[R] looking for a cleaner way to do something

2006-10-17 Thread Leeds, Mark \(IED\)
I have two numeric vectors each of length 17 and each is named the exact
same way.
 
so 
obsnum p  m pppmp . dot dot dot.. 
temp1is141752 63   85
 
 obsnum p  m pppmp . dot dot dot.. 
temp2 is   1213 4150   97
 
what i want to have is a resultant matrix with 2 rows and 16 columns
where the 16 columns are the 2:17 columns divided by the respective
first element in each vector.
( so 52, 63 and 85 should all get divided by 1417  and 41, 50 and 97
should all be divided by 1213 ).
 
it doesn't have to retain the column names because i can just assign
them again when i am assigning the rownames.
 
below is my  code :
 
resultmatrix-rbind(temp1,temp2)
resultmatrix-resultmatrix[,2:17]/resultmatrix[,1]
 
colnames(resultmatrix)-colnames(temp1)
rownames(resultmatrix)-c(group1,group2)
 
I'm pretty sure above will work but it seemed kind of ugly and I
wondering if there is a better way because i am trying to improve in R.
if there isn't, that's fine. thanks.


This is not an offer (or solicitation of an offer) to buy/sell the 
securities/instruments mentioned or an official confirmation.  Morgan Stanley 
may deal as principal in or own or act as market maker for 
securities/instruments mentioned or may advise the issuers.  This is not 
research and is not from MS Research but it may refer to a research 
analyst/research report.  Unless indicated, these views are the author's and 
may differ from those of Morgan Stanley research or others in the Firm.  We do 
not represent this is accurate or complete and we may not update this.  Past 
performance is not indicative of future returns.  For additional information, 
research reports and important disclosures, contact me or see 
https://secure.ms.com/servlet/cls.  You should not use e-mail to request, 
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transfer instructions, or to effect any other transactions.  We cannot 
guarantee that any such requests received via !
 e-mail will be processed in a timely manner.  This communication is solely for 
the addressee(s) and may contain confidential information.  We do not waive 
confidentiality by mistransmission.  Contact me if you do not wish to receive 
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defined in the UK Financial Services Authority's rules).

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Re: [R] looking for a cleaner way to do something

2006-10-17 Thread Gabor Grothendieck
Try this:

X - structure(11:15, .Names = letters[1:5])
Y - structure(21:25, .Names = letters[1:5])

rbind(group1 = X, group2 = Y)
tab - rbind(group1 = X, group2 = Y)
tab[,-1] / tab[,1]

On 10/17/06, Leeds, Mark (IED) [EMAIL PROTECTED] wrote:
 I have two numeric vectors each of length 17 and each is named the exact
 same way.

 so
obsnum p  m pppmp . dot dot dot..
 temp1is141752 63   85

 obsnum p  m pppmp . dot dot dot..
 temp2 is   1213 4150   97

 what i want to have is a resultant matrix with 2 rows and 16 columns
 where the 16 columns are the 2:17 columns divided by the respective
 first element in each vector.
 ( so 52, 63 and 85 should all get divided by 1417  and 41, 50 and 97
 should all be divided by 1213 ).

 it doesn't have to retain the column names because i can just assign
 them again when i am assigning the rownames.

 below is my  code :

 resultmatrix-rbind(temp1,temp2)
 resultmatrix-resultmatrix[,2:17]/resultmatrix[,1]

 colnames(resultmatrix)-colnames(temp1)
 rownames(resultmatrix)-c(group1,group2)

 I'm pretty sure above will work but it seemed kind of ugly and I
 wondering if there is a better way because i am trying to improve in R.
 if there isn't, that's fine. thanks.
 

 This is not an offer (or solicitation of an offer) to buy/sell the 
 securities/instruments mentioned or an official confirmation.  Morgan Stanley 
 may deal as principal in or own or act as market maker for 
 securities/instruments mentioned or may advise the issuers.  This is not 
 research and is not from MS Research but it may refer to a research 
 analyst/research report.  Unless indicated, these views are the author's and 
 may differ from those of Morgan Stanley research or others in the Firm.  We 
 do not represent this is accurate or complete and we may not update this.  
 Past performance is not indicative of future returns.  For additional 
 information, research reports and important disclosures, contact me or see 
 https://secure.ms.com/servlet/cls.  You should not use e-mail to request, 
 authorize or effect the purchase or sale of any security or instrument, to 
 send transfer instructions, or to effect any other transactions.  We cannot 
 guarantee that any such requests received vi!
 a !
  e-mail will be processed in a timely manner.  This communication is solely 
 for the addressee(s) and may contain confidential information.  We do not 
 waive confidentiality by mistransmission.  Contact me if you do not wish to 
 receive these communications.  In the UK, this communication is directed in 
 the UK to those persons who are market counterparties or intermediate 
 customers (as defined in the UK Financial Services Authority's rules).

[[alternative HTML version deleted]]

 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] looking for a cleaner way to do something

2006-10-17 Thread Gabor Grothendieck
Sorry there was an extra line in there.  It should be:

X - structure(11:15, .Names = letters[1:5])
Y - structure(21:25, .Names = letters[1:5])

tab - rbind(group1 = X, group2 = Y)
tab[,-1] / tab[,1]


On 10/17/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
 Try this:

 X - structure(11:15, .Names = letters[1:5])
 Y - structure(21:25, .Names = letters[1:5])

 rbind(group1 = X, group2 = Y)
 tab - rbind(group1 = X, group2 = Y)
 tab[,-1] / tab[,1]

 On 10/17/06, Leeds, Mark (IED) [EMAIL PROTECTED] wrote:
  I have two numeric vectors each of length 17 and each is named the exact
  same way.
 
  so
 obsnum p  m pppmp . dot dot dot..
  temp1is141752 63   85
 
  obsnum p  m pppmp . dot dot dot..
  temp2 is   1213 4150   97
 
  what i want to have is a resultant matrix with 2 rows and 16 columns
  where the 16 columns are the 2:17 columns divided by the respective
  first element in each vector.
  ( so 52, 63 and 85 should all get divided by 1417  and 41, 50 and 97
  should all be divided by 1213 ).
 
  it doesn't have to retain the column names because i can just assign
  them again when i am assigning the rownames.
 
  below is my  code :
 
  resultmatrix-rbind(temp1,temp2)
  resultmatrix-resultmatrix[,2:17]/resultmatrix[,1]
 
  colnames(resultmatrix)-colnames(temp1)
  rownames(resultmatrix)-c(group1,group2)
 
  I'm pretty sure above will work but it seemed kind of ugly and I
  wondering if there is a better way because i am trying to improve in R.
  if there isn't, that's fine. thanks.
  
 
  This is not an offer (or solicitation of an offer) to buy/sell the 
  securities/instruments mentioned or an official confirmation.  Morgan 
  Stanley may deal as principal in or own or act as market maker for 
  securities/instruments mentioned or may advise the issuers.  This is not 
  research and is not from MS Research but it may refer to a research 
  analyst/research report.  Unless indicated, these views are the author's 
  and may differ from those of Morgan Stanley research or others in the Firm. 
   We do not represent this is accurate or complete and we may not update 
  this.  Past performance is not indicative of future returns.  For 
  additional information, research reports and important disclosures, contact 
  me or see https://secure.ms.com/servlet/cls.  You should not use e-mail to 
  request, authorize or effect the purchase or sale of any security or 
  instrument, to send transfer instructions, or to effect any other 
  transactions.  We cannot guarantee that any such requests received !
 via !
   e-mail will be processed in a timely manner.  This communication is solely 
  for the addressee(s) and may contain confidential information.  We do not 
  waive confidentiality by mistransmission.  Contact me if you do not wish to 
  receive these communications.  In the UK, this communication is directed in 
  the UK to those persons who are market counterparties or intermediate 
  customers (as defined in the UK Financial Services Authority's rules).
 
 [[alternative HTML version deleted]]
 
  __
  R-help@stat.math.ethz.ch mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 


__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.