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On Thu, 20 Apr 2006, Manuel Gutierrez wrote:
Is it possible to include a factor in an nls
formula?
Yes. What do you intend by it? If you mean what it
would mean for a lm
formula, you need A[a] and starting values for A.
There's an example on p.219 of MASS4.
I've searched the help
Is it possible to include a factor in an nls formula?
I've searched the help pages without any luck so I
guess it is not feasible.
I've given it a few attempts without luck getting the
message:
+ not meaningful for factors in:
Ops.factor(independ^EE, a)
This is a toy example, my realworld case is
, Manuel
Gutierrez wrote:
Is it possible to include a factor in an nls
formula?
I've searched the help pages without any luck so I
guess it is not feasible.
I've given it a few attempts without luck getting
the
message:
+ not meaningful for factors in:
Ops.factor(independ^EE
: 0x88a076c
But I can not find what is form.
Any help, please.
Manuel
Manuel Gutierrez wrote:
The option se.fit in predict.nls is currently
ignored.
Is there any other function available to calculate
the
error in the predictions?
Thanks,
Manuel
The option se.fit in predict.nls is currently ignored.
Is there any other function available to calculate the
error in the predictions?
Thanks,
Manuel
__
LLama Gratis a cualquier PC del Mundo.
Llamadas a fijos y móviles desde 1
Are there any functions to do error propagation in R?
I have done a search with little success. Any
pointers to read about this topic are greatly
welcomed.
My specific problem is: I use a linear model (lm) to
predict the biomass of an individual in a population,
then I add up the biomass of all
Are there any functions to do error propagation in R?
I have done a search with little success. Any
pointers to read about this topic are greatly
welcomed.
My specific problem is: I use a linear model (lm) to
predict the biomass of an individual in a population,
then I add up the biomass of all
I have a linear model y~x1+x2 of some data where the
coefficient for
x1 is higher than I would have expected from theory
(0.7 vs 0.88)
I wondered whether this would be an artifact due to x1
and x2 being correlated despite that the variance
inflation factor is not too high (1.065):
I used
Thanks to all,
Yes, I meant a single test for both coefficients.
Peter's reply is what I wanted. I've tried with
linear.hypothesis but I must confess that with my
limited statistical experience and without the car
book at hand, the nomenclature for the function was a
bit difficult to understand
In a multiple linear regression with two independent
variables is there any function in R to test for the
coefficients being different than some given values?
Example:
x1-rnorm(100)
x2-rnorm(100)
y-3+0.6*x1+0.3*x2
lm(y~x1+x2)
Obtain a test for the coefficients for x1 being
different than 0.6 and
I am trying to understand how the SOM algorithm works
using library(class) SOM function.
I have a 1000*10 matrix and I want to be able to
summarize the different types of 10-element vectors.
In my real world case it is likely that most of the
1000 values are of one kind the rest of other (this is
I've a linux system with 2Gb of memory which is not
enough for reading a 446Mb netcdf file using ncdf:
library(ncdf)
ncold - open.ncdf(gridone.grd)
Error: cannot allocate vector of size 1822753 Kb
When I look at the free memory in my system I can see
that none of the Swap space is being used by
When I try to unlist a very large list, R is killed
without any other warning:
A-as.list(as.data.frame(matrix(1:21639744,nrow=3578,ncol=6048)))
with
AA-unlist(A)
or
AA-c(A,recursive=TRUE)
I get a
R terminado (killed)
and the end of the session.
I think I'll need to get more RAM (now 1Gb, any
I could not find any help pages on How to test many
objects for being of equal length
Something like identical for more than two objects?
x-1:6
y-1:10
z-3:5
## For two objects I can do:
identical(length(x),length(y))
## For more than two I currently can do:
I have an openoffice spreadsheet with a column of
character strings.
Some of them contain accents.
I want to read it in R so I have saved it as a csv
file using Western Europe (ISO-8859-1) character set
(the default, I've tried other sets but it doesn't
help).
R reads it fine with
of a
UTF-8 locale, which R
does not currently support and which some Linux
distros have made their
default. However, R does issue a warning -- so did
you get one?
On Thu, 25 Nov 2004, Manuel Gutierrez wrote:
I have an openoffice spreadsheet with a column of
character strings.
Some
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