] glm beta hypothesis testing
Davis, Jacob B. JBDavis at txfb-ins.com writes:
In summary.glm I'm trying to get a better feel for the z output. The
following lines can be found in the function
[snip]
digging through the function is good: debugging your way through
the function
I have recently fit a binomial link = logit model and I want to visually
see the estimated response across a specific covariate.
I can accomplish this by creating a function that extracts the betas
from the model then forms a linear combination with the classes I'm
interested in next pass the
If object is user defined is:
object$df.residual
the same thing as
df.residual(object)
This is my first time to encounter the $ sign in R, I'm new. I'm
reviewing summary.glm and in most cases it looks as though the $ is
used to extract some characteristic/property of the object,
In summary.glm I'm trying to get a better feel for the z output. The
following lines can be found in the function
1 if (p 0) {
2p1 - 1:p
3Qr - object$qr
4coef.p - object$coefficients[Qr$pivot[p1]]
5covmat.unscaled - chol2inv(Qr$qr[p1, p1, drop =
to help their self.
Patrick Burns showed me where S Poetry was, being a newbie I had no idea
what are where that was, now I do.
-Original Message-
From: Joerg van den Hoff [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 20, 2006 11:21 AM
To: Davis, Jacob B.
Cc: r-help@stat.math.ethz.ch
I have a vector that has 1,974 elements and each element is one of the
following (B, F, N, Y). How do I recreate that vector accept in the
place of N put 0 and in the place of B, F or Y put a 1?
Thanks,
Jacob
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