Re: [R] Seeking help with a loop

2005-08-03 Thread Tony Plate
x - data.frame(q33a=3:4,q33b=5:6,q35a=1:2,q35b=2:1) y - list() for (i in grep(q33, colnames(x), value=TRUE)) +y[[sub(q33,,i)]] - ifelse(x[[sub(q33,q35,i)]]==1, x[[i]], NA) as.data.frame(y) a b 1 3 NA 2 NA 6 # if you really want to create new variables rather # than have them

Re: [R] Seeking help with a loop

2005-08-03 Thread Jean Eid
You can do the following without resorting to a hard coded loop sapply( paste(q35, letters[1:grep(r, letters)], sep=), function(x) ifelse(temp[, x]%in%1,temp[, sub(5, 3, x)],NA) as the following example shows temp - matrix(sample(c(0,1), 360, replace=T), nrow=10) colnames(temp) - c(paste(q33,