Use as.matrix() :
m - round( as.dist( cor( matrix( rnorm(600), nc=6 ) ) ), 2 )
m
1 2 3 4 5
2 -0.05
3 0.01 0.03
4 0.00 0.05 0.00
5 0.20 0.07 0.09 -0.07
6 0.03 0.02 0.11 -0.15 -0.11
as.matrix( m )
1 23 4 5 6
1 0.00 -0.05 0.01 0.00 0.20 0.03
2 -0.05 0.00 0.03 0.05 0.07 0.02
3 0.01 0.03 0.00 0.00 0.09 0.11
4 0.00 0.05 0.00 0.00 -0.07 -0.15
5 0.20 0.07 0.09 -0.07 0.00 -0.11
6 0.03 0.02 0.11 -0.15 -0.11 0.00
On Tue, 2005-11-29 at 03:04 -0800, Robert wrote:
I have the following matrix:
1 234 5
2 0.7760856
3 2.016 1.6907899
4 0.6148687 0.2424415 1.593916
5 3.0227028 2.3636083 1.512634 2.426591
6 3.2104434 2.5334957 1.730422 2.608584 0.2184739
the diagonal is 0 and it is a symmetric matrix.
Is there any function to return to the normal one?
That is, the 6 by 6 one?
-
Single? There's someone we'd like you to meet.
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