classification
R-help,
I'm trying to work out the density function by doing:
df(5.22245, 3, 22)
[1] 0.005896862
df(15.20675, 6, 4)
[1] 0.001223825
In excell the result is :
0.0071060464 * FDIST(5.22245,3,22)
0.011406 -- FDIST(15.20675,6,4)
From my point of view the differences in the second
Hi,
With your help I've found out that library(GRASS) is the responsible for
several warnings I'm obtaining.
I've got a loop (~100 runs) and for every loop, I'm carrying out several
operations over a sequence of raster maps (12) read from the GRASS GIS.
But for every map and loop I always use
Hello,
I am trying to explore a classification with GGobi. I am trying to
generate additional data according to the model so I can draw the
decision boundaries on the GGobi plot. The problem is that I always get
the same error: Error in predict.lda(model,data): wrong number of
variables, even if I
I think you'll have to compare FDIST to pf() and not df()
Best regards
Frede Aakmann Tøgersen
Scientist
UNIVERSITY OF AARHUS
Faculty of Agricultural Sciences
Dept. of Genetics and Biotechnology
Blichers Allé 20, P.O. BOX 50
DK-8830 Tjele
Phone: +45 8999 1900
Direct: +45 8999 1878
On 07-Aug-07 10:27:06, Luis Ridao Cruz wrote:
R-help,
I'm trying to work out the density function by doing:
df(5.22245, 3, 22)
[1] 0.005896862
df(15.20675, 6, 4)
[1] 0.001223825
In excell the result is :
0.0071060464 * FDIST(5.22245,3,22)
0.011406 --
Hi
I have fitted a linear mixed model using the lme function but now wish to
calculate robust standard errors for my model. I have been able to find
several functions which calculate robust s.e for lm objects but have not been
able to find a function which calcualtes robust s.e for lme objects.
Hello everybody,
I've a question about autoregressive Regressionmodels.
Let Y[1],.,Y[n], be a time series.
Given the model:
Y[t] = phi[1]*Y[t-1] + phi[2]*Y[t-1] + ... + phi[p]*Y[t-p] + x_t^T*beta + u_t,
where x_t=(x[1t],x[2t],x[mt]) and beta=(beta[1],...,beta[m]) and u_t~(0,1)
I
Have you tried using classifly directly?
library(classifly)
classifly(Tumor ~ ., my.data.set, lda)
generate_classification_data is an internal function, and you are
passing it the wrong arguments.
Hadley
On 8/7/07, Dani Valverde [EMAIL PROTECTED] wrote:
Hello,
I am trying to explore a
arima (see ?arima) supports explanatory variables in the xreg= argument.
On 8/7/07, Maja Schröter [EMAIL PROTECTED] wrote:
Hello everybody,
I've a question about autoregressive Regressionmodels.
Let Y[1],.,Y[n], be a time series.
Given the model:
Y[t] = phi[1]*Y[t-1] + phi[2]*Y[t-1]
Hi R-users,
What is the best way to achieve a table which contains all days and months
between years 2007-2020? I would like to calculate number of days in each
month within those years (to data frame).
Regards,
Lauri
[[alternative HTML version deleted]]
Hi,
I have a batch routine that does PCA on a series of files and saves the results
as a csv file, and the respective graphs as pdf and jpg. While pdf's are fine,
jpg files have a light grey background does not matter what color i set the bg
param. I am running this on a PC with 4 GB RAM -
Stripping either or both ends can be achieved by the somewhat tortuous but
fairly general
stripspace-function(x) sub(^\\s*([^ ]*.*[^ ])\\s*$, \\1,x)
which uses a replacement buffer to keep the useful part of the string.
Prof Brian Ripley [EMAIL PROTECTED] 06/08/2007 21:23:49
I am sure Marc
On Tue, Aug 07, 2007 at 03:53:28PM +0300, Lauri Nikkinen wrote:
What is the best way to achieve a table which contains all days and months
between years 2007-2020? I would like to calculate number of days in each
month within those years (to data frame).
Here you go -- just replace
diff(seq(as.Date(2007-01-01), as.Date(2021-01-01), by = month))
Time differences in days
[1] 31 28 31 30 31 30 31 31 30 31 30 31 31 29 31 30 31 30 31 31 30 31 30 31 31
[26] 28 31 30 31 30 31 31 30 31 30 31 31 28 31 30 31 30 31 31 30 31 30 31 31 28
[51] 31 30 31 30 31 31 30 31 30 31 31 29 31
Just one refinement if you want it nicely formatted:
ts(diff(seq(as.Date(2007-01-01), as.Date(2021-01-01), by = month)),
start = c(2007, 01), freq = 12)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
2007 31 28 31 30 31 30 31 31 30 31 30 31
2008 31 29 31 30 31 30 31
Lauri Nikkinen wrote:
Hi R-users,
What is the best way to achieve a table which contains all days and months
between years 2007-2020? I would like to calculate number of days in each
month within those years (to data frame).
Regards,
Lauri
How about this?
X - seq(ISOdate(2007,1,1),
Dear experts,
I have in all 14 matrices which stands for gene expression divergence and 14
matrices which stands for gene sequence divergence. I have tried joining them
by using the concatanation function giving
SequenceDivergence - c(X1,X2,X3,X4,X5,X6,X7,X8,X9,X10,X11,X12,X13,X14)
Dear fellow R-ussers,
Thanks for your help on th AIC.
I have yet an other question about logistic models. to buuild the model i
used sevral packages, (MASS, nlme, binom), just to make sure i had all the
tools at my disposal. now i would like to validat the model. ussing a
cross validation tool.
Lucy:
Why are you interested in robust standard errors from lme? Typically,
robust standard errors are sought when there is model misspecification
due to ignoring some covariance among units with a group.
But, a mixed model is designed to directly account for covariances among
units within a
On Tue, 7 Aug 2007, Gabor Grothendieck wrote:
arima (see ?arima) supports explanatory variables in the xreg= argument.
In addition to arima(), the function dynlm() in package dynlm might be
useful if you want to fit the model by OLS. See also package dyn for a
similar approach.
Z
On 8/7/07,
Hello,
I have been fitting nonlinear models with random effects using nlme with the
corCAR1 correlation structure, as I have unequally spaced observations per
subject, and serially correlated errors. My question is regarding the Phi
parameter.
Example of output:
Correlation Structure:
Seth and Stephen,
Thanks a lot for the explanation and help! I really appreciate it.
Gang
On Aug 6, 2007, at 6:41 PM, Stephen Tucker wrote:
That's because tag - 1 is evaluated in a local environment (of the
function)
- once function(err) exits, the information is lost. Try R's -
I'm trying to run a contrast with lme, but could not get it work:
anova(lme(Beta ~ Trust*Sex*Freq, random = ~1|Subj, Model), L=c
(TrustT:Sex:Freq=1, TrustU:Sex:Freq=-1))
Error in anova.lme(lme(Beta ~ Trust * Sex * Freq, random = ~1 | Subj, :
Effects TrustT:Sex:Freq, TrustU:Sex:Freq
Dear list members,
I have problems to interpret the coefficients from a lm model involving
the interaction of a numeric and factor variable compared to separate lm
models for each level of the factor variable.
## data:
y1 - rnorm(20) + 6.8
y2 - rnorm(20) + (1:20*1.7 + 1)
y3 - rnorm(20) +
On Tue, 7 Aug 2007, Doran, Harold wrote:
Lucy:
Why are you interested in robust standard errors from lme? Typically,
robust standard errors are sought when there is model misspecification
due to ignoring some covariance among units with a group.
But, a mixed model is designed to directly
Simple question how can you position text in the top left hand corner of
a plot? I am plotting multiple plots using par(mfrow=c(2,3)) and all I
want to do is label these plots a), b), c) etc. I have been fiddling
around with both text and mtext but without much luck. text is fine but
each plot
I have a question about how to save the output of a logistic regression
model in some format (delimited, preferably) so that I can manipulate it
to make nice tables in excel. I have tried print, save, write, none seem
to do what I want them to. Does anyone have any ideas?
Lynn D. Disney,
You can call par('usr') to find the current coordinates, then use the
text function (the pos and offset arguments may be helpful as well)
The cnvrt.coords function from the TeachingDemos package may also be of
help for finding coordinates for the text function.
Hope this helps,
--
Gregory
In the single model all three levels share the same intercept which
means that the slope must change to accomodate it
whereas in the three separate models they each have their own
intercept.
Try looking at it graphically and note how the black dotted lines
are all forced to go through the same
It's not so straightforward with the manipulation, but if you're familiar
with LaTeX, I'd recommend the xtable package. It makes very readable
regression summaries.
Kyle H. Ambert
Department of Behavioral Neuroscience
Oregon Health Science University
On 8/7/07, Lynn Disney [EMAIL
Hello,
I have some files generated from microarray experiments. I used scan() to
read the files, and assigned each file to a unique name with many rows and
columns. Now I want to create a array (ArrayA) with unique names, and I can
use ArrayA[1,2][[6]] to refer the data in each file. Is there any
See ?sink
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 07/08/07, Lynn Disney [EMAIL PROTECTED] wrote:
I have a question about how to save the output of a logistic regression
model in some format (delimited, preferably) so that I can manipulate it
to make nice
maybe this is what you want?
plot(rnorm(10))
legend(topleft, A), bty=n)
?
b
On Aug 7, 2007, at 11:08 AM, Daniel Brewer wrote:
Simple question how can you position text in the top left hand
corner of
a plot? I am plotting multiple plots using par(mfrow=c(2,3)) and
all I
want to do is
-Original Message-
From: Thomas Lumley [mailto:[EMAIL PROTECTED]
Sent: Tuesday, August 07, 2007 11:06 AM
To: Doran, Harold
Cc: Lucy Radford; r-help@stat.math.ethz.ch
Subject: Re: [R] Robust Standard Errors for lme object
On Tue, 7 Aug 2007, Doran, Harold wrote:
Lucy:
Why
On 07-Aug-07 15:34:13, Gabor Grothendieck wrote:
In the single model all three levels share the same intercept which
means that the slope must change to accomodate it
whereas in the three separate models they each have their own
intercept.
I think this arose because of the formulation of the
Also check this post
https://stat.ethz.ch/pipermail/r-help/2007-May/132866.html
for a number of formulations.
On 8/7/07, Ted Harding [EMAIL PROTECTED] wrote:
On 07-Aug-07 15:34:13, Gabor Grothendieck wrote:
In the single model all three levels share the same intercept which
means that the
These are not the same model. You want x*f, and then you will find
the differences in intercepts and slopes from group 1 as the coefficients.
Remember too that the combined model pools error variances and the
separate model has separate error variance for each group.
To understand model
On Tue, 7 Aug 2007, Tom.O wrote:
Hi
Im pretty new to R and I have run in to a problem. How do I name all the
levels in this list.
One way:
MyList -
mapply(function(x) mapply(
function(y) mapply( function(z)
Hello SK,
I suggest you try the RandomFields package. It has specific functions
for simulating random fields with an array of different algorithms and
distributions. The GaussRF function in particular normal generates
random fields.
Julian
Julian M. Burgos
Fisheries Acoustics Research Lab
Dear All,
I am new to R. I need to read XLs files, parse the data
and convert them into txt format for further calculation . If any one
have code for that , please send me code or suggestions for the
same.Waiting for reply.
Thanking you
Animesh
[[alternative HTML
Hi,
I am trying to install RMySql-.0.6.0 to work with WinXP, MySQL 5 and R 2.51.
there is no binary for windows on cran-r, so i grabbed RMySql-0.6.0.tar.gz and
tried to compile it.
I get the following error:
* checking for file 'RMySQL/DESCRIPTION' ... OK
* preparing 'RMySQL':
* checking
Actually there is an RMYSQL windows binary in the CRAN Extras area but
it crashes on my XP machine when I try to use it. I have had more luck with
the Windows binary in the Bioconductor Extras area (which seems to work except
for some warnings that you can ignore):
Dear help-list,
I would like to perform a linear regression on the log10 of the two
vectors ov.mag.min and res.600nm. The slope and intercept of the
regression I use to plot a wider range of ov.mag.min in a double log plot.
For a linear regression on only tow points, wouldn't I expect the
Hello,
I am new to R. I used scan() to read data from tab-delimited files. I want
to save all my data files (multiple scan()) in another file, and use it
like infile statement in SAS or \input{tex.file} in latex.
Thanks!
__
R-help@stat.math.ethz.ch
How do I include bar values in a barplot (or other R graphics, where this
could be applicable)?
To make sure I am clear I am attaching a barplot created with OpenOffice.org
which has barplot values written on top of each barplot.
--
Donatas Glodenis
http://dg.lapas.info
Donatas G. wrote:
How do I include bar values in a barplot (or other R graphics, where this
could be applicable)?
To make sure I am clear I am attaching a barplot created with OpenOffice.org
which has barplot values written on top of each barplot.
This causes an optical illusion in
Dear all,
I want to estimate a crossed-random-effects model (i.e., measurements,
students, schools) where students migrate between schools over time.
I'm interested in the fixed effects of SES, age and their
interaction on read (reading achievement) while accounting for the
sample design. Based
If my sample size is small is there a particular switch option that I need to
use with t.test so that it calculates the t ratio correctly?
Here is a dummy example?
á =0.05
Mean pain reduction for A =27; B =31 and SD are SDA=9 SDB=12
drgA.p-rnorm(5,27,9);
drgB.p-rnorm(5,31,12)
On 8/7/2007 2:58 PM, Kim Milferstedt wrote:
Dear help-list,
I would like to perform a linear regression on the log10 of the two
vectors ov.mag.min and res.600nm. The slope and intercept of the
regression I use to plot a wider range of ov.mag.min in a double log plot.
For a linear
Hi,
Tiandao Li wrote:
Hello,
I have some files generated from microarray experiments. I used scan() to
read the files, and assigned each file to a unique name with many rows and
columns. Now I want to create a array (ArrayA) with unique names, and I can
use ArrayA[1,2][[6]] to refer the
Hello, my objective is to produce a data.frame that represents a grid of data
points evenly spaced as closely together as possible on a graph with domain and
range both being [0,1]. I tried to get a smaller example working first and I
tried the following code:
sink(file=Rsampledata)
a-0
Try:
data - expand.grid( a= seq(0,1,.1), b= seq(0,1,.1) )
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of esh
How do I get output with \color{blue}, i.e. with
only one backslash???
\color{blue}
[1] color{blue}
Warning messages:
1: '\c' is an unrecognized escape in a character
string
2: unrecognized escape removed from \color{blue}
\\color{blue}
[1] \\color{blue}
Any help greatly appreciated.
Perhaps:
cat(\\color{blue}\n)
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 07/08/07, Mikkel Grum [EMAIL PROTECTED] wrote:
How do I get output with \color{blue}, i.e. with
only one backslash???
\color{blue}
[1] color{blue}
Warning messages:
1: '\c' is an
Mikkel,
As
RSiteSearch(backslash)
would have shown you, this is a FAQ.
Your second attempt is correct.
To understand why, see the R FAQ
7.37 Why does backslash behave strangely inside strings?
Chuck
On Tue, 7 Aug 2007, Mikkel Grum wrote:
How do I get output with
On Tuesday 07 August 2007 22:09:52 Donatas G. wrote:
How do I include bar values in a barplot (or other R graphics, where this
could be applicable)?
To make sure I am clear I am attaching a barplot created with
OpenOffice.org which has barplot values written on top of each barplot.
Here is
See:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/56852.html
On 8/7/07, Donatas G. [EMAIL PROTECTED] wrote:
On Tuesday 07 August 2007 22:09:52 Donatas G. wrote:
How do I include bar values in a barplot (or other R graphics, where this
could be applicable)?
To make sure I am clear I
Hello,
I have 30 GenePix tab-delimited files generated from 10 microarray
experiments, each has 3 replicates. I used scan() to read the files, and
assigned each file to a unique name (such as A1, A2, A3 for experment A,
and B1, B2, and B3 for experiment B) with 1000 rows and 56 columns.
Now I
Generally adding the numbers to a graph accomplishes 2 things:
1) it acts as an admission that your graph is a failure
2) it converts the graph into a poorly laid out table (with a colorful
and distracting background)
In general it is better to find an appropriate graph that does convey
the
On Tuesday 07 August 2007 22:09:52 Donatas G. wrote:
How do I include bar values in a barplot (or other R graphics, where this
could be applicable)?
To make sure I am clear I am attaching a barplot created with
OpenOffice.org which has barplot values written on top of each barplot.
After
Dear all,
I want to estimate a crossed-random-effects model (i.e., measurements,
students, schools) where students migrate between schools over time.
I'm interested in the fixed effects of SES, age and their
interaction on read (reading achievement) while accounting for the
sample design. Based
On 8/7/07, Daniel Caro [EMAIL PROTECTED] wrote:
Dear all,
I want to estimate a crossed-random-effects model (i.e., measurements,
students, schools) where students migrate between schools over time.
I'm interested in the fixed effects of SES, age and their
interaction on read (reading
I wasn't aware of this literature, thanks for the references.
On 8/5/07, RAVI VARADHAN [EMAIL PROTECTED] wrote:
Another possibility is to use data squashing methods. Relevant papers are:
(1) DuMouchel et al. (1999), (2) Madigan et al. (2002), and (3) Owen (1999).
Ravi.
Hello all,
I consider myself pretty new to the whole OO based programming so
I'm sorry if I'm doing something stupid.
xml-read.metlin(url)
Error in function (classes, fdef, mtable) :
unable to find an inherited method for function read.metlin,
for signature url
read.metlin
Why would anyone want to fit a mixture of normals with 110 million
observations?? Any questions about the distribution that you would care to
ask can be answered directly from the data. Of course, any test of normality
(or anything else) would be rejected.
More to the point, the data are
Have you considered the situation of wanting to characterize
probability densities of prevalence estimates based on a complex
random sample of some large population.
On 8/7/07, Bert Gunter [EMAIL PROTECTED] wrote:
Why would anyone want to fit a mixture of normals with 110 million
observations??
Have you considered the situation of wanting to characterize
probability densities of prevalence estimates based on a complex
random sample of some large population.
No -- and I stand by my statement. The empirical distribution of the data
themselves are the best characterization of the
Hi All
I dont know if anyone else has noticed the same thing, but with 2 subsequent
runs of the same syntax, I am getting exactly the same results. I was expecting
that results differ slighlty, say in the 4th or 5th decimal place.
Is this a specialty with R2WinBUGS? Does it have something to do
Hello-
Upon searching the email archives and reading documentation I haven't found
what I'm looking for. I have a dataset with a time/date stamp on a series
of geographic locations (lat/lon) associated with the movements of animals.
On some days there are numerous locations and some days there
If you are going to read it back into R, then use 'save'; if it is
input to another applicaiton, consider 'write.csv'. I assume that
when you say save all my data files you really mean save all my R
objects.
On 8/7/07, Tiandao Li [EMAIL PROTECTED] wrote:
Hello,
I am new to R. I used scan() to
Is this what you want?
x - scan(textConnection(1979.00
+
+ 1979.020833
+
+ 1979.041667
+
+ 1979.062500), what=0)
Read 4 items
# get the year and then determine the number of seconds in the year so you can
# use the decimal part of the year
x.year - floor(x)
# fraction of the year
x.frac
Assuming *A* animal can only be in one location at any one time, I don't
understand how once you have selected the location nearest 12pm how you can
select based on the type of location?
Do you mean to select on location before timei.e. from the best location
visited that day which was closest
Hi Nair,
If the two populations are normal the t-test gives you
the exact result for whatever the sample size is (the
sample size will affect the number of degrees of
freedom).
When the populations are not normal and the sample
size is large it is still OK to use t-test (because of
the Central
Thanks Ross. Yes, upon your remark it seems that maybe I need to be
selecting first for the best available location, and then by the time stamp
nearest to 12pm. It seems like tapply(), or aggregate() or aggregate.ts()
might be applicable, but I'm working through trying different functions and
I have tried the following to extract my subset and no luck yet. Any ideas?
subset.df-subset(df, subset=c(DeployID,Date.Time,
LocationQuality==(ordered(c(Good, Poor, Unknown))),
Latitude,Longitude), select= min(abs(Date.Time-12:00)))
I'm not sure if my 'ordered' argument will
In the first part of myfile.R, I used scan() 100 times to read data from
100 different tab-delimited files. I want to save this part to another
data file, so I won't accidently make mistakes, and I want to re-use/input
it like infile statement in SAS or \input(file.tex} in latex. Don't want
to
Read the data in and transform the Date, Time and Quality columns
so that Date and Time are the respective chron classes (see RNews 4/1 Help
Desk article) and Quality is a factor such that lower levels are better.
Then sort the data frame by Date, Quality and time from noon. That would
actually
I would hope that you don't have 100 'scan' statements; you should
just have a loop that is using a set of file names in a vector to read
the data. Are you reading the data into separate objects? If so,
have you considered reading the 100 files into a 'list' so that you
have a single object with
Hi!
R is an amazing piece of software and with so many libraries it can do
almost anything... but I was very surprised that a standard binary
search function seems not to exist. I can find other much more
highly-complex search routines (optimize, uniroot, nlm) in the standard
I thought of loop at first. My data were generated from 32 microarray
experiments, each had 3 replicates, 96 files in total. I named the files
based on different conditions or time series, and I really won't want to
name them after numbers. It will make me confused later when I need to
You don't have to name them after numbers. What I sent was just an
example of a character vector with file names. If you have all the
files in a directory, then you can set the loop to read in all the
files (or selected one based on a pattern match). If you are
copy/pasting the 'scan' command,
toby909 at gmail.com writes:
Is this a specialty with R2WinBUGS? Does it have something to do with the
seed
value? Isnt the seed value reset everytime I restart winbugs?
I always have the same seed if I start WinBUGS multiple times.
Gregor
__
Dear R users,
I am fitting a t-distribution to some data, then selecting randomly from
the distribution. I am using the brand new ghyp package, which seems
designed to do this. Firstly is this approach appropriate or are their
alternatives I should also consider? I have a small dataset and the
Thanks,
I have considered using array but I dont belive its possible. For my
function isn't really paste(), its a custom function that takes the three
different parameters. The result however is a matrix where the size depends
on the inputs. I belive thats hard to fit into an array. But if you
Another way to do this is by using the SQLite select statements making
use of the sqldf package.
First let us assume that the alphabetic order of the Quality levels
reflects their desirability as well. In the example data this is true
but if its not true in the whole data set where there may be
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