Re: [R] Remove empty list from list - remove only one row and make as matrix

2006-08-29 Thread Muhammad Subianto

Dear all,
Dimitris, thanks for your great help and quick response.

Best, Muhammad Subianto


 > dff[sapply(dff, is.matrix)]
[[1]]
  [,1] [,2] [,3] [,4] [,5]
[1,]16   11   161
[2,]49   14   191
[3,]5   10   15   201

[[2]]
  [,1] [,2] [,3] [,4] [,5]
[1,]38   13   18   -1
[2,]5   10   15   20   -1

 > lapply(dff, function(x) if(!is.matrix(x)) rbind(x) else x)
[[1]]
  [,1] [,2] [,3] [,4] [,5]
[1,]16   11   161
[2,]49   14   191
[3,]5   10   15   201

[[2]]
   [,1] [,2] [,3] [,4] [,5]
x16   11   161

[[3]]
  [,1] [,2] [,3] [,4] [,5]
[1,]38   13   18   -1
[2,]5   10   15   20   -1

 >

On this day 29/08/2006 13:34, Dimitris Rizopoulos wrote:
> try the following:
> 
> # a
> dff[sapply(dff, is.matrix)]
> 
> # b
> lapply(dff, function(x) if(!is.matrix(x)) rbind(x) else x)
> 
> 
> I hope it helps.
> 
> Best,
> Dimitris
> 
> 
> Dimitris Rizopoulos
> Ph.D. Student
> Biostatistical Centre
> School of Public Health
> Catholic University of Leuven
> 
> Address: Kapucijnenvoer 35, Leuven, Belgium
> Tel: +32/(0)16/336899
> Fax: +32/(0)16/337015
> Web: http://med.kuleuven.be/biostat/
>  http://www.student.kuleuven.be/~m0390867/dimitris.htm
> 
> 
> - Original Message - 
> From: "Muhammad Subianto" <[EMAIL PROTECTED]>
> To: 
> Sent: Tuesday, August 29, 2006 1:22 PM
> Subject: Re: [R] Remove empty list from list - remove only one row and 
> make as matrix
> 
> 
>> Dear all,
>> After I work around, I found in my list of data with only one row 
>> which
>> need to remove or make it as matrix.
>> Here I write again my other toy example:
>> x <- list(matrix(1:20, 5, 4),matrix(1:20, 5, 4),matrix(1:20, 5,
>> 4),matrix(1:20, 5, 4),matrix(1:20, 5, 4))
>> y <- list(c(1, -1, -1, 1, 1),c(1, -1, -1, -1, -1),c(1, 1, 1, 1, 
>> 1),c(1,
>> 1, -1, 1, -1),c(-1, -1, -1, -1, -1))
>> ## Thanks to Gabor Grothendieck for this trick.
>> ## SIMPLIFY? SIMPLIFY >< simplify
>> xy.list <- mapply(cbind, x, y, SIMPLIFY=FALSE)
>>
>> point.class <-
>> t(cbind(c(10,20,15,4,-1),c(21,10,15,34,-1),c(11,13,6,3,1),c(7,5,5,2,1),c(8,9,5,12,-1)))
>> class.diffsame <- points.neighb(as.matrix(point.class), xy.list, 5)
>> pd.class <- points.diff(class.diffsame,xy.list)
>>
>> nc.test <- vector("list",length(pd.class))
>> for (i in 1:length(pd.class)) {
>>  nc.test[[i]] <- pd.class[[i]]$point.diff
>> }
>> nc.test
>>
>> # delete null/empty entries in a list
>> dff <- delete.NULLs(nc.test)
>> dff; str(dff)
>>> dff
>> [[1]]
>>  [,1] [,2] [,3] [,4] [,5]
>> [1,]16   11   161
>> [2,]49   14   191
>> [3,]5   10   15   201
>>
>> [[2]]
>> [1]  1  6 11 16  1
>>
>> [[3]]
>>  [,1] [,2] [,3] [,4] [,5]
>> [1,]38   13   18   -1
>> [2,]5   10   15   20   -1
>>
>> lapply(dff, nrow)
>>> lapply(dff, nrow)
>> [[1]]
>> [1] 3
>>
>> [[2]]
>> NULL
>>
>> [[3]]
>> [1] 2
>>
>> #I can use
>> #dff[unlist(lapply(dff, nrow) == 1)] #2,3, etc
>>
>> I have two questions here:
>> a. I need to remove dff[[2]]
>> b. How to make it as matrix (in list). I mean the result something 
>> like
>>
>> [[1]]
>>  [,1] [,2] [,3] [,4] [,5]
>> [1,]16   11   161
>> [2,]49   14   191
>> [3,]5   10   15   201
>>
>> [[2]]
>>  [,1] [,2] [,3] [,4] [,5]
>> [1]1611   161
>>
>> [[3]]
>>  [,1] [,2] [,3] [,4] [,5]
>> [1,]38   13   18   -1
>> [2,]5   10   15   20   -1
>>
>>
>> Best, Muhammad Subianto
>>
>>
>> points.neighb <- function(p.class, list.nc, class.col) {
>>ntuples <- nrow(p.class)
>>instvec <- vector("list",length=ntuples)
>>for (i in 1:ntuples) {
>> # Thanks to Petr Pikal for this trick
>> instvec[[i]]$class.diff <- (p.class[i,class.col] -
>> list.nc[[i]][,class.col])!=0
>> instvec[[i]]$class.same <- (p.class[i,class.col] -
>> list.nc[[i]][,class.col])==0
>>}
>>instvec
>> }
>>
>> points.diff <- function(p.class, list.nc) {
>>ntuples <- length(list.nc)
>>instvec <- vector("list",ntuples)
>>for (i in 1:ntuples) {
>> instvec[[i]]$point.diff <- 
>> list.nc[[i]][p.class[[i]]$class.diff,]
>> instvec[[i]]$point.same <- 
>> list.nc[[i]][p.class[[i]]$class.same,]
>>}
>>instvec
>> }
>>
>> # Thanks to Jim Holtman for this trick
>> delete.NULLs  <-  function(x.list){
>> x.list[unlist(lapply(x.list, length) != 0)]
>> }
>>

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Re: [R] Remove empty list from list - remove only one row and make as matrix

2006-08-29 Thread Dimitris Rizopoulos
try the following:

# a
dff[sapply(dff, is.matrix)]

# b
lapply(dff, function(x) if(!is.matrix(x)) rbind(x) else x)


I hope it helps.

Best,
Dimitris


Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
 http://www.student.kuleuven.be/~m0390867/dimitris.htm


- Original Message - 
From: "Muhammad Subianto" <[EMAIL PROTECTED]>
To: 
Sent: Tuesday, August 29, 2006 1:22 PM
Subject: Re: [R] Remove empty list from list - remove only one row and 
make as matrix


> Dear all,
> After I work around, I found in my list of data with only one row 
> which
> need to remove or make it as matrix.
> Here I write again my other toy example:
> x <- list(matrix(1:20, 5, 4),matrix(1:20, 5, 4),matrix(1:20, 5,
> 4),matrix(1:20, 5, 4),matrix(1:20, 5, 4))
> y <- list(c(1, -1, -1, 1, 1),c(1, -1, -1, -1, -1),c(1, 1, 1, 1, 
> 1),c(1,
> 1, -1, 1, -1),c(-1, -1, -1, -1, -1))
> ## Thanks to Gabor Grothendieck for this trick.
> ## SIMPLIFY? SIMPLIFY >< simplify
> xy.list <- mapply(cbind, x, y, SIMPLIFY=FALSE)
>
> point.class <-
> t(cbind(c(10,20,15,4,-1),c(21,10,15,34,-1),c(11,13,6,3,1),c(7,5,5,2,1),c(8,9,5,12,-1)))
> class.diffsame <- points.neighb(as.matrix(point.class), xy.list, 5)
> pd.class <- points.diff(class.diffsame,xy.list)
>
> nc.test <- vector("list",length(pd.class))
> for (i in 1:length(pd.class)) {
>  nc.test[[i]] <- pd.class[[i]]$point.diff
> }
> nc.test
>
> # delete null/empty entries in a list
> dff <- delete.NULLs(nc.test)
> dff; str(dff)
> > dff
> [[1]]
>  [,1] [,2] [,3] [,4] [,5]
> [1,]16   11   161
> [2,]49   14   191
> [3,]5   10   15   201
>
> [[2]]
> [1]  1  6 11 16  1
>
> [[3]]
>  [,1] [,2] [,3] [,4] [,5]
> [1,]38   13   18   -1
> [2,]5   10   15   20   -1
>
> >
>
> lapply(dff, nrow)
> > lapply(dff, nrow)
> [[1]]
> [1] 3
>
> [[2]]
> NULL
>
> [[3]]
> [1] 2
>
> >
>
> #I can use
> #dff[unlist(lapply(dff, nrow) == 1)] #2,3, etc
>
> I have two questions here:
> a. I need to remove dff[[2]]
> b. How to make it as matrix (in list). I mean the result something 
> like
>
> [[1]]
>  [,1] [,2] [,3] [,4] [,5]
> [1,]16   11   161
> [2,]49   14   191
> [3,]5   10   15   201
>
> [[2]]
>  [,1] [,2] [,3] [,4] [,5]
> [1]1611   161
>
> [[3]]
>  [,1] [,2] [,3] [,4] [,5]
> [1,]38   13   18   -1
> [2,]5   10   15   20   -1
>
>
> Best, Muhammad Subianto
>
>
> points.neighb <- function(p.class, list.nc, class.col) {
>ntuples <- nrow(p.class)
>instvec <- vector("list",length=ntuples)
>for (i in 1:ntuples) {
> # Thanks to Petr Pikal for this trick
> instvec[[i]]$class.diff <- (p.class[i,class.col] -
> list.nc[[i]][,class.col])!=0
> instvec[[i]]$class.same <- (p.class[i,class.col] -
> list.nc[[i]][,class.col])==0
>}
>instvec
> }
>
> points.diff <- function(p.class, list.nc) {
>ntuples <- length(list.nc)
>instvec <- vector("list",ntuples)
>for (i in 1:ntuples) {
> instvec[[i]]$point.diff <- 
> list.nc[[i]][p.class[[i]]$class.diff,]
> instvec[[i]]$point.same <- 
> list.nc[[i]][p.class[[i]]$class.same,]
>}
>instvec
> }
>
> # Thanks to Jim Holtman for this trick
> delete.NULLs  <-  function(x.list){
> x.list[unlist(lapply(x.list, length) != 0)]
> }
>
> __
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide 
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 


Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm

__
R-help@stat.math.ethz.ch mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Remove empty list from list - remove only one row and make as matrix

2006-08-29 Thread Muhammad Subianto
Dear all,
After I work around, I found in my list of data with only one row which 
need to remove or make it as matrix.
Here I write again my other toy example:
x <- list(matrix(1:20, 5, 4),matrix(1:20, 5, 4),matrix(1:20, 5, 
4),matrix(1:20, 5, 4),matrix(1:20, 5, 4))
y <- list(c(1, -1, -1, 1, 1),c(1, -1, -1, -1, -1),c(1, 1, 1, 1, 1),c(1, 
1, -1, 1, -1),c(-1, -1, -1, -1, -1))
## Thanks to Gabor Grothendieck for this trick.
## SIMPLIFY? SIMPLIFY >< simplify
xy.list <- mapply(cbind, x, y, SIMPLIFY=FALSE)

point.class <- 
t(cbind(c(10,20,15,4,-1),c(21,10,15,34,-1),c(11,13,6,3,1),c(7,5,5,2,1),c(8,9,5,12,-1)))
class.diffsame <- points.neighb(as.matrix(point.class), xy.list, 5)
pd.class <- points.diff(class.diffsame,xy.list)

nc.test <- vector("list",length(pd.class))
for (i in 1:length(pd.class)) {
  nc.test[[i]] <- pd.class[[i]]$point.diff
}
nc.test

# delete null/empty entries in a list
dff <- delete.NULLs(nc.test)
dff; str(dff)
 > dff
[[1]]
  [,1] [,2] [,3] [,4] [,5]
[1,]16   11   161
[2,]49   14   191
[3,]5   10   15   201

[[2]]
[1]  1  6 11 16  1

[[3]]
  [,1] [,2] [,3] [,4] [,5]
[1,]38   13   18   -1
[2,]5   10   15   20   -1

 >

lapply(dff, nrow)
 > lapply(dff, nrow)
[[1]]
[1] 3

[[2]]
NULL

[[3]]
[1] 2

 >

#I can use
#dff[unlist(lapply(dff, nrow) == 1)] #2,3, etc

I have two questions here:
a. I need to remove dff[[2]]
b. How to make it as matrix (in list). I mean the result something like

[[1]]
  [,1] [,2] [,3] [,4] [,5]
[1,]16   11   161
[2,]49   14   191
[3,]5   10   15   201

[[2]]
  [,1] [,2] [,3] [,4] [,5]
[1]1611   161

[[3]]
  [,1] [,2] [,3] [,4] [,5]
[1,]38   13   18   -1
[2,]5   10   15   20   -1


Best, Muhammad Subianto


points.neighb <- function(p.class, list.nc, class.col) {
ntuples <- nrow(p.class)
instvec <- vector("list",length=ntuples)
for (i in 1:ntuples) {
 # Thanks to Petr Pikal for this trick
 instvec[[i]]$class.diff <- (p.class[i,class.col] - 
list.nc[[i]][,class.col])!=0
 instvec[[i]]$class.same <- (p.class[i,class.col] - 
list.nc[[i]][,class.col])==0
}
instvec
}

points.diff <- function(p.class, list.nc) {
ntuples <- length(list.nc)
instvec <- vector("list",ntuples)
for (i in 1:ntuples) {
 instvec[[i]]$point.diff <- list.nc[[i]][p.class[[i]]$class.diff,]
 instvec[[i]]$point.same <- list.nc[[i]][p.class[[i]]$class.same,]
}
instvec
}

# Thanks to Jim Holtman for this trick
delete.NULLs  <-  function(x.list){
 x.list[unlist(lapply(x.list, length) != 0)]
}

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.