in Google
> (as US user) yielded some good results (5th and 7th entry), but there
> was another example that explicitly yielded this technique. I can't
> seem to recall my exact search string.
>
>
> - Original Message -
> From: "David L. Van Brunt, Ph.D.&quo
On Thu, 2007-03-15 at 10:21 +0100, Peter Dalgaard wrote:
> Gavin Simpson wrote:
> > On Wed, 2007-03-14 at 20:16 -0700, Steven McKinney wrote:
> >
> >> Since you can index a matrix or dataframe with
> >> a matrix of logicals, you can use is.na()
> >> to index all the NA locations and replace them
On Thu, Mar 15, 2007 at 10:21:22AM +0100, Peter Dalgaard wrote:
> Gavin Simpson wrote:
> > On Wed, 2007-03-14 at 20:16 -0700, Steven McKinney wrote:
> >
> >> Since you can index a matrix or dataframe with
> >> a matrix of logicals, you can use is.na()
> >> to index all the NA locations and repla
Gavin Simpson wrote:
> On Wed, 2007-03-14 at 20:16 -0700, Steven McKinney wrote:
>
>> Since you can index a matrix or dataframe with
>> a matrix of logicals, you can use is.na()
>> to index all the NA locations and replace them
>> all with 0 in one command.
>>
>>
>
> A quicker solution, tha
y and Breast Cancer Program
> British Columbia Cancer Research Centre
>
> email: [EMAIL PROTECTED]
>
> tel: 604-675-8000 x7561
>
> BCCRC
> Molecular Oncology
> 675 West 10th Ave, Floor 4
> Vancouver B.C.
> V5Z 1L3
> Canada
>
>
>
>
> -Ori
/14/2007 5:22 PM
To: R-Help List
Subject: [R] replacing all NA's in a dataframe with zeros...
I've seen how to replace the NA's in a single column with a data frame
*> mydata$ncigs[is.na(mydata$ncigs)]<-0
*But this is just one column... I have thousands of columns (!) that
---
From: "David L. Van Brunt, Ph.D." <[EMAIL PROTECTED]>
To: "R-Help List"
Sent: Wednesday, March 14, 2007 5:22 PM
Subject: [R] replacing all NA's in a dataframe with zeros...
> I've seen how to replace the NA's in a single column with a data
>
I've seen how to replace the NA's in a single column with a data frame
*> mydata$ncigs[is.na(mydata$ncigs)]<-0
*But this is just one column... I have thousands of columns (!) that I need
to do this, and I can't figure out a way, outside of the dreaded loop, do
replace all NA's in an entire data
