Hi.
I am using R 2.3.1 on WIndows XP, and I am having trouble with the rank
function in the presence of numerical NA data. I want the NA's all to get
the same rank, but they don't. Here is an example from my session:
ct_align_rets_f2$liq[6851:6859]
[1] 115396 NA 362595 NA 242986
-help@stat.math.ethz.ch
Date sent: Thu, 11 Jan 2007 18:29:16 -0500
Subject:[R] rank function and NA in 2.3.1
Hi.
I am using R 2.3.1 on WIndows XP, and I am having trouble with the
rank function in the presence of numerical NA data. I want the NA's
all to get
y-round(c(0.68,0.95,b,c,d),2)
rank(y)
[1] 3.5 5.0 1.0 2.0 3.5
On 10/10/06, Li Zhang [EMAIL PROTECTED] wrote:
Does anyone know why the two rank functions gives
different results? I need to use the rank function in
a for loop, so the sequence to be ranked is given
values in the form of part
Because y[1] and y[5] are not the same in Part1 but are in Part2:
# using y from Part1
y[5] - y[1]
[1] 1.110223e-16
You could round your numbers to 2 digits, say:
rank(round(100*y)) # y is from Part1
[1] 3.5 5.0 1.0 2.0 3.5
On 10/10/06, Li Zhang [EMAIL PROTECTED] wrote:
Does anyone know
On Tue, 10 Oct 2006, Gabor Grothendieck wrote:
Because y[1] and y[5] are not the same in Part1 but are in Part2:
# using y from Part1
y[5] - y[1]
[1] 1.110223e-16
Yes, this is FAQ 7.31: Why doesn't R think these numbers are equal?
i-1.94
d-2.62-i
print(0.68, digits=16)
[1] 0.68
Li Zhang wrote:
Does anyone know why the two rank functions gives
different results? I need to use the rank function in
a for loop, so the sequence to be ranked is given
values in the form of part (1). How can I use
assignment like in part (1) to get correct ranks as in
part (2)?
Thank
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Hello! I have a question on rank function that i#039;m working on now.
Even though my English i not good, I hope you understand what i#039;m asking for. It
is a program that i
