let me amend my previous message to remove a silly mistake:
I have a (non-normal) distribution S that is a mixture of two normal
distributions C and C-bar. I need to find the percentage of the area
of S that both C and C-bar occupy.
Thanks again,
Alan Gibson
On 5/1/07, Leeds, Mark (IED) [EMAIL PROTECTED] wrote:
What do you mean by a normal distribution made up of to normal
distributions ? A mixture of two
Normals with different variances doesn't result in a normal distribution
so I'm not sure what you
Nean but maybe someone else does. No offense intended but, if noone
replies,
That means that noone else understood either.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Alan Gibson
Sent: Tuesday, May 01, 2007 8:02 PM
To: R-help@stat.math.ethz.ch
Subject: [R] Percentage area of a distribution
It seems like this should be pretty straight forward, but for some
reason the answer escapes me.
I have a normal distribution S made up of two normal distributions C and
C-bar. I need to find the percentage of the area of S that both C and
C-bar occupy.
Any suggestions?
Thanks in advance,
Alan Gibson
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