Hello,
I've encountered the need to cut some chron objects of the form:
R mychron - chron(sort(runif(10, 0, 10)))
R mychron
[1] (01/01/70 16:36:20) (01/02/70 00:08:46) (01/03/70 16:54:49)
[4] (01/04/70 06:45:00) (01/07/70 06:21:24) (01/07/70 18:28:44)
[7] (01/08/70 00:47:05) (01/08/70
Assuming, as in your post:
set.seed(123)
mychron - chron(sort(runif(10, 0, 10)))
breaks - quantile(mychron)
# is one of these adequate?
cut(mychron, breaks)
cut(unclass(mychron), unclass(breaks), lab = FALSE)
On 8/2/05, Sebastian Luque [EMAIL PROTECTED] wrote:
Hello,
I've encountered
Gabor Grothendieck [EMAIL PROTECTED] wrote:
Assuming, as in your post:
set.seed(123)
mychron - chron(sort(runif(10, 0, 10)))
breaks - quantile(mychron)
# is one of these adequate?
cut(mychron, breaks)
cut(unclass(mychron), unclass(breaks), lab = FALSE)
Thank you Gabor, that showed me I
How about the following:
set.seed(123)
mychron - chron(sort(runif(10, 0, 10)))
(breaks - chron(pretty(quantile(mychron
[1] 01/01/70 01/03/70 01/05/70 01/07/70 01/09/70 01/11/70
spencer graves
Sebastian Luque wrote:
Gabor Grothendieck [EMAIL PROTECTED] wrote:
Assuming, as in your
Spencer Graves [EMAIL PROTECTED] wrote:
How about the following:
set.seed(123)
mychron - chron(sort(runif(10, 0, 10)))
(breaks - chron(pretty(quantile(mychron
[1] 01/01/70 01/03/70 01/05/70 01/07/70 01/09/70 01/11/70
I was looking for a way to cut it into specified units of time, rather
