I don't know if its faster but you could try timing this to find out:
r$seid - merge(h, r, by = cid)[,2]
On 8/27/05, Omar Lakkis [EMAIL PROTECTED] wrote:
I have the following two mapping data frames (r) and (h). I want to
fill teh value of r$seid with the value of r$seid where r$cid==h$cid.
I can do it with sapply as such:
r$seid = sapply(r$cid, function(cid) h[h$cid==cid,]$seid)
Is ther a better (faster) way to do this?
r - data.frame(seid=NA, cid= c(2181,2221,))
r
seid cid
1 NA2181
2 NA2221
3 NA
h - data.frame(seid= c(5598,5609,4931,5611,8123,8122), cid=
c(2219,,2181,2190,2817,2221))
h
cid seid
1 5598 2219
2 5609
3 4931 2181
4 5611 2190
5 8123 2817
6 8122 2221
to get the desired result of:
r
seid cid
1 4931 2181
2 8122 2221
3 5609
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