male
> which(sexf %in% "male")
[1] 1 2
> which(sexf == "male")
[1] 1 2
Bill Venables
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Alexander Nervedi
Sent: Tuesday, 12 December 2006 10:09 AM
To: r-help@stat.math.ethz.ch
Subject: [R]
Hi,
To be able to match cases with a benchmark I need to have a data.frame with
a character id variable. however, I am surprised why this seems to be so
hard. In fact I was unable to succeed. Here is what I tried:
>test1 <-expand.grid(ID = 1:2, sex = c("male","female"))
>is(test1[,2])
[1] "fact
