Hi,
Am using maanova package for doing anova.But am getting error like
this..plz, help me regarding this..
TGR=read.madata(rmaexpr.dat,designfile=design.dat)
Reading one color array.
Otherwise change arrayType='twoColor' then read the data again
Warning messages:
1: In
Dear R users,
I have panel data on the amount of money spent by travellers from 8 origin
countries in 4 destinations. I would like to carry out analysis for
destinations, origins and time. However, it seems to me that the package
plm can only esitmate two-way panel data (indexed by a
-Mensaje original-
De: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] En nombre de Dipa Hari
Enviado el: lunes, 12 de julio de 2010 22:19
Para: r-help@r-project.org
Asunto: [R] ed50
I am using semiparametric Model
library(mgcv)
Hi all,
I'm just wondering if there is a equivalent of SAS's FIRST. and LAST.
variables in R?
For example, suppose this is a snapshot of the data:
ClientCode CaseCode open closeImportant
1 37 28 2003-07-08 2003-09-021
2
Hi,
I expect there are better ways of doing this then the following, but you
can probably get the same sort of thing using the split command
bb =
matrix(c(1,1,1,2,2,2,3,3,3,3,10,11,12,43,23,14,52,52,12,23),ncol=2,byrow
=FALSE)
aa = split(bb,bb[,1])
sapply(aa,function(temp) {cc =
Hello R-users,
I have a very large vector (a) containing elements consisting of numbers
and letters, this is the i.e.
a
[1] 1.11.2a 1.11.2d 1.11.2e 1.11.2f 1.11.2x1
1.11.2x1b
[7] 1.11.2x21.11.2x2a 1.11.2x2b 1.11.2x31.11.2x4
1.11.2x4a
[13] 1.11.2x5
Here is one way
a_clip - sub(^([0-9]+\\.[0-9]+\\.[0-9]+).*$, \\1, a)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Lorenzo Cattarino
Sent: Tuesday, 13 July 2010 5:20 PM
To: r-help@r-project.org
Subject: [R] modifying vector
On Tue, Jul 13, 2010 at 3:20 AM, Lorenzo Cattarino
l.cattar...@uq.edu.au wrote:
Hello R-users,
I have a very large vector (a) containing elements consisting of numbers
and letters, this is the i.e.
a
[1] 1.11.2a 1.11.2d 1.11.2e 1.11.2f 1.11.2x1
1.11.2x1b
[...]
How
DN == David Neu da...@davidneu.com
on Mon, 12 Jul 2010 18:15:04 -0400 writes:
DN Hi, Is there a way to create a matrix in which the
DN column names are not checked to see if they are valid
DN variable names?
Why do you need that if you are really using a matrix, not a
data
On 07/13/2010 01:10 AM, g...@ucalgary.ca wrote:
I would like to sum/mean/min a list of lists and numbers to return the
related lists.
-1+2*c(1,1,0)+2+c(-1,10,-1) returns c(2,13,0) but
sum(1,2*c(1,1,0),2,c(-1,10,-1)) returns 15 not a list.
Using the suggestions of Gabor Grothendieck,
Dear R-help Team Members,
I am venkatesh , Student of university of Hyderabad, while Installing R from
the specified servers, I encountered the following problem. please help me
regarding. i need this to do my project .
Thanking you.
*Problem* :
Cannot access installation media
Dear R-help team ,
I am venkatesh, student of University of Hyderabad, India. I couldn't able to
access R-repositories at Your specified servers.It is giving error such as
Couldn't able to access media. Can you please help me Regarding this.
i am anticipating for your reply, thanking you.
I have 5 columns- Trial.Group, Mean, Standard Deviation, Upper percentile,
Lower percentile.
Trial.Group 41 subjects: 3 to 4 yrs-Male
Mean 444
SD 25
upper 494
lower 393
and all the data is like that.
and i wish to recreate this excel
Hi Sarah,
We regularly undertake work in the food sector and have developed many
custom built solutions. To be more specific, the statistics we employ is
that of sensory analysis and we regularly use the sensominer package in
R.
Regards,
Richard Weeks
Mangosolutions
data analysis that delivers
Hi R,
I am examining the mean returns 10 days before and 10 days after a
event. Now I have several events the corresponding pre and post event 10
day mean returns... something like this
Pre_Start Pre_End Pre_MeanPre_SD
Post_StartPost_End
Hi
r-help-boun...@r-project.org napsal dne 12.07.2010 16:09:30:
When I just run a for loop it works. But if I am going to run a for loop
every time for large vectors I might as well use C or any other
language.
The reason R is powerful is becasue it can handle large vectors without
each
Hi
r-help-boun...@r-project.org napsal dne 13.07.2010 12:18:21:
Hi R,
I am examining the mean returns 10 days before and 10 days after a
event. Now I have several events the corresponding pre and post event 10
day mean returns... something like this
Pre_Start
I see. I did not get these performances since did not directly compare
arrays but run seemingly expensive for-loops to do it iteratively...
:(
R.
On Tue, Jul 13, 2010 at 1:42 AM, Hadley Wickham had...@rice.edu wrote:
strings - replicate(1e5, paste(sample(letters, 100, rep = T), collapse
Dear List,
I would like to modify the settings for plotting a Vennerable object,
but I don't know how...so if anyone has an idea I would be really
graetfull.
best, Fabian
some R code to illustrate my problem:
library(Vennerable)
ven - compute.Venn(Venn(SetNames=c(A, B),
Hi
I do not use any of mentioned libraries so I can not directly answer it. I
would try to use debug(expr.frame) to see at what time the error is
thrown.
I have no idea why did you obtain error. Try to evaluate code in peaces
e.g. what is result of
list(MAf=quote(SMA(Last, 20)),
Hi folks,
I am confused whether the following is a bug or it is fine
Here is the explanation
a - zoo(c(NA,1:9),1:10)
Now If I do
rollapply(a,FUN=mean,width=3,align=right)
I get
rollapply(a,FUN=mean,width=3,align=right)
3 4 5 6 7 8 9 10
NA NA NA NA NA NA NA NA
But I shouldn't be
Many many thanks to all of you. The beer cleared the air of doubts!
Pls look at the following lines of code. This is taken from the example of
tradesys documentation. When I run the given example using the data.frame
spx it works just very fine but while I use some other data.frame (here
nifty) it
Dear Danice,
as far as I know, three-way panels are not considered in the
econometrics literature (two dimensions make things complicated enough
already). They are also not implemented in plm.
You might find support for more elaborate nesting structures in the nlme
and lme4 packages. Yet, as the
Given vectors of strings of arbitrary length
content - c(abc, def)
searchset - c(a, abc, abcdef, d, def, defghi)
Is it possible to determine the content String set that matches the
searchset in the sense of 'startswith' ? This would be a vector of all
strings in content that start with the
On Tue, 2010-07-13 at 13:39 +0530, venkatesh bandaru wrote:
Dear R-help Team Members,
I am venkatesh , Student of university of Hyderabad, while Installing R from
the specified servers, I encountered the following problem. please help me
regarding. i need this to do my project .
Thanking
On Tue, 2010-07-13 at 17:13 +0530, sayan dasgupta wrote:
Hi folks,
I am confused whether the following is a bug or it is fine
Here is the explanation
a - zoo(c(NA,1:9),1:10)
Now If I do
rollapply(a,FUN=mean,width=3,align=right)
mean() has argument na.rm which defaults to FALSE. As
That helped. I continued to have issues with
draw.in=vplayout(2,2)$name
(I guess I still don't understand it use), but the following positions
the plot on the grid where I want it.
grid.newpage()
pushViewport(viewport(layout=grid.layout(2,2)))
vp - vplayout(2,2)
pushViewport(vp)
On Tue, Jul 13, 2010 at 5:27 PM, Gavin Simpson gavin.simp...@ucl.ac.ukwrote:
On Tue, 2010-07-13 at 17:13 +0530, sayan dasgupta wrote:
Hi folks,
I am confused whether the following is a bug or it is fine
Here is the explanation
a - zoo(c(NA,1:9),1:10)
Now If I do
Dear list!
I develop a package for R and wonder how I can best define
package-wide constants (both character strings or named vectors of
strings) which are used throughout different classes and methods. I'm
new to R and wonder if there is some kind of “best practice” that I
just haven't read of
Hi all,
I would like to detect all strings in the vector 'content' that
contain the strings from the vector 'search'. Here a code example:
content - data.frame(urls=c(
On 13/07/2010 8:20 AM, Daniel Nüst wrote:
Dear list!
I develop a package for R and wonder how I can best define
package-wide constants (both character strings or named vectors of
strings) which are used throughout different classes and methods. I'm
new to R and wonder if there is some kind of
On Tue, 2010-07-13 at 17:41 +0530, sayan dasgupta wrote:
On Tue, Jul 13, 2010 at 5:27 PM, Gavin Simpson
gavin.simp...@ucl.ac.uk wrote:
On Tue, 2010-07-13 at 17:13 +0530, sayan dasgupta wrote:
Hi folks,
I am confused whether the following is a bug or it
On Tue, Jul 13, 2010 at 7:43 AM, sayan dasgupta kitt...@gmail.com wrote:
Hi folks,
I am confused whether the following is a bug or it is fine
Here is the explanation
a - zoo(c(NA,1:9),1:10)
Now If I do
rollapply(a,FUN=mean,width=3,align=right)
I get
On Jul 13, 2010, at 8:47 AM, Josh B wrote:
Thanks again, David.
...but, alas, I still can't get it work! Here's what I'm trying now:
for (i in 1:2) {
mod.poly3 - try(lrm(x[,i] ~ pol(x1, 3) + pol(x2, 3), data=x))
results[1,i] - anova(mod.poly3)[1,3]
}
You need to do some
On Jul 13, 2010, at 9:04 AM, David Winsemius wrote:
On Jul 13, 2010, at 8:47 AM, Josh B wrote:
Thanks again, David.
...but, alas, I still can't get it work!
(BTW, it did work.)
Here's what I'm trying now:
for (i in 1:2) {
mod.poly3 - try(lrm(x[,i] ~ pol(x1, 3) + pol(x2, 3),
Dear list,
I am currently doing some simulation studies where I want to compare different
scenarios.
In particular, two scenarios should be compared: 10.000 cases in 100 groups
with 100 cases per group and 10.000 cases in 100 groups with random group size
(ranging from 5 to 500).
The first
Dear all
I finally found the way to do it. Nlme accepts simpler functions than
selfStart:
# Defining my function
Myfun -function(x1,x2,Tmax,Topt,B,E) {
(((Tmax-x1)/(Tmax-Topt))*(x1/Topt)^(Topt/(Tmax-Topt)))*exp(-exp(B*(log(x2)-log(abs(E)
}
# Calling nlme
nlmefit3 - nlme( y ~
On Tue, 2010-07-13 at 01:42 -0400, Hadley Wickham wrote:
strings - replicate(1e5, paste(sample(letters, 100, rep = T), collapse =
))
system.time(strings[-1] == strings[-1e5])
# user system elapsed
# 0.016 0.000 0.017
So it takes ~1/100 of a second to do ~100,000 string
well %in% is really checking if the element is in the set and is not a
substring operator.
To get the result you want, try
content[grepl(search$signatures, content$urls),]
For multiple operations you could try
sapply(search$signatures, grepl, x=content$urls)
Nikhil Kaza
Asst. Professor,
Hi List, just to know if the issue is only a problem of mine or if it is a
general issue due to the new MS Office pack. I'm using R 2.11.1 32 bits in a
Windows 7 x64 with the MS office 2010 x64 installed. I can import .xls files
normally (the same way I did with my Excel 2007 32 bits). But the
Thanks Richard and Erik,
I hate to buy the book and not find the solution to the following:
proc.means - function() {
deparse(match.call()[-1])
}
proc.means(this is a sentence)
unexpected symbol in proc means(this is)
One possible solution would be to 'peek' into the memory buffer
I am using windows Xp OS and R 2.10. I treid to install ROracle package and I
got following error:-
This application has failed to start because orasql9.dll was not found.
Re-installing
the application may fix this problem
I have already installed the dependecy package DBI
Please help
Thanks for the tip. From the link you posted:
| You can embed the user id and password into the URL. For example:
|
| http://userid:passw...@www.anywhere.com/
| ftp://userid:passw...@ftp.anywhere.com/
I'm still having issues, though. I am trying to fetch some csv files from a
storage site
Dear All,
Could someone please advice me the appropriate package for fitting the SARIMA
model?
Thanks
Fir
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Thanks again, David.
...but, alas, I still can't get it work! Here's what I'm trying now:
for (i in 1:2) {
mod.poly3 - try(lrm(x[,i] ~ pol(x1, 3) + pol(x2, 3), data=x))
results[1,i] - anova(mod.poly3)[1,3]
}
Here's what happens (from the console):
Error in fitter(X, Y, penalty.matrix
In my opinion the try and tryCatch commands are written and documented rather
poorly. Thus I am not sure what to program exactly.
For instance, I could query mod.poly3 and use an if/then statement to proceed,
but querying mod.poly3 is weird. For instance, here's the output when it fails:
On Tue, Jul 13, 2010 at 9:31 AM, Rodrigo Aluizio r.alui...@gmail.com wrote:
Hi List, just to know if the issue is only a problem of mine or if it is a
general issue due to the new MS Office pack. I'm using R 2.11.1 32 bits in a
Windows 7 x64 with the MS office 2010 x64 installed. I can import
Hi,
On Sat, Jul 10, 2010 at 12:35 AM, Noah Silverman
n...@smartmediacorp.com wrote:
Steve,
Couldn't he also just use the decision.value property to see the equivilent
of t(x) %*% b for each row?
I don't follow what you're saying. What is this the equivalent of?
What's b here? The
Hi Matt,
I think there are some confusing factors in your results.
system.time(strcmp(strings[-1], strings[-1e5]))
would also include the time required to perform both subscripting
(strings[-1] and strings[-1e5] ) which actually takes some time.
Also, you do have a bit of overhead due to
Update: Solution ##
Dear all,
just in case someone has the same question: I found the method
writeBiclusterResults. It prints the results of all modules together in one
file, containing the gene names and array/experiment names. It does not
Dear useRs,
I am facing the following problem in R and hope you can help me. I want to
discretize a normal distribution to 4 predefined bands. The bands are
1,2,10 and 20. In order to maintain the symmetric shape and the mean of the
density I need to cut off all negative values and the
Hi,
On Mon, Jul 12, 2010 at 4:55 AM, manuel.martin
manuel.mar...@orleans.inra.fr wrote:
On 07/10/2010 04:11 AM, Steve Lianoglou wrote:
On Fri, Jul 9, 2010 at 12:15 PM, manuel.martin
manuel.mar...@orleans.inra.fr wrote:
snip
Dear all,
after having calibrated a svm model through the svm()
Dear all,
I have a code that generates data vectors within R. For example assume:
z - rlnorm(1000, meanlog = 0, sdlog = 1)
Every time a vector has been generated I would like to export it into a csv
file. So my idea is something as follows:
for (i in 1:100) {
z - rlnorm(1000, meanlog = 0, sdlog
On 13/07/2010 8:39 AM, Roger Deangelis wrote:
Thanks Richard and Erik,
I hate to buy the book and not find the solution to the following:
proc.means - function() {
deparse(match.call()[-1])
}
proc.means(this is a sentence)
unexpected symbol in proc means(this is)
One possible
write.csv(z, paste(c:/z_,i,.csvsep=''))
You will have to modify this to prepend 0s.
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
nikhil.l...@gmail.com
On Jul 13, 2010, at 10:03 AM, Michael Haenlein wrote:
Dear all,
I have a code that generates data
On Tue, 13 Jul 2010, Rodrigo Aluizio wrote:
Hi List, just to know if the issue is only a problem of mine or if it is a
general issue due to the new MS Office pack. I'm using R 2.11.1 32 bits in a
It's a Microsoft muddle, covered in the RODBC manual for the next
release. Note that R-sig-db
Hi Felipe,
The problem has nothing to do with Sweave or \Sexpr. The problem is
that by the time you call \Sexpr report is a matrix, and you cannot
access the column names of a matrix with names(). You need to use
colnames() or convert the matrix to a data.frame.
Perhaps a true useR can write R
On Jul 13, 2010, at 9:24 AM, Josh B wrote:
In my opinion the try and tryCatch commands are written and
documented rather poorly. Thus I am not sure what to program exactly.
Didn't you see the silent parameter? Its seems to be documented
fairly clearly to me.
The testing of try at the
On Jul 13, 2010, at 10:26 AM, David Winsemius wrote:
On Jul 13, 2010, at 9:24 AM, Josh B wrote:
In my opinion the try and tryCatch commands are written and
documented rather poorly. Thus I am not sure what to program exactly.
Didn't you see the silent parameter? Its seems to be
Hi,
I have used the instruction aov in the following manner:
res - aov(qwe ~ asd)
when I typed res I get:
_
Call:
aov(formula = qwe ~ asd)
Terms:
asd Residuals
Sum of Squares 0.0708704 0.5255957
Deg. of Freedom 1 8
Residual standard error:
On Jul 13, 2010, at 10:35 AM, Luis Borda de Agua wrote:
Hi,
I have used the instruction aov in the following manner:
res - aov(qwe ~ asd)
when I typed res I get:
_
Call:
aov(formula = qwe ~ asd)
Terms:
asd Residuals
Sum of Squares 0.0708704 0.5255957
Deg. of
Thanks Izta:
I see your point, then I should extract the column names when the
dataset is first read because is a dataframe:
report - structure(list(Date = c(3/12/2010, 3/13/2010, 3/14/2010,
3/15/2010), Run1 = c(33 (119 ? 119), n (0 ? 0), 893 (110 ? 146),
140 (111 ? 150)), Run2 = c(33 (71 ?
The high-level concept you need is called Regular Expressions. R
supports these through several functions, see ?regex .
Ralf B wrote:
Hi all,
I would like to detect all strings in the vector 'content' that
contain the strings from the vector 'search'. Here a code example:
content -
I think the easiest way is from calling anova() on your aov class
object. For instance
y - 1:10
x - runif(10)
my.aov - aov(y ~ x)
anova(my.aov)[Residuals, Sum Sq]
anova(my.aov)[x, Pr(F)]
You can also extract these values from a call to summary(my.aov), but
that output is a list (even for an
R list-
i have begun using the MplusAutomation while piloting a large-scale
simulation (~200,000 replications). since the package takes advantage of the
DOS batch mode available in Mplus, each replication starts and activates a new
instance of a command prompt window. this effectively locks me
Dear nuncio
my internet is connected properly, i am running yast as a superuser , i am
getting the following error
*Problem* :
Cannot access installation media
http://download.opensuse.org/repositories/devel:languages:R:patched/openSUSE_11.2
(Medium 1).
Check whether the server is
Dear Clay,
dear list,
I face the same problem when rounding POSIXct objects. Have you (or has
anybody) found an explanation meanwhile, or a way to work around this issue?
Example:
opt-options(digits.secs=3)
ts1-as.POSIXct(c(2006-11-01 09:00:00.03, 2006-11-01 09:00:01,
2006-11-01
You could try rlm in the MASS package; it doesn't use he resampling
step.
That seems to do the trick. Thank you!
--
View this message in context:
http://r.789695.n4.nabble.com/Robust-regression-error-Too-many-singular-resamples-tp2286585p2287468.html
Sent from the R help mailing list archive
Actually,
I realized that my task was a bit more complicated as I have different
(let's call them) Markets and the dates repeat themselves across
markets. And the original code from Gabor gives an error - because
dates repeate themselves and apparently zoo cannot handle it. So, I
had to do program
Is it possible to download data from password-protected ftp sites? I saw
another thread with instructions for uploading files using RCurl, but I
could not find information for downloading them in the RCurl documentation.
Did you try the ?getURL function in RCurl? See the `Test the
If the curves are sufficiently close to sine (cosine) curves and you know the
period, then this can be restructured as a linear model and you can avoid all
the complexities that come with non-linear models. Further, from your
description, it does not sound like you really gain much from using
Good idea Romain, there is quite a bit of type testing in the function
versions of STRING_ELT and CHAR, not to mention the function call
overhead. Since the types are checked explicitly, I believe this
function is safe. All together now...
system.time(strings[-1] == strings[-1e5])
user
Hi Felipe,
See in line below.
On Tue, Jul 13, 2010 at 11:04 AM, Felipe Carrillo
mazatlanmex...@yahoo.com wrote:
Thanks Izta:
I see your point, then I should extract the column names when the
dataset is first read because is a dataframe:
That might work, but it's definitely not how I would do
There are several functions in several packages for plotting intervals that
will give you plots much better than the excel one. The RSiteSearch function
or the sos package may help you find those.
But it is also easy to create such plots using just a few lines of R code and
base graphics.
content[na.omit(pmatch(searchset, content,,TRUE))]
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Ralf B
...
Aug;235(2):E97-102). The paper is freely available. The idea is to fit
the curves individually and obtain the residual sum of squares and
then fit the curves altogether somehow constraining some parameters
and then you have another residual sum of squares. Then you can do a
F-test.
For one definition of random:
ss - rexp(100)
ss - ss/sum(ss)
ss - 5 + round( ss*9500 )
cnt - 0
while( ( d - sum(ss) - 1 ) != 0 ) {
tmpid - sample.int(100,1)
ss[tmpid] - ss[tmpid] - d
ss[ ss 500 ] - 500
ss[ ss 5 ] - 5
cnt - cnt + 1
Create a shortcut that targets your batch file and edit its properties to open
minimized, and call the shortcut from R rather than the calling the batch file
directly.
Gushta, Matthew mgus...@air.org wrote:
R list-
i have begun using the MplusAutomation while piloting a large-scale
simulation
On Tue, Jul 13, 2010 at 11:19 AM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Actually,
I realized that my task was a bit more complicated as I have different
(let's call them) Markets and the dates repeat themselves across
markets. And the original code from Gabor gives an
Guys, I wrote to the finance mailing list earlier with my questions but was
directed here.
Sorry for the repeat.
---
library(quantmod)
now - Sys.time()
midnight - strptime()# I want to make this a static variable
that will be equal to 12:00:00 am but I dont know
Paul wrote:
I am trying to recreate an analysis that has been done by another group
(in SAS I believe). I'm stuck on one part, I think because my stats
knowledge is lacking, and while it's OT, I'm hoping someone here can help.
Given this dataframe;
snip
Well, that will teach me to read the
i try to show the result of the cluster-analysis (hclust, method=ward) in a
table with following information
first column: height
second column: number of clusters
third column: clustering information
0,041 | 20 | (3)-(5)
0,111 | 19 | (6)-(11)
0,211 | 18 |
Thank you very much, Gabor!
Dimitri
On Tue, Jul 13, 2010 at 12:25 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Tue, Jul 13, 2010 at 11:19 AM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Actually,
I realized that my task was a bit more complicated as I have different
Hello,
are you trying to pase SAS code (or lightly modified SAS code) and run it in R?
Then you are right: the hard part is parsing the code. I don't believe that's
possible without a custom parser, and even then it's really hard to parse all
the SAS sub languages right: data step, macro
Hi:
Using this dataframe with quite long column headers, how can I wrap the
text so that the columns are narrower. I was trying to use strwrap without
success. Thanks
reportDF - structure(list(IDDate = c(3/12/2010, 3/13/2010, 3/14/2010,
3/15/2010), FirstRunoftheYear = c(33 (119 ? 119), n (0 ?
N_runs -1 seems a bit of an odd df to choose to calculate the CI for a
mean. To answer your question, I think that t.test() is the easiest
way to get a CI in R. That said, you can use the MS_residuals from
ANOVA to take advantage of variance calculated on groups and pooled.
Something like:
foo
What is the original intent? The bandwidth:productivity ratio is not
looking encouraging for this problem.
Frank
On 07/13/2010 12:38 PM, schuster wrote:
Hello,
are you trying to pase SAS code (or lightly modified SAS code) and run it in R?
Then you are right: the hard part is parsing the
You can't try this:
sapply(names(reportDF), toString, width = 10)
abbreviate(names(reportDF))
On Tue, Jul 13, 2010 at 2:43 PM, Felipe Carrillo
mazatlanmex...@yahoo.comwrote:
Hi:
Using this dataframe with quite long column headers, how can I wrap the
text so that the columns are narrower. I
I agree that 'list' is a terrible package name, but only secondarily
because it is a data type. The primary problem is that it is so generic
as to be almost totally uninformative about what the package does.
For some reason package writers seem to prefer maximally uninformative
names for
Using this dataframe with quite long column headers, how can I wrap the
text so that the columns are narrower. I was trying to use strwrap without
success. Thanks
reportDF - structure(list(IDDate = c(3/12/2010, 3/13/2010, 3/14/2010,
3/15/2010), FirstRunoftheYear = c(33 (119 ? 119), n (0 ?
When running the combined code with your suggested line:
content - data.frame(urls=c(
http://www.google.com/search?source=ighl=enrlz==q=stuffaq=faqi=g10aql=oq=gs_rfai=CrrIS3VU8TJqcMJHuzASm9qyBBgAAAKoEBU_QsmVh;,
My solution was based on using vectors (which were your original example), now
you are using data frames. The actual result is NA, then you just print
content again (which my code never modified) so you are going to see the full
content data frame.
Try:
Hi everybody
I am trying to install RJSONIO from source in on Mac OS X 10.5.8. I used the
Package Installer.
The message and sessionInfo is attached below
Can someone help me to understand the error message and maybe give hint
towards solving the problem
thanks in advance
Christiaan
Message:
Hello!
I am trying to scale the outliers in a boxplot. I am passing pars =
list(boxwex=0.1, staplewex=0.1, outwex=0.1) to the boxplot command. The
boxes are scaled correctly, but the circles (outliers) are not scaled at
all, and thus pretty big compared to the boxes scaled with 0.1.
Am I
On Tue, Jul 13, 2010 at 9:54 AM, Aaditya Nanduri
aaditya.nand...@gmail.com wrote:
Guys, I wrote to the finance mailing list earlier with my questions but was
directed here.
Sorry for the repeat.
---
library(quantmod)
now - Sys.time()
midnight - strptime() #
Dear all,
Apologies if this question is bit theoretical and for the longish email.
I am meta-analyzing the coefficients and standard errors from multiple
studies where the raw data is not available.
Each study analyst runs a model that includes an interaction term for,
say, between sex and
Raubertas, Richard wrote:
I agree that 'list' is a terrible package name, but only secondarily
because it is a data type. The primary problem is that it is so generic
as to be almost totally uninformative about what the package does.
For some reason package writers seem to prefer
Dear all,
Please forgive me if there is a duplicate post; my previous mail perhaps didnt
reach the list...
Let say I have following time series
library(zoo)
dat1 - zooreg(rnorm(10), start=as.Date(2010-01-01), frequency=1)
dat1[c(3, 7,8)] = NA
dat1
2010-01-01 2010-01-02 2010-01-03
Megh,
I don't know whether this is the best way, but it works:
seq(1,length(dat1))[!is.na(dat1)]
[1] 1 2 4 5 6 9 10
Jonathan
On Tue, Jul 13, 2010 at 1:58 PM, Megh Dal megh700...@yahoo.com wrote:
Dear all,
Please forgive me if there is a duplicate post; my previous mail perhaps
Hello R-users,
Checking the archives, I recently came across this topic:
export tables to Excel files
(http://r.789695.n4.nabble.com/export-tables-to-Excel-files-td1565679.html#a1565679),
and the following interesting references have been proposed:
1 - 100 of 146 matches
Mail list logo
