Dear list members,
How can I replace the nested for loops at then end of the script
below with more efficient code?
# Begin script__
# Dichotomous scores for 100 respondents on 3 items with
# probabilities of a correct response = .6, .4, and .7,
You may be able to simplify it further, but just by replacing the whole
inner-most loop with
opt.mat2[k,j] - mean(x.mat[kt == x.mat[, nc], j])
the computation is instantaneous on my 1.6GHz Pentium M laptop (whereas your
code took just over 7 seconds).
HTH,
Andy
From: Haynes, Maurice
