Hello,
is there a way to use the aggregate function to calculate monthly mean
in case i have one row in data frame that holds the date like
-mm-dd? i know that it works for daily means. i also like to do it
for monthly and yearly means. maybe there is something like aggregate(x,
try this. The first group of lines recreates your data frame, DF, and
the last line is the aggregate:
Input - DateTimez
2006-01-01 21:00 6,2
2006-01-01 22:00 5,7
2006-01-01 23:00 3,2
2006-01-02 00:00 7,8
2006-01-02 01:00 6,8
2006-01-02
it works. thanks a lot.
Gabor Grothendieck wrote:
try this. The first group of lines recreates your data frame, DF, and
the last line is the aggregate:
Input - DateTimez
2006-01-01 21:00 6,2
2006-01-01 22:00 5,7
2006-01-01 23:00 3,2
2006-01-02
If monthly should aggregate per -mm combination, you could try
something like
aggregate(x$z,list(cut(as.Date(x$Date),m)),mean)
for monthly aggregation and
aggregate(x$z,list(cut(as.Date(x$Date),y)),mean)
for yearly means.
If monthly aggregation should aggregate over different years
Dear r-help reader,
I have some problems with the aggregate function.
My datframe looks like
frame
Day Time V1 V2
1 M0 3 NA
2 M0 4 NA
3 M0 5 2
4 M1 NA 4
5 M1 10 6
6 T0 4 45
7 T1 4 3
8 T1 3 2
9 T1 6 1
I used the aggegate
Frank [EMAIL PROTECTED] writes:
aggregate(frame[,c(-1)],list(frame$Day,frame$Time),mean)
My problem is now that I do not obtain a 'mean' for Day=M/Time=0 and
Day=M/Time=1,
because aggregate ignores all values for a grouping variable if NA
occurs.
No. But mean() will give an NA
aggregate(frame[,c(-1)],list(frame$Day,frame$Time),mean, na.rm=T)
2006/10/1, Frank [EMAIL PROTECTED]:
Dear r-help reader,
I have some problems with the aggregate function.
My datframe looks like
frame
Day Time V1 V2
1 M0 3 NA
2 M0 4 NA
3 M0 5 2
4 M1 NA
See ?mean and note the na.rm= argument:
aggregate(frame[-1], frame[1:2], mean, na.rm = TRUE)
On 10/1/06, Frank [EMAIL PROTECTED] wrote:
Dear r-help reader,
I have some problems with the aggregate function.
My datframe looks like
frame
Day Time V1 V2
1 M0 3 NA
2 M0 4
Nice trick, thx...
Stéphane.
On Wed, 2006-03-29 at 11:17 -0500, jim holtman wrote:
try 'by':
x
S_id AF_Class count... R_gc_percent S_length
5 82644971 30 0.4835678
6 826449737 0.4835678
8 82645541 31
Dear R users,
I have some trouble with the aggregate function. Here are my data
daf
S_id AF_Class count... R_gc_percent S_length
5 82644971 30 0.4835678
6 826449737 0.4835678
8 82645541 31 0.5138894
9
try 'by':
x
S_id AF_Class count... R_gc_percent S_length
5 82644971 30 0.4835678
6 826449737 0.4835678
8 82645541 31 0.5138894
9 82645542 11 0.5138894
10 826455431
Hi all,
I have the folowing frame(there are more columns than shown),
1 2 34 5
Year Total TusWhi Norw
1994 1.00 1830 0 355
1995 1.00 0 00
1995 1.00 0
Hi,
# x ... your frame
attach(x)
sum(Total[Year==1997 Tus 0])
I hope this helps
Best,
Matthias
-Ursprüngliche Nachricht-
Von: Luis Rideau Cruz [mailto:[EMAIL PROTECTED]
Gesendet: Montag, 26. Juli 2004 14:52
An: [EMAIL PROTECTED]
Betreff: [R] aggregate function
Hi all,
I
Hi,
# x ... your frame
attach(x)
sum(Total[Year==1997 Tus 0])
I hope this helps
Best,
Matthias Templ
-Ursprüngliche Nachricht-
Von: Luis Rideau Cruz [mailto:[EMAIL PROTECTED]
Gesendet: Montag, 26. Juli 2004 14:52
An: [EMAIL PROTECTED]
Betreff: [R] aggregate function
I would try something like:
lapply(frame[3:5], function(i) tapply(frame$Total[i0], frame$Year[i0],
sum))
$Tus
1994 1995 1997 1999
1121
$Whi
1995 1997 1999
1.00 4.00 2.04
$Norw
1994 1995 1997 1998 1999
11512
HTH,
Andy
From: Luis Rideau Cruz
Hi
[Sorry if this gets posted twice. I have been having some
problems with gmane posting.]
We can use rowsum like this:
rowsum(frame$Total * (frame[,3:5]0), frame$Year)
Tus Whi Norw
1994 1 0.00 1
1995 1 1.00 1
1997 2 4.00 5
1998 0 0.00 1
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