Dear all,
I have looked for an answer for a couple of days, but can't come with any
solution.
I have a set of functions, say:
t0 - function(x) {1}
t1 - function(x) {x}
t2 - function(x) {x^2}
t3 - function(x) {x^3}
I would like to find a way to add up the previous 4 functions and obtain a
Try this:
L - list(function(x) 1, function(x) x, sin, cos)
sumL - function(x) sum(sapply(L, function(f) f(x)))
sumL(pi) # pi
On 10/20/06, James Foadi [EMAIL PROTECTED] wrote:
Dear all,
I have looked for an answer for a couple of days, but can't come with any
solution.
I have a set of
James Foadi [EMAIL PROTECTED] writes:
Dear all,
I have looked for an answer for a couple of days, but can't come with any
solution.
I have a set of functions, say:
t0 - function(x) {1}
t1 - function(x) {x}
t2 - function(x) {x^2}
t3 - function(x) {x^3}
I would like to find a
will this work for you?
t0 - function(x) {1}
t1 - function(x) {x}
t2 - function(x) {x^2}
t3 - function(x) {x^3}
t.l - list(t0,t1,t2,t3)
t.l
[[1]]
function(x) {1}
[[2]]
function(x) {x}
[[3]]
function(x) {x^2}
[[4]]
function(x) {x^3}
arg.val - 4 # evaluate for 4
Here is one way. To have a vectorized version you need to redefine
't0', though
t0 - function(x) {1}
t1 - function(x) {x}
t2 - function(x) {x^2}
t3 - function(x) {x^3}
ttt - list(t0,t1,t2,t3)
rrr - function(x) sum(sapply(seq(along=ttt), function(i) ttt[[i]](x)))
## vectorized version
ttt[[1]]
Many thanks to those who have answered my question.
Could I ask Gabor and Peter the meaning of:
sum(sapply(ttt,function(f) f(x)))
I gather that a mysterious function f(x) is applied to all components of
ttt, and sum can act on this modified object. But what is exactly f? And how
does the list
ttt is a list of functions so each function in ttt is passed in turn to
the anonymous function as argument f.
On 10/20/06, James Foadi [EMAIL PROTECTED] wrote:
Many thanks to those who have answered my question.
Could I ask Gabor and Peter the meaning of:
sum(sapply(ttt,function(f) f(x)))
