A variety of tricks would need to be used to invert a matrix of this size. If
there are any other properties of the matrix that you know (symmetric, positive
definite, etc, sparse) then they could be useful too. You could partition the
matrix first, then use an in-place inverse technique for eac
Hi-
I am trying to find a way to diffuse GIS data on a European map. I have a
dataset consisting of particular locations scattered across Europe,
along with magnitude and value information. I can plot these as discrete
points with something like the following:
"geocode" is a dataframe with four c
try >help.search("state space") you will get pointer where you want to go
cm.state(CreditMetrics) Computation of state space
dlmLL(dlm)Log likelihood evaluation for a
state space model
SS(dse1) State Space Models
colorbar() from the package matlab.
nightly.py wrote:
>
> Hi, I have some data which I was plotting using image(). I wanted to
> add a vertical color key to the plot and I found that heatmap.2 in
> gplots does let me add a color key. However, I was thinking of a
> vertical bar with the co
I would greatly appreciate if someone can tell me how to solve the issue I have
been facing. After creating a large sparse matrix (6300 by 8300 matrix), I
saved image of it in my work space to do further computation. Since then
whenever I start R (version 2.5.1 on Windows XP, SP2), I seem to ge
Hey all,
I am trying to work under a State Space form, but I didn't get the help
exactly.
Have anyone eles used this functions?
I was used to work with S-PLUS, but I have some codes I need to adpt.
Thanks alot,
Bernardo
[[alternative HTML version deleted]]
While inverting the matrix may be a problem, if you
need to solve an equation A*x = b you do not need to
invert A, there exist iterative methods which do need
A or inv(A) - all you need to provide is a function
that computes A*x for an arbitrary vector x.
For such a large matrix this may be slow bu
As I understand this,
P(T+ | D-)=1-P(T+ | D+)=0.05
is the probability not to detect desease for a person
at ICU who has the desease. Correct?
What I asked was whether it is possible to mistakenly
detect the desease for a person who does not have it?
Assuming that this is impossible the formula i
You can get the legend outside the plot region by
1. First changing the clipping region via par(xpd = TRUE) ; (or xpd=NA). see
?par
2. Specifying x and y coodinates for legend placement outside the limits of
the plot region.
This allows you to include a legend without adding a bunch of useless
w
Hi Duncan, Hi Michael,
Duncan Murdoch stats.uwo.ca> writes:
> On 8/13/2007 1:33 PM, Michael Kubovy wrote:
>
> - You saw ugly artifacts in a graph you produced. That's a bug. The
> question is, what caused it?
> - You rightly asked on R-help. It might have been a bug in the way
> you we
Team, we figured this out, Roger at XLSOLUTIONS solved the puzzle for
us..!! Okay you can easily change the color palette.
see below:
library(MASS)
library(deldir)
set.seed(1123)
y <- runif(20)
x <- runif(20)
#run voronoi from deldir package
ddd <- deldir(x,y)
ttt <- tile.list(ddd)
plot.deld
HI
I got a problem in the predict function of the kernlab.
I want to use ksvm and predict with kernelmatrix (S4 method for signature
'kernelMatrix')
#executing the following sentences
library(kernlab)
# identity kernel
k <- function(x,y) {
n<-length(x)
cont<-0
for(i in 1:n){
if(
Hi Akki,
Then you may need to increase y-axis scale by ylim=c(min,max)
Cheers
Nguyen
On 8/12/07, akki <[EMAIL PROTECTED]> wrote:
> Hi,
> I have a problem when I want to put a legend on the graph.
> I do:
>
> legend("topright", names(o), cex=0.9, col=plot_colors,lty=1:5, bty="n")
>
> but the legen
Dear List,
I'm trying to import a multiple polygon shapefile in splancs. I've found the
following command but it seems to work only for single polygons:
Name_of_splancs_polygon<-getPolygonCoordsSlot
(getPolygonsPolygonsSlot(getSpPpolygonsSlot(name_of_sp_polygon) [[1]]) [[1]])
I've tried to
Ryan Briscoe Runquist ucdavis.edu> writes:
>
>
> Hello,
>
> I am having a bit of trouble with scatterplot3d().
>
> I was able to plot a 3d cloud of points using the following code:
>
> >my.3dplot<-scatterplot3d(my.coords, pch=19, zlim=c(0,1), scale.y=0.5,
> angle=30, box=FALSE)
>
> where my
I have data on number of vines per tree for ~550 trees. Over half of
the trees did not have any vines and the data is fairly skewed
(median = 0, mean = 1.158, 3rd qu. = 1.000). I am attempting to
investigate whether plot location (four sites), species (I'm using
only the four most common
For example, the correlation matrix is 3x3 and looks like
1 0.75 0 0 0
0.751 0 0 0
0 0 0 0 0
Can I write the code like this?
p<- 3 # number of variables per observation
N<- 10 # number of samples
# define population correlation matrix sigma
sigma<-matrix(0,p,p
I don't think you can define a matrix this large in R, even if you have
the memory. Then, of course, inverting it there may be other programs
that have limitations.
Paul
Jiao Yang wrote:
> Can R invert a 16x16 matrix with all positive numbers? Thanks a lot!
>
> ___
Part of the homework you were supposed to do before asking this question:
help.search("coefficients")
.
.
.
coef(stats) Extract Model Coefficients
.
.
.
So, go read
?coef
and
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
As your emai
You would need 200GB to store a since image, so if you have about 1TB
of physical memory on your computer, it might be possible.
On 8/13/07, Jiao Yang <[EMAIL PROTECTED]> wrote:
> Can R invert a 16x16 matrix with all positive numbers? Thanks a lot!
>
>
Thanks Deepayan,
I actually looked at the upper section but couldn't not spot these
arguments. I thought they were optional arguments in '...'. I will try
to open my eyes next time ;)
Deepayan Sarkar a écrit :
> On 8/13/07, Sébastien <[EMAIL PROTECTED]> wrote:
>
>> Dear R-users,
>>
>> The
Hello,
I would like to use the BDS test from the tseries package, but there is
something I don't understand in the results of the test. Let's say, I
want the BDS values for an embedding dimension equal to 2 :
> bds.test(c, m = 2, eps = seq(0.5 * sd(c), 2 * sd(c), length =
4),trace=FALSE);
Her
Can R invert a 16x16 matrix with all positive numbers? Thanks a lot!
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide c
Hi there,
In multiple regression one way to view R^2 is as (the square of) the
correlation between original y's and the estimated y's.
Suppose you fit a multilevel model with random intercept for each
cluster. Would it be valid to compute an R^2 by using fixed effects
plus the group intercept
On 8/13/07, Sébastien <[EMAIL PROTECTED]> wrote:
> Dear R-users,
>
> The help does not give much details on the use of the arguments 'from'
> and 'to' in the panel.abline function.
Not surprising, since panel.abline doesn't actually have arguments
called 'from' and 'to'.
> I have looked in the ar
Dear Catarina,
I prefer to leave the AIC value as NA for the tweedie GLM family
because it takes extra time to compute and is only occasionally
wanted. It's easy to compute the AIC yourself using the dtweedie()
function of the tweedie package.
Best wishes
Gordon
At 03:05 AM 14/08/2007, Catari
Hi, I have some data which I was plotting using image(). I wanted to
add a vertical color key to the plot and I found that heatmap.2 in
gplots does let me add a color key. However, I was thinking of a
vertical bar with the color range rather than the style that gplots
provides.
Is there a
Dear R-users,
The help does not give much details on the use of the arguments 'from'
and 'to' in the panel.abline function. I have looked in the archives but
did not find how to implement them. My different tries failed miserably.
E.g, the following code doesn't seem to work, in a sense that th
This should do it:
> txt
[1]
"\nhttp://www.mysite.com/system/empty.asp?P=2&VID=default&SID=421384237289476&S=1&C=18631";
[2]
"\nhttp://www.mysite.com/system/empty.asp?P=123&VID=default&SID=421384237289476&S=1&C=18643";
[3]
"\nhttp://www.mysite.com/system/empty.asp?P=342&VID=default&SID=42138423
On 8/13/2007 3:03 PM, Ryan Briscoe Runquist wrote:
> Hello,
>
> I am having a bit of trouble with scatterplot3d().
>
> I was able to plot a 3d cloud of points using the following code:
>
>>my.3dplot<-scatterplot3d(my.coords, pch=19, zlim=c(0,1), scale.y=0.5,
> angle=30, box=FALSE)
>
> where my.
On 8/13/07, Yuelin Li <[EMAIL PROTECTED]> wrote:
> Thanks for the quick response. The general use is like the following.
> Suppose I have another variable, tkmark, which for cohort "1970" is
> coded 1.0 at x = c(7, 19) and 0 otherwise. For cohort "1980", tkmark
> is coded 1.0 at x = c(2, 11, 12,
I seem to recall that rfImpute() can sometimes come up with NAs at some
point in the iterations. Could you please send me a (small) set of
data/code that reproduces the problem?
Andy
From: Eric Turkheimer
>
> I am having trouble with the rfImpute function in the
> randomForest package.
> Here
Hello,
I am having a bit of trouble with scatterplot3d().
I was able to plot a 3d cloud of points using the following code:
>my.3dplot<-scatterplot3d(my.coords, pch=19, zlim=c(0,1), scale.y=0.5,
angle=30, box=FALSE)
where my.coords is a data frame that contains x, y, and z coordinates for
grid
I am trying to analyse a mouse dataset with 45000 genes and 24 or 48
timpoints to find cycling genes using GeneCycle. However the function
fisher.g.test never runs. I am pasting the input/output summary below. I
would be grateful if someone could provide any insight.
I 've run GeneCycle successful
Thanks for the quick response. The general use is like the following.
Suppose I have another variable, tkmark, which for cohort "1970" is
coded 1.0 at x = c(7, 19) and 0 otherwise. For cohort "1980", tkmark
is coded 1.0 at x = c(2, 11, 12, 19) and 0 otherwise. For each
"cohort", I want to mark w
Hello,
I am looking at data on child survival from a survey with a stratified
two-stage design. I have been trying out the excellent survey package, with
which I have done a descriptive analysis and Cox models. I need to calculate
rates (with a child-year denominator) and various rate ratios plus
Dear R ussers,
I'm still working with the categorical models, and i can not do cross
validation on them because odf their nature.
not cv works perfectly on other models so i wonderd if it is possible to
extract the beta's from a categorical model, then use their value in a
0/1 glm.
Their formu
Hi
I am looking for a structural equation modeling package in R which can be
used for categorical data. Is anyone aware of the existence of such a
package? Would appreciate any help on this.
Thank you
Upasna
--
-
Upasna Sharma
Thank you, Rowan, for the explanation and another workaround.
I think my major confusion stemmed from the idea that the plotted point
colors would change only as a result of changing the limits of the plot.
I was and still am confused by the disparity between the plot using
PBSmapping and the
Dear R-users,
How do I extract numbers between asp?P= and &VID from my txt vector? I have
tried grep function with no luck.
txt <- c("
http://www.mysite.com/system/empty.asp?P=2&VID=default&SID=421384237289476&S=1&C=18631";,
"
http://www.mysite.com/system/empty.asp?P=123&VID=default&SID=421384237
On 8/13/2007 1:33 PM, Michael Kubovy wrote:
> Hi Duncan,
>
> I was trying to learn to remove the artifacts by setting the
> parameters of the image so that anti-aliasing wouldn't produce them
> (analogous to making sure that the screens of two halftone screen
> process images are in register
Hi Duncan,
I was trying to learn to remove the artifacts by setting the
parameters of the image so that anti-aliasing wouldn't produce them
(analogous to making sure that the screens of two halftone screen
process images are in register before combining them so as to avoid
Moiré patterns).
Hi David,
Thanks for the message. Essentially, the argument 'col' is treated like
a vector which remains independent from (X,Y) and is simply repeated as
need for the number of points. If you specify
col=c("red","blue","green","yellow") as below, and there are only 2
points, only "red" and "blue" w
Dear all,
Thank you for your helpful comments. I have acquired and read
Steyerberg (2001). I may try some of the methods from that paper.
This did prompt a thorough examination of the data. Sure enough, my
worst outlier, where little diversity was observed and the NDVI
measurment was very high
On 8/11/07, Yuelin Li <[EMAIL PROTECTED]> wrote:
> In the hypothetical example below, how do I add two segments() into
> the two panels, respectively? Say segments(x0=5, y0=10, x1=5, y1=20)
> on the left and segments(x0=15, y0=-10, x1=15, y1=-2) on the right?
> Many thanks in advance,
>
> Yuelin L
On 8/13/2007 11:43 AM, Michael Kubovy wrote:
> But is it a bug? Can a program anti-alias text and line drawings and
> not bitmaps?
Anti-aliasing is the removal of artifacts caused by displaying an image
on a low-resolution bitmapped display. Introducing artifacts is a bug.
If it wasn't a bug,
Hi, there:
The following question is more of statistics:
assume i have 5 features in a classification, and I am wondering which
methodology can help me identify which feature "contributes" the most
to classify a specific sample?
I knew some simple modeling like logistic regression probably can d
But is it a bug? Can a program anti-alias text and line drawings and
not bitmaps?
On Aug 13, 2007, at 9:30 AM, Duncan Murdoch wrote:
> On 8/13/2007 11:07 AM, Michael Kubovy wrote:
>> Dear Friends,
>> Thanks for your input.
>> FYI: Preview doesn't show PDF aliasing in the image I produced if
>
This is one of R's rather _endearing_ little
idiosyncrasies. I ran into it a while ago.
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/98090.html
For some reason, possibly historical, the option
"stringAsFactors" is set to TRUE.
As Prof Ripley says FAQ 7.10 will tell you
as.numeric(as.chara
On 8/13/2007 11:07 AM, Michael Kubovy wrote:
> Dear Friends,
>
> Thanks for your input.
>
> FYI: Preview doesn't show PDF aliasing in the image I produced if I
> uncheck the "Anti-alias text and line art" box under the PDF tab in
> Preferences. So I'm not yet ready to drop Preview from my too
Dear Friends,
Thanks for your input.
FYI: Preview doesn't show PDF aliasing in the image I produced if I
uncheck the "Anti-alias text and line art" box under the PDF tab in
Preferences. So I'm not yet ready to drop Preview from my toolbox.
MK
On Aug 13, 2007, at 12:02 AM, Mark Wardle wrote:
>>> Petr PIKAL <[EMAIL PROTECTED]> 13/08/2007 14:10:40 >>>
>> How do I read one row of data so as to load site2 into a variable
>>called site2?
>
>?read.table and other read. commands.
Don't forget scan(). But Petr is right, you probably do not need to read one
row at a time.
>> Once
Hi Richard,
No specific answers for your data questions but for
learning R there are any number of resources.
There are links to references for books and a large
number of on-line materials on the R website. Have a
look at the list on the bottom left of the screen for
"books" and "other" which l
Hi,
I've 2 little questions:
Is possible change the size of the values of x and y axes, when I do plot??
How can I put a range of 0.0001 to 5.5000, although my max value is 4 on 'y'
axe log scale (without pattern 1e-0'X')?
Thanks.
[[alternative HTML version deleted]]
Hi
[EMAIL PROTECTED] napsal dne 13.08.2007 14:04:50:
> Dear all,
>
>
> I have 4 sites and want to determine how different they are from each
other.
> For this I have decided to use R though it seems a bit daunting to
learn.
> I have read data in from a CSV the structure is :
>
>Specie
Hi,
I was wondering if Statdataml is currently the preferred way to
represent statistical data in XML in R. And also if the Statdataml api
provides ways to load the XML as a HTTP GET?
If so can you give me an easy example of this. Thanks.
Cheers,
Bryan Rasmussen
Hi.
You should study "An Introduction to R" manual.
It is installed with R in PDF format and is accessible from the menu (Help
-> Manuals (in PDF) -> )
There are several links in the R web site.
Go to http://www.r-project.org/ and see links under the word "Documentation"
in the left frame.
There
Hello,
I am trying to estimate an ordered logistic regression in R, and I wish to
use robust estimators. Can this be (simply) done? More specifically, can
this be done using polr (in MASS) together with sandwich. I am using R
2.5.1 on Mac OS 10.4.10. If not, is there any other way?
I can fit a mo
Dear all,
I have 4 sites and want to determine how different they are from each other.
For this I have decided to use R though it seems a bit daunting to learn.
I have read data in from a CSV the structure is :
Species1 Species2 Species3
Site1 4 4 7
Site2 3 1 0
Site3 0 99 6
? par# then scroll down to look at 'las'
You probably want
par(las=1)
HTH, Mike.
akki wrote:
>
> hi,
> When I do a graph. the values on y axe are vertical position. How can I
> put
> the values in horizontal position?
>
> thanks
>
> [[alternative HTML version deleted]]
>
>
On Mon, 2007-08-13 at 13:37 +0200, akki wrote:
> hi,
> When I do a graph. the values on y axe are vertical position. How can I put
> the values in horizontal position?
>
> thanks
If you mean "How do I rotate the tick labels?" then look at ?par and
parameter 'las'. E.g. this shows the options avai
hi,
When I do a graph. the values on y axe are vertical position. How can I put
the values in horizontal position?
thanks
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
See ?class
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
On 13/08/07, Jabez Wilson <[EMAIL PROTECTED]> wrote:
>
> Dear all, please help with what must be a straightforward question which I
> can't answer.
>
> I add a column of my dataframe as factor of an existing
typeof() for 'types'.
However, "factor" is not a type but a class, so class() is probably what
you want.
On Mon, 13 Aug 2007, Jabez Wilson wrote:
> Dear all, please help with what must be a straightforward question which
> I can't answer.
But 'An Introduction to R' could.
> I add a column o
Dear all, please help with what must be a straightforward question which I
can't answer.
I add a column of my dataframe as factor of an existing column e.g.
df[,5] <- factor(df[,2])
and can test that it is by is.factor()
but if I did not know in advance what "types" the col
Assuming that the daily.incomes are the same lengths, then your loop could be:
Lst <- list()
for (i in 1:count) Lst[[i]] <- list(..)
Lst.col <- do.call('cbind', Lst)
On 8/12/07, Yuchen Luo <[EMAIL PROTECTED]> wrote:
> Dear friends.
> Every loop of my program will result in a list that is very
On Sun, Aug 12, 2007 at 10:50:59AM -0700, Yuchen Luo wrote:
> Dear Professor Murdoch.
> Thank you so much
>
> Best Wishes
> Yuchen Luo
>
> On 8/12/07, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
> >
> > Yuchen Luo wrote:
> > > Dear Colleagues.
> > >
> > > I believe this should be a problem enco
a) I agreed with your suggestion about the condition "else". L = Level of
noise fluctuates during the various moments of the day (i.e L= L+5 between
18:00:00 and 21:59:59; L=L+10 between 22:00:00 and 05:59:59 and L = L
else).
b)
mytab is a data table including Time column, Level column, ,
T
KOITA Lassana - STAC/ACE wrote:
> Hi,
> data are extracted from MS Access with the format: ("%d/%m%Y %H%M%S"); ex:
> 16/09/2006 03:38:37
1. the example you gave in your first message is still not reproducible,
you gave the following:
myfunc <- function(mytab, Time, Level)
{
vect <- rep(0, le
yoo wrote:
> Yea, I found the shutdown function in the java interface as well.. but is
> there a way I can send a shutdown command through linux shell? (something
> that I can cron?)
Write a minimal java program that sends the shutdown command, then run
that from your shell...
Barry
_
Arjun Bhandari adia.ae> writes:
> I conduct a univariate regression with lm function. I would like to get
> the p value for the regression. Is there a method that would enable me to
> extract the p value into a variable.
# From lm docs (Sorry, Annette, for misusing your data)
ctl <- c(4.17,5.5
apply(tmp, 1, function(x) paste(sort(unique(x[x!=0])),collapse="_"))
Jacques VESLOT
INRA - Biostatistique & Processus Spatiaux
Site Agroparc 84914 Avignon Cedex 9, France
Tel: +33 (0) 4 32 72 21 58
Fax: +33 (0) 4 32 72 21 84
[EMAIL PROTECTED] a écrit :
>
> Hi List,
>
> I am combining column
Hi,
data are extracted from MS Access with the format: ("%d/%m%Y %H%M%S"); ex:
16/09/2006 03:38:37
I still have error messneger
Thank you for your help.
Lassana KOITA
Chargé d'Etudes de Sécurité Aéroportuaire et d'Analyse Statistique /
Project Engineer Airport Safety Studies & Statistical an
Hi,
The probability of false detection is: P(T+ | D-)=1-P(T+ | D+)=0.05.
and I want to find the joint probability P(T+,D+)=P(T+|D+)*P(D+)
Thank you for your reply,
Sigalit.
On 8/13/07, Moshe Olshansky <[EMAIL PROTECTED]> wrote:
>
> Hi Sigalit,
>
> Do you want to find the probability P(T+ = t AND
Thank you both!
The hint with the pty="s" was very useful. I did not know it before.
Ciao,
Antje
Ivar Herfindal schrieb:
> Dear Antje
>
> I cannot see that you have got any replies yet, so I will make and
> attempt. However, I am sure other have more formally correct solutions.
>
> When you c
Hi List,
I am combining column values of a dataframe to create a new variable
that is the sorted and unqiue combination of the columns (and excluding
0). The following works, but surely there is a more elegant way of doing
this?
t1<-NULL
for(i in 1:nrow(tmp)) {
if(i == 1){
sort(c(tmp[i,1],
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