Dear All:
I have a dataset like
A=c(0,12,34,5,6,0,4,5,6,0,12,3,4,8,7,0,4,3,5,0,...),I want to add a
column to this dataset, it must be in
B=c(1,1,1,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,5,..), How can I create B
based on the sequence of A. Appreciate.
Zheng
Lu
Sent: Tuesday, August 28, 2007 5:00 PM
To: r-help@stat.math.ethz.ch
Subject: [R] data manipulation help
Dear All:
I have a dataset like
A=c(0,12,34,5,6,0,4,5,6,0,12,3,4,8,7,0,4,3,5,0,...),I want to add a
column to this dataset, it must be in
B=c(1,1,1,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,5
On Tue, 28 Aug 2007, Zheng Lu wrote:
Dear All:
I have a dataset like
A=c(0,12,34,5,6,0,4,5,6,0,12,3,4,8,7,0,4,3,5,0,...),I want to add a
column to this dataset, it must be in
B=c(1,1,1,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,5,..), How can I create B
based on the sequence of A. Appreciate.
...is this what you're looking for?
donedat - subset(data,ID 6000 | ID = 7000)
findat - donedat[-unique(rapply(donedat,function(x)
which( x 0 ))),,drop=FALSE]
the second line looks through each column, and finds the indices of negative
values - rapply() returns
Dear Friends,
I have data set with around 220,000 rows and 17 columns. One of the columns is
an id variable which is grouped from 1000 through 9000. I need to perform the
following operations.
1) Remove all the observations with id's between 6000 and 6999
I tried using this method.
remdat1
On Apr 17, 2007, at 8:03 PM, Anup Nandialath wrote:
Dear Friends,
I have data set with around 220,000 rows and 17 columns. One of the
columns is an id variable which is grouped from 1000 through 9000.
I need to perform the following operations.
1) Remove all the observations with id's
R Users,
I have written a small simulation model in R which outputs a datafile
consisting of ending population sizes for each simulation run (year). The data
(see short data example below) is labeled by NUM (simulation run), sim (year)
and N (yearly count). After searching the help files and
Does this start to do what you want?
x - NUM sim N
+ 1 1 466
+ 1 2 450
+ 1 3 473
+ 1 4 531
+ 1 5 515
+ 1 6 502
+ 1 7 471
+ 1 8 460
+ 1 9 458
+ 1 10 434
+ 2 1 289
+ 2 2 356
+ 2 3 387
+ 2 4 440
+ 2 5 457
+ 2 6 466
+ 2 7 467
+ 2 8 449
+ 2 9 387
+ 2 10 394
+ 3 1 367
+ 3 2 400
+ 3 3 476
+
Federico Calboli wrote:
Hi All,
Is there some document/manual about data manipulation within R that I
could use as a reference (obviously, aside the R manuals)?
The reason I am asking is that I have a number of data frames/matrices
containg genetic data. The data is in a character form,
Hi All,
Is there some document/manual about data manipulation within R that I
could use as a reference (obviously, aside the R manuals)?
The reason I am asking is that I have a number of data frames/matrices
containg genetic data. The data is in a character form, as in:
V1 V2 V3 V4 V5
1 AA
On Thursday May 4 2006 10:20, Federico Calboli wrote:
The reason I am asking is that I have a number of data frames/matrices
containg genetic data. The data is in a character form, as in:
Take a look at the Bioconductor project: Bioconductor is an open source and
open development software
Marc Bernard bernarduse1 at yahoo.fr writes:
I would be grateful if you can help me. My problem is the following:
I have a data set like:
ID time X1 X2
11 x111 x211
12 x112 x212
where X1 and X2 are 2 covariates and time is the time
Dear All,
I would be grateful if you can help me. My problem is the following:
I have a data set like:
ID time X1 X2
11 x111 x211
12 x112 x212
21 x121 x221
22 x122 x222
23 x123 x223
where
Hi,
This may not be the best solution, but at least it's
easy to see what i'm doing, assume that your data set
is called data:
# remove the 4th column
data1 = data[,-4]
# remove the 3rd column
data2 = data[,-3]
# use cbind to add an extra column with only X1
#elements
data1 = cbind(data1,
Marc Bernard [EMAIL PROTECTED] wrote:
Dear All,
I would be grateful if you can help me. My problem is the following:
I have a data set like:
ID time X1 X2
11 x111 x211
12 x112 x212
21 x121 x221
22 x122
This is what reshape() does.
-thomas
On Thu, 8 Sep 2005, Marc Bernard wrote:
Dear All,
I would be grateful if you can help me. My problem is the following:
I have a data set like:
ID time X1 X2
11 x111 x211
12 x112 x212
21
Also see Hadley Wickham's reshape package for more bells whistles.
--
HTH!
Jim Porzak
Loyalty Matrix Inc.
On 9/8/05, Thomas Lumley [EMAIL PROTECTED] wrote:
This is what reshape() does.
-thomas
On Thu, 8 Sep 2005, Marc Bernard wrote:
Dear All,
I would be grateful if
I am sure all this work but If you want exaclty the output to be the way
you mentioned do this
temp-read.table(yourfile, as.is=T, header=T)
temp1-temp[, 1:3]
temp2-temp[, c(1,2,4)]
colnames(temp1)[3]-X
colnames(temp2)[3]-X
temp3-merge(temp1, temp2, all=T)
temp3$type-toupper(substr(temp3$X, 1,2))
roberto munguia munguiar at posgrado.ecologia.edu.mx writes:
I have a dataframe with 468 individuals (rows) that I captured at least once
during 28 visits (columns), it looks like:
mortality[1:10,]
11 0 0 0 1 1
1
Hellow everybody,
I have a dataframe with 468 individuals (rows) that I captured at least once
during 28 visits (columns), it looks like:
mortality[1:10,]
X18.10.2004 X20.10.2004 X22.10.2004 X24.10.2004 X26.10.2004 X28.10.2004
X30.10.2004 X01.11.2004 X03.11.2004 X07.11.2004
1
Hello,
may I ask a further question?
I have realized that data -
matrix(scan(file-name), ncol=29) will read the data differently than I
thought, i.e., (4,1) is the first column, (17,1) is the second column, and
(1,1) is the third and so on by this code - please see the data below.
Therefore,
You just need to try harder in reading the documentation. Try:
data - matrix(scan(file-name), ncol=29, byrow=TRUE)
Andy
From: Yoko Nakajima
Hello,
may I ask a further question?
I have realized that data -
matrix(scan(file-name), ncol=29) will read the data
differently than I
Hello,
my question is about the data handling.
I have a data set that is lined as:
4 1 17 1 1
-5.1536 -0.1668 -2.3412 -0.5062 0.9621 0.3640 0.3678 -0.5081 -0.2227
0.8142 -0.0389 -0.0445 -0.0578 -0.1175 -0.1232 0.8673 -0.1033 -0.0796
-0.0341 -0.1716 -0.1801 -0.7014 0.6578 0.5611
4 1 17
: Wednesday, April 13, 2005 7:56 PM
To: r-help@stat.math.ethz.ch
Subject: [R] data manipulation
Hello,
my question is about the data handling.
I have a data set that is lined as:
4 1 17 1 1
-5.1536 -0.1668 -2.3412 -0.5062 0.9621 0.3640 0.3678
-0.5081 -0.2227
0.8142 -0.0389
On Wed, 2005-04-13 at 20:56 -0400, Yoko Nakajima wrote:
Hello,
my question is about the data handling.
I have a data set that is lined as:
4 1 17 1 1
-5.1536 -0.1668 -2.3412 -0.5062 0.9621 0.3640 0.3678 -0.5081
-0.2227
0.8142 -0.0389 -0.0445 -0.0578 -0.1175 -0.1232 0.8673 -0.1033
thanks a lot for the information, reshape did the job
datars -reshape(data, timevar=TERRCODE, idvar=BID, direction=wide)
greetings
helli
BID TERRCODEANMCODE
200310413120660 22 0
200310413120660 273 0
200310413120660 280 0
200310413120660 467 0
200310413120660 468
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Hi,
Not sure if I am making a simple problem complex but still here
we go:
I have a data frame with four columns say, X1 X2 X3 and X4. I
want to break X4 into deciles and for each deciles obtained, I want to
see corresponding elements of X1.
Ideally, the output should be
Hi,
see ? quantile to obtain deciles of variable X1
see ? cut to divide the range of 'x' into intervals
and codes the values in 'x' according to which
interval they fall.
se ? table to use the cross-classifying factors to
build a contingency table of the counts at each
combination of factor
Try this. The function takes a vector of dates of the form -mm and produces a new
character vector of dates of the same form except the
output date is the beginning of the 6 month period in which the input date lies. The
6 month intervals are measured from the minimum date.
Sorry but there was an error in the seq statement. Here it is again.
date.grouping - function(d) {
# for ea date in d calculate date beginning 6 month period which contains it
mat - matrix(as.numeric(unlist(strsplit(as.character(d),-))),nr=2)
f - function(x) do.call( ISOdate, as.list(x) )
And here is a simplification I just noticed:
date.grouping - function(d) {
# for ea date in d calculate date beginning 6 month period which contains it
POSIXct.dates - as.POSIXct(paste(as.character(d),01,sep=-))
breaks - c(seq(from=min(POSIXct.dates), to=max(POSIXct.dates), by=6 mo), Inf)
Hi,
I am new to R, coming from a few years using Stata. I've been twisting my
brain and checking several R and S references over the last few days to
try to solve this data management problem: I have a data set with a unique
patient identifier that is repeated along multiple rows, a variable
Ricardo Pietrobon [EMAIL PROTECTED] writes:
IDdatecost
1 2001-01 200.00
1 2001-01 123.94
1 2001-03 100.23
1 2001-04 150.34
2 2001-03 296.34
2 2002-05 156.36
I would like to obtain the median costs and boxplots
Dear All,
I would like to ask you how to accomplish a little tricky data
manipulation. I have a large dataset, looking something like:
templinecagenumber
18 18 1 6678.63
18 18 1 7774.458
18 18 1 7845.902
18 18 1 9483.578
Have you considered aggregate [documented in help(aggregate) or
www.r-project.org - search - R site search or Venables and Ripley,
Modern Applied Statistics with S]?
hope this helps. spencer graves
Federico Calboli wrote:
Dear All,
I would like to ask you how to accomplish a little tricky
x - read.table(file(clipboard), header=T)
# add an extra field to define groups of 5 sequential rows
x[,code] - rep(seq(len=nrow(x)/5), each=5)
x
temp line cage number code
118 181 6678.6301
218 181 7774.4581
318 181 7845.9021
418 181
On Fri, 14 Feb 2003 [EMAIL PROTECTED] wrote:
On Thu, 13 Feb 2003, kjetil brinchmann halvorsen wrote:
On 13 Feb 2003 at 17:09, Jason Bond wrote:
case switch
[R-core : switch should be better
Hello,
I'm a recovering xlispstat user, and am trying to become a good R
user. I've looked around on the CRAN doc website and have found quite a
few sets of documentation with various level of data manipulation function
descriptions (of what I've seen, most relatively low levels), and many
On 13 Feb 2003 at 17:09, Jason Bond wrote:
As lisp-stat user, I tried to compile a short dictionary within your
answer below:
Hello,
I'm a recovering xlispstat user, and am trying to become a good R
user. I've looked around on the CRAN doc website and have found quite a
few sets of
On Thu, 13 Feb 2003, kjetil brinchmann halvorsen wrote:
On 13 Feb 2003 at 17:09, Jason Bond wrote:
case switch
[R-core : switch should be better
announced. It is for
I am interested in building a model with a subset of data from a column.
The first 6 lines of my data look like this:
QUAD YEAR SITE TREAT HERB TILL PLANT SEED Kweed
1 A4 2002s 1NN NN 55.00
2A10 2002s 1NN NN 60.00
3 B2 2002
You might want to try subsetting the data frame first, and then fit the
model. Something like
knap.sub - knap[c(41:60,81:100,101:120,121:140), ]
knap.fit1 - lm(Kweed ~ TREAT, data = knap.sub)
might work for you.
-roger
___
UCLA Department of Statistics
[EMAIL
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