Hi,
yes, it is all about numerical accuracy;
x - c(6.402611, 6.402611, 6.420587)
x001 - sapply(1:9, function(type) quantile(x, probs=0.01, type=type))
names(x001) - NULL
print(x001)
## [1] 6.402611 6.402611 6.402611 6.402611 6.402611
## [6] 6.402611 6.402611 6.402611 6.402611
diff(x001)
## [1]
Hello,
I am getting an unexpected result from quantile(). Specifically, the
return value falls outside the range of the data, which I wouldn't
have thought possible for a weighted average of 2 order statistics.
Is this an unintended accuracy issue or am I being too casual in my
comparison (is
