Michael Friendly wrote:
Thanks to all who replied, particularly Duncan Murdoch, whose solution I
adopted.
It thought it might be of interest to some to see the results and
compare these ways
of representing the distribution of historical events over time.
The events are the items I
Michael Friendly wrote:
Thanks to all who replied, particularly Duncan Murdoch, whose solution I
adopted.
It thought it might be of interest to some to see the results and
compare these ways
of representing the distribution of historical events over time.
The events are the items I
Laura Holt wrote:
Hi R !
I have the following set up:
par(mfrow=c(2,2))
curve(dexp,from=0,to=5)
hist(z1,main=Size 5)
hist(z2,main=Size 15)
hist(z3,main=Size 30)
I would like to put a title at the very top of the page that ties the
theme of all the charts
together. How would
Mikkel Grum wrote:
In a number of different situations I'm trying to
remove factor levels that are represented by less than
a certain number of rows, e.g. if I had the dataset aa
below and wanted to remove the species that are
represented in less than 2 rows:
data(iris)
aa -
Ken Termiso wrote:
Hi all,
I've got a data frame with NA values scattered throughout. I would like to
find the rows which contain an NA. Trying to find the indices of the NAs
with grep() doesn't work (apparently you can't convert NA to NA character
value, even with as.character()) so I
Hi, all,
I just recently upgraded my computer though I'm using the same OS (XP).
But now I'm having difficulty building packages and I cannot seem to
solve the problem. I'm using R-2.1.1pat on Windows XP.
Here is what I tried:
D:\Users\sundard\slib\sundar\RR CMD CHECK sundar
* checking for
Duncan Murdoch wrote:
On 7/11/2005 3:21 PM, Sundar Dorai-Raj wrote:
Hi, all,
I just recently upgraded my computer though I'm using the same OS (XP).
But now I'm having difficulty building packages and I cannot seem to
solve the problem. I'm using R-2.1.1pat on Windows XP.
Here is what
David Kane wrote:
I have a formula from which I want to deduce the name of the response
variable. One way of doing so is as follows:
my.form - as.formula(y ~ x + z)
all.vars(my.form)[1]
[1] y
Is there a better way and/or preferrred method of determining y from
my.form than this
Benjamin Tyner wrote:
I'm updating the loess routines to allow for, among other things,
arbitrary local polynomial degree and number of predictors. For now,
I've given the updated package its own namespace. The trouble is,
panel.loess still calls the original code in package:stats instead
Eric Hu wrote:
Hi, I ran into a dilemma trying to plot the following data in a 3d
scatter fashion. My data are not always increasing as persp() expects.
For now I use scatterplot3d to get points in a 3d scatter plot. I
wonder if I have any way to plot the surfaces. Thanks!
Eric
Andy Bunn wrote:
Hello: I'm reading in a series of text files (100 files that are each 2000
rows by 6 columns). I wish to combine the columns (6) of each file (100) and
get the row mean. I'd like to end up with a data.frame of 2000 rows by 6
columns.
foo - list()
for(i in 1:10){
#
Jay Rotella wrote:
Hi,
I am interested in using the numeric output from the gradient attribute of
deriv's output in subsequent analyses.
But, I have so far been unable to determine how to do so.
I will use the example from the deriv help to illustrate.
## function with defaulted
Laura M Marx wrote:
Hi there,
I've looked through the very helpful advice about adding fitted lines to
plots in the r-help archive, and can't find a post where someone has offered
a solution for my specific problem. I need to plot logistic regression fits
from three differently-sized
Sam Baxter wrote:
Hi
I am trying to set up 16 graphs on one graphics page in R. I have used
the mfrow=c(4,4) command. However I get a lot of white space between
each graph. Does anyone know how I can reduce this?
Thanks
Sam
Two options:
1. play around with the `mar' parameter
[EMAIL PROTECTED] wrote:
Hi R users,
I am having a little problem finding the the solution to this problem in R:
1. I need to generate normal distribution of sample size 30, mean = 50, sd =
5.
2. From the statistics obtained in step 1, I need to generate the Inverse
Gamma
[EMAIL PROTECTED] wrote:
I'm having trouble with the order of the panels using xyplot. I had used
this bit of code before and received the desired plot (the code was not
identical, but very similar; perhaps more importantly I was working with an
older version of R) . Now the panels
Mike Jones wrote:
Hi,
I'd like to return the rows of sampled values of a vector. Can't figure
out how to do it.
For example: I start with [3, 1, 7, 4, 10] that have position
[1,2,3,4,5]. I sample [10,1,4] and I want to return [5,2,4].
I'm sure there's a simple way to do that but
Gregory Gentlemen wrote:
Hi guys
im having a problem getting R to numerically integrate for some function,
say f(bhat)*optimize(G(bhat)), over bhat. Where id like to integrate this
over some finite range, so that here as we integrate over bhat optimize would
return a different optimum.
Again, not a good example, since f is linear in n so the max will always
be at 15.
Try this:
f - function(x, n) -(x - 2.5 * n)^2 # max is at 2.5*n
g - function(n) {
o - vector(numeric, length(n))
for(i in seq(along = n))
o[i] - optimize(f, c(0, 15), maximum = TRUE, n =
Hi, Mike,
Mike Lawrence wrote:
Hi Deepayan,
Thanks for the reply, but when I enter the type = b code into the
auto.key
(see below) command I get the following message:
Error in valid.pch(x$pch) : zero-length 'pch'
Any suggestions?
Why not just ignore auto.key and use key?
Rebecca Young wrote:
Hello,
Can you get eigenvalues in addition to eigevectors using prcomp? If so how?
I am unable to use princomp due to small sample sizes.
Thank you in advance for your help!
Rebecca Young
Hi, Rebecca,
From ?prcomp:
The calculation is done by a singular
Hi, Anders/Dimitris,
Dimitris Rizopoulos wrote:
maybe you could consider something like this:
dat - data.frame(x = c(1, 2, 2, 3, 3, 4),
y1 = c(1, 1, 2, 1, 7, 8),
y2 = c(NA, NA, NA, 5, 5, 4),
y3 = c(3, 11, NA, 16, 2, 1))
#
Eric Archer wrote:
List gurus,
I'm trying to code a Gompertz growth curve function as part of a larger
project and have run across a problem due to my ignorance of
environments. Some sample data and the function are as follows:
growth - data.frame(age = c(1.92, 3, 5.83, 3.17, 15.5,
Rangesh Kunnavakkam wrote:
I have a large vector of around 12597 elements and I wish to calculate
p-value for each element using a formula of something like:
p-value= 1- exp^(kexp^(-labda))
I was wondering someone could give some ideas how to implement for each
nwew wrote:
Dear R-helpers,
The function optim implements algorithms that I would like to use.
I have function implemented in R, which given the parameters of which
minimization is to take place returns a scalar as well as the gradient.
Unfortunately optim requires two function
Abdou ALI wrote:
Do you know why additional graphical parameters (like type,pch, ...)
do not work in the R contour fonction. For example the command
'contour(..., type=o,pch=16)' gives nothing, just simple contour lines.
Please, can you explain why you think it does make sense here?
The
吴 昊 wrote:
Hi
does R provide some interpolation fucntions?
thank
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
tom wright wrote:
Can someone please explain why this works:
d-c(0,2,3,2,0,3,4,0,0,0,0,0)
d.mat-matrix(data=d,nrow=4,ncol=3,byrow=TRUE)
for(i in 1:length(d.mat[1,])){
+ d.mat[,i][d.mat[,i]==0]-mean(d.mat[,i][d.mat[,i]0])
+ }
Whereas:
d-c(0,2,3,2,0,3,4,0,0,0,0,0)
Clark Allan wrote:
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
2 2
3 3
4
i stil want the following!
z[,1]=1
z[,2]=1:3
z[,3]=1:5
i made
Katharina,
I agree with Prof. Ripley's assessment. But, perhaps one thing you may
have overlooked is that subset.data.frame does not remove unused levels. So,
subset_of_dataframe = subset(data_frame, (b 80 c 190))
levels(subset_of_dataframe$d)
[1] q r s t
table(subset_of_dataframe$d)
mark salsburg wrote:
I have a vector of size 217 called A.
the values of A are not sorted and range from 0 to 1 (normalized)
I am having difficulty writing a program to create a new vector B where
if A's value is 0 A =0.333 then B is 0
if A's value is 0.333 A =0.666 then B is 1
if
mark salsburg wrote:
I have a vector of size 217 called A.
the values of A are not sorted and range from 0 to 1 (normalized)
I am having difficulty writing a program to create a new vector B where
if A's value is 0 A =0.333 then B is 0
if A's value is 0.333 A =0.666 then B is 1
if
Hu, Ying (NIH/NCI) wrote:
I have two data sets:
File1.txt:
Name id1 id2 id3 ...
N10 1 0 ...
N20 1 1 ...
N31 1 -1...
...
File2.txt:
Group id1 id2 id3 ...
G1 1.22 1.34 2.44 ...
G2 2.33
PROTECTED]
Sent: Wednesday, August 17, 2005 7:01 PM
To: Sundar Dorai-Raj
Cc: Hu, Ying (NIH/NCI); r-help@stat.math.ethz.ch
Subject: Re: [R] do glm with two data sets
On Wed, 2005-08-17 at 17:22 -0500, Sundar Dorai-Raj wrote:
Hu, Ying (NIH/NCI) wrote:
I have two data sets:
File1.txt:
Name id1
: Thursday, August 18, 2005 11:00 AM
To: Hu, Ying (NIH/NCI)
Cc: Sundar Dorai-Raj; r-help@stat.math.ethz.ch
Subject: RE: [R] do glm with two data sets
On Thu, 2005-08-18 at 10:38 -0400, Hu, Ying (NIH/NCI) wrote:
Thanks for your help.
# read the two data sets
e - as.matrix(read.table(file1.txt
Ross Boylan wrote:
I want to add an argument if it is not present. Following the Green
Book, p. 337:
test - function(x, ...){
dots - list(...)
if (!hasArg(from))
from - 0
else
from - dots$from
curve(x, from=from, ...)
}
test(sin)
test(sin, from=4)
Error in
Sundar Dorai-Raj wrote:
Ross Boylan wrote:
I want to add an argument if it is not present. Following the Green
Book, p. 337:
test - function(x, ...){
dots - list(...)
if (!hasArg(from))
from - 0
else
from - dots$from
curve(x, from=from, ...)
}
test(sin)
test(sin, from=4
Anon. wrote:
I'm sure I'm missing something obvious here, but I can't find the
solution (including in the FAQ etc.).
I have a vector of names of variables like this: NRes.x.y. where x and y
are numbers. I want to extract these numbers as numbers to use
elsewhere. I can extract the
?rbind
--sundar
Mag. Ferri Leberl wrote:
Dear colleagues!
I am afraid this is an easy question but as a pitty I did not find out on my
own, so please be patient with my question:
If I have a data frame X and an array Y. Which is the command to make Y
become
an additional row of X?
Martin Henry H. Stevens wrote:
Mac OS 10.3.9 R framework v. 2.1.1
I am attempting to put a fitted curve into each panel of a lattice
graph, but am failing to do so. I have tried writing a very
sophisticated function to do so. The function seems to work when used
with plot(), but does
Jamieson Cobleigh wrote:
Similar to my last question, I want to tighten up the spacing and
margins in a plot I am doing with lattice.
Here are the commands I'm using:
data - data.frame(x=c(1:3, 1:3), y=c(1:3, 1:3*2),
cat=c(foo,foo,foo,bar, bar,bar))
xyplot(panel=panel.superpose, y~x,
Patrick Connolly wrote:
I've never had this problem before and can't see what could be
different from other times I've used keys with lattice.
It appears that auto.key is being taken as TRUE when I specify a key
list. The list I specify seems to be ignored.
Where can I place a
Olshansky,Moshe wrote:
What is the classic R function for solving a (possibly over
determined) system of non-linear equations?
Thank you!
Moshe Olshansky
e-mail: [EMAIL PROTECTED]
I'm not sure what your definition of 'classic' is, but there are
several options in
[EMAIL PROTECTED] wrote:
Can anyone tell me how to do set
differences in R?
e.g., if I have a vector
a-c(1,2,3,4,5) and another vector
b-c(2,5), how can I do something like
a/b = (1,3,4)?
Thanks!
a[!a %in% b]
*or*
setdiff(a, b)
--sundar
Antoine de Bary wrote:
Hi, and thanks for your help
in order to do collinearity analysis I downloaded the perturb package. I run
a lm (regression) and on that the ³calldiag² commad to get condition numbers
but i get the following message: the variable XY with modus ³numeric² was
not found
Carlos Maurício Cardeal Mendes wrote:
Hi everyone !
Could you please help me with this problem ?
I´ve trying to write a code that assign to a variable the content from
another, but all I´ve got is a message error. For example:
if (age =10) {group == 1}
else if (age 10 age = 20)
Three things:
1. Please do not hit the reply button to an unrelated topic and change
the subject. As the signature tells you, PLEASE do read the posting
guide! http://www.R-project.org/posting-guide.html;
2. You are looking for the eda *package* and not a *library*.
3. Since eda is not on
Omar Lakkis wrote:
How can I determine whT OS I am running under?
if WINDOWS do this
if LINUX do that
Hi, Omar,
Look at version$os.
# windows
version$os
[1] mingw32
# linux
version$os
[1] linux-gnu
HTH,
--sundar
__
if is not vectorised and age is a vector. Try the following test:
if(c(TRUE, FALSE)) TRUE else FALSE
You really need to use ifelse.
ifelse(c(TRUE, FALSE), TRUE, FALSE)
As others have suggested, you might want to look at ?cut.
--sundar
Carlos Mauricio Cardeal Mendes wrote:
Ok Petr, I run
A.Brennan wrote:
Hi
i am having a problem with the 'integrate' function
the function i want to integrate has the form
sum(vector^x)
i have defined the function with a for loop first -
integrandtotest - function(x)
{a-rep(0,len=2)
for (i in 1:2)
{a[i]-t[i]^x}
My guess is he wants this:
c1 - factor(c)
d1 - factor(d)
m - lmer(a ~ b + (1|c1:d1)+(1|c1))
which assumes d1 is nested within c1.
Take a look at Section 3 in the MlmSoftRev vignette:
library(mlmRev)
vignette(MlmSoftRev)
HTH,
--sundar
Doran, Harold wrote:
I think you might have confused lme
[EMAIL PROTECTED] wrote:
subject: trimmed mean in R seems to round the trimming fraction
to [EMAIL PROTECTED]
Consider the following example of 10 numbers. 10% trimmed mean is correct
but you can see that the result is the same for many trimming fractions
till 0.20!
For example
Qiong Yang wrote:
Hi,
I could not use 'exlcude=' option in factor()
to exclude a level from a existing factor.
x is a factor:
x
[1] a b c
Levels: a b c
factor(x,exclude=c)
[1] a b c
Levels: a b c
Warning message:
NAs introduced by coercion
However, c is not coded as
Randall R Schulz wrote:
Hadley,
On Thursday 22 September 2005 16:36, hadley wickham wrote:
Reshape version 0.5
===
Reshape is an R package for flexibly restructuring and aggregating
data. It's very much pivot table inspired, and it (hopefully) makes
it very easy to view
Florian Defregger wrote:
Dear all,
I wonder if I can put together a histogram where one bin contains all the
values that are larger than a certain specified value.
Example:
I have values ranging from 0 to 40 and I want 10 bins from 0 to 10, i.e. for
the intervals [0,1), [1,2) , ...,
Kemp S E (Comp) wrote:
Hi,
I am using the arima.sim function to generate some AR time series. However,
the function does not seem to produce exactly the same time series when I
specify the innov parameter. For example
r - rnorm(300)
x - arima.sim(300,
Adrian DUSA wrote:
Dear all,
In order to ease the transition from SPSS to R for some of my colleagues, I
am
trying to create a function which would show the variables and their labels
(if those exist), using function label in package Hmisc.
A toy example would be this:
my.data -
Adrian DUSA wrote:
On Friday 07 October 2005 20:55, Sundar Dorai-Raj wrote:
Adrian DUSA wrote:
[...snip...]
Hi, Adrian,
You need to assign fix(dataf) to something:
my.data - data.frame(age=c(24,35,28), gender=c(Male, Female, Male))
require(Hmisc)
label(my.data$age) - Respondent's age
Xiao Shi wrote:
Hi ,
I have a vector,for example,
x=rnorm(100)
Then i rendom choose 20 of them.
chosen=sample(x,20).
And i want to get the remain values in x.
Is there a quick way to go?
Thanks in advance.
[[alternative HTML version deleted]]
How about:
x - rnorm(100)
y -
Michel Friesenhahn wrote:
I'm using read.csv to read in a csv file containing '#' characters. For
example, say I'm reading the following file (test.csv):
var1,var2,var3
a,b,c
d,e#,f
g,h,i
It outputs:
read.csv(Raw Data\\test.csv)
var1 var2 var3
1abc
2de
Jan Sabee wrote:
Dear all,
I am still learning R with write a small function for my self.
I was wondering if someone can help me to write a R function formula below:
Z_k (x) = \sum_{i=0}^{i=k} \binom{n}{i} (m-1)^i
Thanks a million in advance,
Sincerely,
Jan Sabee
(This smells like a
Waichler, Scott R wrote:
Is there a way to get the aspect ratio as output from a plot() call or
something similar in the base graphics system? I would like to note
vertical exaggeration on an elevation profile.
Thanks,
Scott Waichler
Pacific Northwest National Laboratory
[EMAIL
Tom Lenaerts wrote:
Hello,
Using the following code i want to make a level or contourplot of some
data that I produced
library(grid);library(lattice);
No need to explicitly load grid. This is done when attaching
lattice. Also, you do not need any ; at the end of any lines.
mydata
://www.tomlenaerts.tk/
Postdoc Researcher @ IRIDIA-Universite Libre de Bruxelles-Belgium
Guest Professor @ DINF-Vrije Uiversiteit Brussel-Belgium
On 11 Oct 2005, at 22:26, Sundar Dorai-Raj wrote:
Tom Lenaerts wrote:
Hello,
Using the following code i want to make a level
t c wrote:
What are the functions available for use with “aggregate”? Where can a
reference to them be found?
Since aggregate is a S3 generic, you can use
methods(aggregate)
to see what objects have an aggregate method. For me, I have the
following:
methods(aggregate)
[1]
Benedykt P. Barszcz wrote:
Dnia czwartek, 13 października 2005 23:25, Andrew Robinson napisał:
Marco,
use the system command.
?system
I hope that this helps,
system(ls, intern = FALSE, ignore.stderr = TRUE)
Error in as.character(args[[i]]) : cannot coerce to vector
In fact it
Dieter Menne wrote:
Dear R-Listeners,
as the Sweave faq says:
http://www.ci.tuwien.ac.at/~leisch/Sweave/FAQ.html
creating several figures from one figure chunk does not work, and for
standard graphics, a workaround is given. Now I have a multipage trellis
plot with an a-priori
Doran, Harold wrote:
I need to wrap a loop inside a function and am having a small bit of
difficulty getting the results I need. Below is a replicable example.
# define functions
pcm - function(theta,d,score){
exp(rowSums(outer(theta,d[1:score],'-')))/
John Wiedenhoeft wrote:
Dear all,
I apologize if this is a FAQ (seems a bit like one, but I didn't find
anything).
I'm looking for an easy way to cut one value out of a vector and shorten
the vector accordingly. Something like:
x - c(1, 1, 0, 6, 2)
throwaway(x[3])
which will return
Georg Otto wrote:
Hi,
i have a list of several vectors, for example:
vectorlist
$vector.a.1
[1] a b c
$vector.a.2
[1] a b d
$vector.b.1
[1] e f g
I can use intersect to find elements that appear in $vector.a.1 and
$vector.a.2:
intersect(vectorlist[[1]],
Try:
plot(x, y, asp = 1)
--sundar
bogdan romocea wrote:
Dear useRs,
I'd like to produce some scatter plots where N units on the X axis are
equal to N units on the Y axis (as measured with a ruler, on screen or
paper). This approach
x - sample(10:200,40) ; y - sample(20:100,40)
LL wrote:
Hi.. I am running R version 2.3.1 on a Windows XP machine with the latest
Miktex 2.5 installed. I get no errors from R when running the Sweave example,
testfile - system.file(Sweave, Sweave-test-1.Rnw, package = utils)
However, when I tex the resulting .tex file (after
Hi, all,
I'm looking a utility for removing a directory from within R. Currently,
I'm using:
foo - function(...) {
mydir - tempdir()
dir.create(mydir, showWarnings = FALSE, recursive = TRUE)
on.exit(system(sprintf(rm -rf %s, mydir)))
## do some stuff in mydir
invisible()
}
Please ignore. I forgot ?unlink had a recursive argument.
Thanks.
--sundar
Sundar Dorai-Raj wrote:
Hi, all,
I'm looking a utility for removing a directory from within R. Currently,
I'm using:
foo - function(...) {
mydir - tempdir()
dir.create(mydir, showWarnings = FALSE
Hi, Jose/John,
Here's an example to help Jose and highlights John's advice. Also
includes set.seed which should be included in all simulations posted to
R-help.
set.seed(42)
mu - 10
sigma - 5
n - 3
nsim - 1
m - matrix(rnorm(n * nsim, mu, sigma), nsim, n)
t - apply(m, 1, function(x)
[EMAIL PROTECTED] wrote:
Hello,
I am a new user of R and found the function dtnorm() in the package msm.
My problem now is, that it is not possible for me to get the mean and sd out
of a sample when I want a left-truncated normal distribution starting at 0.
fitdistr(x,dtnorm,
Sorry, didn't notice that you *did* mention dtnorm is part of msm.
Ignore that part of the advice...
--sundar
Sundar Dorai-Raj wrote:
[EMAIL PROTECTED] wrote:
Hello,
I am a new user of R and found the function dtnorm() in the package msm.
My problem now is, that it is not possible for me
in advance
markus
Sorry, didn't notice that you *did* mention dtnorm is part of msm.
Ignore that part of the advice...
--sundar
Sundar Dorai-Raj wrote:
[EMAIL PROTECTED] wrote:
Hello,
I am a new user of R and found the function dtnorm() in the package
msm.
My problem now
, there is a way fitdistr can also compute difficult data.
Best regards, markus
-Original Message-
From: Sundar Dorai-Raj [mailto:[EMAIL PROTECTED]
Sent: Donnerstag, 17. August 2006 16:47
To: Schweitzer, Markus
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] fitting truncated normal
Maria Montez wrote:
Hi!
I would like to be able to create formulas automatically. For example, I
want to be able to create a function that takes on two values: resp and
x, and then creates the proper formula to regress resp on x.
My code:
fit.main - function(resp,x) {
form -
Nick Desilsky wrote:
Hi,
any good trick to get the column names for title() aside from running
lapply on the column indexes?
Thanks
Nick.
apply(X[,numCols],2,function(x){
nunqs - length(unique(x))
nnans - sum(is.na(x))
info -
Ernst O Ahlberg Helgee wrote:
Hi!
Im sorry to bother you but I cant fix this.
I use the lattice function levelplot and I want the colorkey at the
bottom, how do I get it there? I have tried changing colorkey.space and
changing in legend but I cant get it right, plz help
btw I'd like to
Robin Hankin said the following on 9/11/2006 3:52 AM:
Hi
Given a real number x, I want to know how accurately R can represent
numbers near x.
In particular, I want to know the infinum of exactly representable
numbers greater than x, and the supremum of exactly representable
Yes. I do this periodically:
dat.new - dat[1:6, ]
dat.new[] - lapply(dat.new, function(x)
if(is.factor(x)) factor(x) else x)
HTH,
--sundar
Afshartous, David said the following on 9/12/2006 11:00 AM:
thanks to all for the quick replies!
if the factor is part of a
Emmanuel Levy said the following on 9/12/2006 3:50 PM:
Hello,
I'd like to group the lines of a matrix so that:
A 1.0 200
A 3.0 800
A 2.0 200
B 0.5 20
B 0.9 50
C 5.0 70
Would give:
A 2.0 400
B 0.7 35
C 5.0 70
So all lines corresponding to a letter (level), become a single line
Dietrich Trenkler said the following on 9/13/2006 9:44 AM:
Dear HelpeRs,
I have some data:
ice - structure(c(0.386, 0.374, 0.393, 0.425, 0.406, 0.344,
0.327, 0.288, 0.269, 0.256, 0.286, 0.298, 0.329, 0.318, 0.381,
0.381, 0.47, 0.443, 0.386, 0.342, 0.319, 0.307, 0.284, 0.326,
Deepayan Sarkar said the following on 9/14/2006 2:31 PM:
Hi,
consider this:
--
estr - c(2^4, alpha[1])
eexp - expression(2^4, alpha[1])
## Is it possible to get 'eexp' starting from 'estr'? The closest I could
## get was:
do.call(expression, lapply(estr, as.name))
Benjamin Tyner said the following on 9/15/2006 2:36 PM:
In dotplot, what's the best way to suppress the unused levels of 'y' on
a per-panel basis? This is useful for the case that 'y' is a factor
taking perhaps thousands of levels, but for a given panel, only a
handfull of these levels
ERICK YEGON said the following on 9/18/2006 8:22 AM:
Hi Gurus, i have a small problem with working with graphs on R.
Say i have data say bull-c(34,23,7,4) and i assign names to the elements in
the brackets
if i do
Pie(bull) i get a pie chart of bull togtjer with the names.
Question. How
Iñaki Murillo Arcos said the following on 9/18/2006 12:31 PM:
Hello,
I don't know if the result of
acos(0.5) == pi/3
is a bug or not. It looks strange to me.
Inaki Murillo
__
R-help@stat.math.ethz.ch mailing list
kone said the following on 9/21/2006 2:30 PM:
Hi,
Is there some function, which generates this kind of n x n -matrix
from a vector?
rhset
[1] 1792 256 13312 512 1024 2048 8192 4096
m=matrix(nrow=length(rhset),ncol=length(rhset))
for(i in 1:length(rhset))
+
Caio Lucidius Naberezny Azevedo said the following on 9/22/2006 4:40 PM:
Hi all,
I need to solve double integrals with no closed solution. Calling x and y
the two variables we have x ~ Normal(y*v,1) and y ~Half-Normal(0,1). In fact,
given a joint funcion g(x,y), I need evaluate the
Marc Schwartz said the following on 9/24/2006 1:56 PM:
On Sun, 2006-09-24 at 11:31 -0700, Jonathan Greenberg wrote:
Another newbie question for you all:
In a function, say I have:
countme - function() {
for(i in 1:10) {
i
}
}
How do I get R to print i as it runs (e.g. By calling
Peter Lauren said the following on 9/27/2006 3:11 PM:
I would like to use readBin to read a binary data
file. Most of the data is 4-byte floating point but,
for some reason, only double precision appears to be
offered. I tried
fVariable=readBin(iFile,what=single());
and got 35.87879
Spencer Jones said the following on 9/28/2006 10:44 AM:
I am fitting a regression model with a bs term and then making predictions
based on the model. According to some info on the internet at
http://www.stat.auckland.ac.nz/~yee/smartpred/DummiesGuide.txt
there are some problems with using
Osman Al-Radi said the following on 10/5/2006 3:43 PM:
Hi,
for the data below:
time-c(rep(1:10,5))
y-time+rnorm(50,5,2)
subject-c(rep('a',10),rep('b',10),rep('c',10),rep('d',10),rep('e',10))
group-c(rep('A',30),rep('B',20))
df-data.frame(subject,group,time,y)
I'd like to produce a
Daniel E. Bunker said the following on 10/12/2006 11:48 AM:
Dear R users,
About a year ago Deepayan offered a suggestion to incorporate error bars
into a dotplot using the singer data as an example
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/63875.html.
When I try to utilize this
Yuval Sapir said the following on 10/12/2006 1:08 PM:
Hi,
I'm trying to perform a glm model on count data (poisson distribution of
the errors) where data are nested.
glmmodel-glm(y~x/z,poisson)
x and z are factors, z nested within x, y is count data.
In that point the R just stuck and not
Jeffrey Stratford said the following on 10/13/2006 9:28 AM:
Hi. I'm attempting to fit a logistic/binomial model so I can determine
the influence of landscape on the probability that a box gets used by a
bird. I've looked at a few sources (MASS text, Dalgaard, Fox and
google) and the
Søren Højsgaard wrote:
Dear all,
One of my students (whom I am trying to convince to use R) wants to get a fairly large SAS dataset into R (about 150mB). An obvious and simple thing she tried was to write the dataset as a .csv-file and then read that into R, but that takes forever (or something
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