Jeff,
Thank you for your response. Upon your suggestion, I sent the connection info
to the slaves as:
mpi.bcast.Robj2slave(sqlUser)
mpi.bcast.Robj2slave(sqlPass)
mpi.bcast.Robj2slave(sqlDBname)
mpi.bcast.Robj2slave(sqlHost)
and then inserted the following command in the slave task:
con -
Erk. Sorry about the wrapping issue on the comments in the code,
which will interfere with a straight copypaste.
Glen
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi,
I've been looking for a package that reads and/or writes in the sdmx
statististical (meta)data format (http://sdmx.org/) but I couldn't find any.
Does anybody know whether this is available?
Cheers!!
Albert-Jan
~~
All
Hi R,
This is a problem, which I have tried to present in a simple way:
Let,
x1=1:10
x2=2:11
y=2+3*x1
lm_obj=lm(y~x1+x2)
lm_obj
step(lm_obj) # Step function for the first time
y=y^0.1
lm_obj
step(lm_obj) #Step function after a transformation on Y, but 'lm_obj' is not
It worked, thanks!
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R-help@r-project.org mailing list
Hi Dennis,
Thanks for the answer, it works perfectly for two time intervals, but
if I add a third interval like this:
ID begin_t1end_t1 begin_t2end_t2
begin_t3end_t3
Thomas 11/03/0413/05/0604/02/07
Dear R-help listes,
I need your helps on implementation a jackknife resampling test.
For example, I have a sample of 100 observations. I need to calculate
the mean by jackknife resampling test. I just intend to sample 75% of
the whole sample (say 75 in this case) in each 100 times of jackknife
Thanks for the explanation!
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Dear all, I need to download some data from this webpage:
http://markets.ft.com/ft/markets/researchArchive.asp
Notable thing here is that there are some fields to be selected to get the
desired data. Is there any R facility to do this directly?
Obviously I can do it manually and then just
Dear list, I'm trying to run the following for loop:
I have two list, the first one is
$'5684'
CFISCALE5684
RAGSOCBBrembo
$'4532'
CFISCALE4532
RAGSOCBStella
which is this one in terms of dput:
dput(kk)
structure(list(`5684` = structure(c(5684, Brembo,
Hi,
While doing matest, i got errors like tis.Can u please help me in solving
these errors.
test.all = matest(madata, fit.full.mix, test.method=c(1,1),
+ shuffle.method=sample, term=Treatment,n.perm=100)
Doing F-test on observed data ...
Error in ma.svd(X, method = dgesvd) : infinite or
Hi,
I've been trying to get this working for ages, but it causes R to hang.
Here is my C code saved as test1.c
# include R.h
# include Rmath.h
void test1 (double *x, double *result)
{
result[0] = rgamma(*x, 2.0);
}
This was compiled using R CMD SHLIB test1.c loaded in R using:
On Jul 20, 2010, at 2:39 AM, Nita Umashankar wrote:
Hello,
I am getting some results from my Probit estimation in R that are in the
opposite direction of what I hypothesized. In sas, the default is
probability that y=0 (instead of 1) so one needs to type the word
descending to get P(y=1).
G'day Steve,
On Tue, 20 Jul 2010 17:20:49 +0930
Steve Pederson stephen.peder...@adelaide.edu.au wrote:
I suggest to insert the following two lines (untested as I usually
don't work on Windows):
# include R.h
# include Rmath.h
void test1 (double *x, double *result)
{
GetRNGstate();
Hi:
This might be a little easier (?):
library(datasets)
skewness - function(x) mean(scale(x)^3)
mean.gt.med - function(x) mean(x)median(x)
# --
# construct the function to apply to each variable in the data frame
f - function(x) c(mean = mean(x), sd = sd(x), skewness = skewness(x),
Hi everybody,
Suppose we have the following data structure:
ddf -data.frame(a=rep(1:4,3), b=rep(paste(p, 1:3, sep=), each=4),
c=c(1,0,0,1,1,1,0,1,1,1,1,1))
I want now to make a contingency table for each pair of values of p,
i.e. a contingency table for each of the pairs (p1,p2), (p1,p3) and
On Tue, 2010-07-20 at 13:16 +0530, Shubha Vishwanath Karanth wrote:
Hi R,
This is a problem, which I have tried to present in a simple way:
Let,
x1=1:10
x2=2:11
y=2+3*x1
lm_obj=lm(y~x1+x2)
lm_obj
step(lm_obj) # Step function for the first time
y=y^0.1
lm_obj
one approach is the following:
ddf - data.frame(a = rep(1:4,3), b = rep(paste(p, 1:3, sep=),
each=4), c = c(1,0,0,1,1,1,0,1,1,1,1,1))
sp - lapply(split(ddf$c, ddf$b), factor, levels = 0:1)
combn(sp, 2, FUN = table, simplify = FALSE)
I hope it helps.
Best,
Dimitris
On 7/20/2010 11:29 AM,
Dear R community,
is there a way to get correct t- and p-values and R squared for linear
regression models specified without an intercept?
example model:
summary(lm(y ~ 0 + x))
This gives too low p-values and too high R squared. Is there a way to
correct it? Or should I specify with intercept
Works as expected, THX a lot.
BR thorn
-Original Message-
From: Dimitris Rizopoulos [mailto:d.rizopou...@erasmusmc.nl]
Sent: mardi 20 juillet 2010 11:41
To: Thaler,Thorn,LAUSANNE,Applied Mathematics
Cc: r-help@r-project.org
Subject: Re: [R] apply: return list of matrices
one
Let's assume x and y as stationary. It's not a spurious regression problem
here. I think the function lm() has to have an intercept to give correct
values of t- and p- and R squared. I wonder if you can correct the values in
R though?
--
View this message in context:
What x and y represent? Are they non-stationary, trending? then you would get
very high R2 (~97-99%) and very low p-value. Perhaps you land on the world
of spurious regression.
In this case forcing intercept to zero would not help you. Work with
differenced series instead raw data.
Thanks and
Hi:
On Tue, Jul 20, 2010 at 2:41 AM, StatWM wmus...@gmx.de wrote:
Dear R community,
is there a way to get correct t- and p-values and R squared for linear
regression models specified without an intercept?
example model:
summary(lm(y ~ 0 + x))
This gives too low p-values and too high R
On Jul 20, 2010, at 11:41 AM, StatWM wrote:
Dear R community,
is there a way to get correct t- and p-values and R squared for linear
regression models specified without an intercept?
example model:
summary(lm(y ~ 0 + x))
This gives too low p-values and too high R squared. Is there
Hi AAditya,
There's a great tool for searching the web, called Google. I used it
to find the following web site when I entered historical libor rates
for the search:
http://www.wsjprimerate.us/libor/libor_rates_history.htm. The site came
up as the first hit. I suggest you use the scrapeR
Hi Berwin,
Thanks for the help. That got it working.
And you're right. I'm still struggling my way through trying to
understand Section 5.
http://cran.r-project.org/doc/manuals/R-exts.html#System-and-foreign-language-interfaces
Cheers,
Steve
Berwin A Turlach wrote:
G'day Steve,
On Tue,
Dear:
Anyone has experience to use R integrate a function with more than two
dimensions, but
you only need to integrate the function respect to one variable, say x. Because
I also
want to maximise the log-likelihood after integration of function respect to x.
Thanks!
Xin
---
Dr.Xin Shi
At 01:11 20/07/2010, Kate Snedeker wrote:
Greetings
I have been trying to use metaplot to create a forest plot of my
meta-analysis results. My data is in the form of ORs, so I've been
inputting the ORs as the point estimate (mn) and the SEs of the
logORs as the SE (se). However, whilst the
Hi,
I have a problem with the time formatting in R. I have entered time in the
format MM:SS.xyz and R has automatically classified this as a factor, but I
need it numerically. However when I use as.numeric() it gives me totally
different numbers. Is there any way I can tell R to read thes
# depends on what you want to do with it.
# if you just want to convert to seconds, use the following
x - c('12:23.45', '34:15.1', '1:34.23')
# split by the :
x.s - strsplit(x, :)
# convert
x.c - sapply(x.s, function(a){
+ as.numeric(a[1]) * 60 + as.numeric(a[2])
+ })
x.c
[1] 743.45
Dear list,
I have a data frame with one column (group) and want to add a second column
(sub) with a serial number that says to which subgroup a cell belongs. A
subgroup contains the consecutive rows of the same group. The number of a
subgroup is based on its position in the table. The first
On Jul 19, 2010, at 9:37 PM, Steve McDonald wrote:
I'm a new user, so my apologies for what is likely a dumb question...
I am having a hard time getting a table of regression results when
using Koenker's code for quantile regression with fixed effects
On Jul 20, 2010, at 1:12 AM, Christian Raschke wrote:
On Tue, 2010-07-20 at 10:12 +1000, bill.venab...@csiro.au wrote:
As far as I know the answer to your question is No, but there are
things you can do to improve the readability of your code. One
thing I find useful is to avoid using $
If you submit these lines, you end up with variable vare.dis. I want
to export vare.dis to csv. Stuck I am.
library(vegan,logical.return = TRUE) #return=true verifies package is
available
library(MASS,logical.return=TRUE) #return=true verifies package is
available
data(varespec)
On Jul 20, 2010, at 7:33 AM, Sarah Chisholm wrote:
Hi,
I have a problem with the time formatting in R. I have entered time
in the format MM:SS.xyz and R has automatically classified this as
a factor, but I need it numerically. However when I use as.numeric()
it gives me totally
Hi,
I am trying to write a method for [,data.frame,expression. But it give the
error:
*
*
*Error in xj[i] : invalid subscript type 'expression'*
I looked at the help files and the archives. No avail. Any ideas? Here is
an example that reproduces the error.
setGeneric( '[' )
[1] [
On Jul 20, 2010, at 8:41 AM, David Winsemius wrote:
On Jul 20, 2010, at 7:33 AM, Sarah Chisholm wrote:
Hi,
I have a problem with the time formatting in R. I have entered time
in the format MM:SS.xyz and R has automatically classified this
as a factor, but I need it numerically. However
is there a way to specify a blank in a string with special/escape
characters?
like:
and now a blankand text after the blank,
where stand for the specification of the blank character
TIA
Mark
–––
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Hi all,
I have a dataframe with survey data. Now I want to calculate means from several
but not all columns (e.g. a1, a2, a3) and save them in a new separate column
(e.g. a).
Like: a = mean(a1, a2, a3)
Can someone help me or give me the right key word to look for?
Thanks
try this:
x - read.table(textConnection(group
+ A
+ A
+ A
+ B
+ B
+ A
+ A
+ B
+ B
+ B
+ A
+ A),header=TRUE, as.is=TRUE)
closeAllConnections()
# use rle to get the 'runs'
x.rle - rle(x$group)
# now generate the group numbers
x.grp - ave(x.rle$values, x.rle$values, FUN=seq_along)
# put the
On Tue, Jul 20, 2010 at 3:30 AM, John Kane jrkrid...@yahoo.ca wrote:
Assuming your data is in data.frame xx
library(reshape)
mm1 - melt(xx, id=c(ID))
cast(mm1, ID ~ variable )
On Jul 20, 2010, at 9:13 AM, Marcus Drescher wrote:
Hi all,
I have a dataframe with survey data. Now I want to calculate means
from several but not all columns (e.g. a1, a2, a3) and save them in
a new separate column (e.g. a).
Well that would be possible unless you are in Minitab or
On 20/07/2010 9:00 AM, Mark Heckmann wrote:
is there a way to specify a blank in a string with special/escape
characters?
like:
and now a blankand text after the blank,
where stand for the specification of the blank character
The answer to your question is yes, because you just
Dear List,
After much searching with no success, I would like to ask how I can
convert a unix/POSIX time (seconds since Jan 01, 1970) into a string
like 01/01/1970 00:00
This is probably easily done with a system(date...) but it would be
great if I could do it in R.
Kind Regards,
Jim
On Jul 20, 2010, at 9:25 AM, David Winsemius wrote:
On Jul 20, 2010, at 9:13 AM, Marcus Drescher wrote:
Hi all,
I have a dataframe with survey data. Now I want to calculate means
from several but not all columns (e.g. a1, a2, a3) and save them in
a new separate column (e.g. a).
Well
Hello all,
I am trying to write a program in R in which I call a function multiple
times within a loop. The problem is that sometimes the function breaks down
while calling another function, and produces an error message that breaks my
loop and the program stops. I would like to keep the loop
On Jul 20, 2010, at 9:26 AM, Jim Hargreaves wrote:
Dear List,
After much searching with no success, I would like to ask how I can
convert a unix/POSIX time (seconds since Jan 01, 1970) into a string
like 01/01/1970 00:00
This is probably easily done with a system(date...) but it would
On Jul 20, 2010, at 9:44 AM, Patrick McKann wrote:
Hello all,
I am trying to write a program in R in which I call a function
multiple
times within a loop. The problem is that sometimes the function
breaks down
while calling another function, and produces an error message that
breaks my
For nls, the fixing (or masking) of parameters is not, to my knowledge,
possible.
This is something I've been trying to get in such routines for over 2
decades. Masks are
available, but not yet well documented, in Rcgmin and Rvmmin packages.
However, these use
an optim() style approach, which is
will reformulate the question:
I use strsplit() to split a string at the blanks. e.g.
strsplit(Split at blanks, )
[[1]]
[1] Split at blanks
Now I would like to write something like a protected blank (like e.g.
in LaTex) into the string that does not get split
by strsplit() but
Mr. Feldman,
I would love nothing more than to reply to your wonderful email with just as
much sarcasm.
However, the fault lies with my question; I should have been more explicit.
It should have been phrased : Where can I find historical OVERNIGHT LIBOR
rates?
And surprisingly, we both use the
Hi,
I am new to clustering and was wondering why pvclust using maximum
as distance measure nearly always results in p-values above 95%.
I wrote an example programme which demonstrates this effect. I
uploaded a PDF showing the results
Here is the code which produces the PDF file:
Hi, you can define delimiters
strsplit(Split%at blanks, |%)
-
A R learner.
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Hi,
I'm using RGoogleDocs/RCurl to update a Google Spreadsheet. Everything
worked OK until this morning, when my ability to write into spreadsheet
cells went away. I get the following weird error:
Error in els[[type + 1]] : subscript out of bounds
Looking at the Google Docs API changelog, I see
Hi,
I am new to clustering and was wondering why pvclust using maximum
as distance measure nearly always results in p-values above 95%.
I wrote an example programme which demonstrates this effect. I
uploaded a PDF showing the results
Here is the code which produces the PDF file:
On 20/07/2010 10:09 AM, Mark Heckmann wrote:
will reformulate the question:
I use strsplit() to split a string at the blanks. e.g.
strsplit(Split at blanks, )
[[1]]
[1] Split at blanks
Now I would like to write something like a protected blank (like e.g.
in LaTex) into the string
This was just what I wanted, thanks!!
Am 20.07.2010 um 16:43 schrieb Duncan Murdoch:
On 20/07/2010 10:09 AM, Mark Heckmann wrote:
will reformulate the question:
I use strsplit() to split a string at the blanks. e.g.
strsplit(Split at blanks, )
[[1]]
[1] Split at blanks
Now I
Dear R-experts:
I am using survreg() to estimate the parameters of a Weibull density having
right-censored observations. Some observations are weighted. To do that I
regress the weighed observations against a column of ones.
When I enter the data as 37 weighted observations, the parameter
Thank you so much! And in package 'base' no less...exactly what I needed!
On Tue, Jul 20, 2010 at 8:55 AM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 20, 2010, at 9:44 AM, Patrick McKann wrote:
Hello all,
I am trying to write a program in R in which I call a function multiple
On Tue, 2010-07-20 at 08:24 -0400, Graves, Gregory wrote:
If you submit these lines, you end up with variable vare.dis. I want
to export vare.dis to csv. Stuck I am.
Hi Yoda ;-)
library(vegan,logical.return = TRUE) #return=true verifies package is
available
Hi,
I successfully created 3 screens with the following:
fig.mat-c(0,.5,.5,.5,1,1,0,0,.5,1,.5,1)
fig.mat-matrix(fig.mat,nrow=3)
fig.mat
split.screen(fig.mat)
I can plot three different plots on those 3 screens, but when I try the
following:
(Trying to create three graphs with a common x-axis
Hi R users,
I am a newbie and therefore the naive question. Sorry but I was unable
to find an answer online. I would like to read 47 data sets
(country1.raw, country2.raw, ... country47.raw) and save into a matrix
each time (data1, data2, data47).
for (i in 1:47){
data(?) -
Hello,
I need a possibility to print a function from R in Java with plot ().
I have taken rJava package and have built up a connection (with the JRI).
But if I call plot () in Java, a R_Graphics window (with R_Graphics:Device
2 (ACTIVE)) opens without contents. If I click this window, whole
Hi R users,
I am new in R. I would like to perform confirmatory factor analysis
for a data set of countries. My data are:
data - read.csv(ses.raw, header = TRUE)
attach(data)
names(data)
[1] idcntry momed daded dadocu momocu hompos finan
The country id is idcntry, my model is
Hi,
I am currently doing a project in which I wish to calculate the
calculate the theoretical price of options using the following models:
1. Constant Elasticity of Variance (CEV) model
2. Merton's jump diffusion model
3. Variance Gamma model
I am not sure as to how to implement this in R. I
Dear All,
I have a raster map of the class 'SpatialPointsDataFrame' and coordinates
of the class 'SpatialPoints'. I would like to retrieve the values that are
contained in the raster map at the specific locations given by the
coordinates.
Can anyone help me out?
Kind regards,
Katrin Fleischer
Hi R-experts,
I have been wasted aroun 2 days to understand Holt-Winter method for double
exponential smoothing.But concept was not clear to me.Please suggest me how
to determeine values of alpha ,beta,gamma.It is bit urgent .please help me
in understanding holtwinter parameter determination .
I
Hi Daniel,
Try this:
for(i in 1:47) {
assign(x = paste(data, i, sep = ),
value = read.csv(file.path(country, i, .raw, fsep = ), header = TRUE),
envir = .GlobalEnv)
}
See ?assign for documentation.
Cheers,
Josh
On Tue, Jul 20, 2010 at 4:52 AM, Daniel Caro dca...@googlemail.com wrote:
Hi there.
I bet this question have been answered many times, but I cant find a good
solution for my problem.
I would like to put a axis break (on y axis) on that flowing plot (let's say
between 20 and 80 in y).
y = c(runif(10, 1, 10), 100);
x = y + runif(11, 10, 50);
plot(x,y)
Is there any
Hi all,
Had struggled in getting Strata in randomForest to work on this.
Can I get randomForest for each of its TREE, to get ALL sample from some
strata to build tree, while leaving some strata TOTALLY untouched as oob?
e.g. in below, how I can tell RF to,
- for tree 1 in the forest, to use
On Tue, Jul 20, 2010 at 5:54 PM, Gavin Simpson gavin.simp...@ucl.ac.ukwrote:
On Tue, 2010-07-20 at 08:24 -0400, Graves, Gregory wrote:
If you submit these lines, you end up with variable vare.dis. I want
to export vare.dis to csv. Stuck I am.
Hi Yoda ;-)
I want THIS on fortune() !
Consider using a 'list' to hold the matrices:
dataList - lapply(1:47, function(num){
read.csv(paste('country', num, '.raw', sep=''), header=TRUE)
}
You can then access your data like:
dataList[[23]] for the 23rd file read in.
On Tue, Jul 20, 2010 at 7:52 AM, Daniel Caro
Here is a function I use to convert a numeric value of the UNIX time to POSIXct
unix2POSIXct - function (time) structure(time, class =
c(POSIXt, POSIXct))
On Tue, Jul 20, 2010 at 9:26 AM, Jim Hargreaves ja...@ipec.co.uk wrote:
Dear List,
After much searching with no success, I would
On Jul 20, 2010, at 11:20 AM, Charles Annis, P.E. wrote:
Dear R-experts:
I am using survreg() to estimate the parameters of a Weibull density
having
right-censored observations. Some observations are weighted. To do
that I
regress the weighed observations against a column of ones.
nas...@uottawa.ca wrote in message
news:33466.129.6.253.2.1279634282.squir...@webmail02.uottawa.ca...
For nls, the fixing (or masking) of parameters is not, to my knowledge,
possible.
This is something I've been trying to get in such routines for over 2
decades. Masks are
available, but not
R experts,
I have been unable to get the following ifelse statement to work as desired
when applied
to my data frame.
Example:
DF$ANYEF -
with(DF,ifelse(PSOUGHT1=='ANY'|PSOUGHT2=='ANY'|PSOUGHT3=='ANY',PEFF,0))
# this statement will be replicated 16 times for 16 unique _EF variables
On Tue, Jul 20, 2010 at 9:58 AM, nas...@uottawa.ca wrote:
For nls, the fixing (or masking) of parameters is not, to my knowledge,
possible.
This is something I've been trying to get in such routines for over 2
decades. Masks are
available, but not yet well documented, in Rcgmin and Rvmmin
David:
Thank you for your comments.
I do understand that absolute values of likelihoods by themselves aren't
meaningful, and only gain meaning when compared with others computed using
the same model but with differing parameter values (for example). That is
why I compute likelihoods myself for
Did you explore the fOptions package? Apart from lot of in-build
functionalities you would see there lot of good references on options
pricing.
Thanks,
--
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Hi Y'all,
I have some data in a table with 2 columns. There are two values: Reduction
and No Reduction. I am trying to make a new variable change which recode
the combinations from column 1 and 2 into a single number. Here is a snippet
from the table:
[1,] NoReduction
Thanks, Peter
This more or less corresponds to the solution I came to, modulo xyinch()
and atan2(x,y) = atan(x/y).
It is mostly intended as a replacement for arrows() in statistical
diagrams/plots where you want to
show a given range in a plot precisely without additional boundary lines.
It
Colleagues,
What is the easiest means to embed a:
® (registered)
or
™ (trademark)
sign in text in a graphic. I would like to use mtext and avoid plotmath, if
possible. Ideally, the sign should be superscripted but I can easily sacrifice
that.
Optimally, I need a solution that
You may want to take a look at the lavaan package and use the multigroup
analysis there (and see if you even need to group by country as well).
Otherwise, you could do something like
library(sem)
library(plyr)
cfa_func-function(a.df){
cfa-sem(ses.model, cov(a.df[,2:7], nrow(a.df)))
On Jul 20, 2010, at 1:14 PM, Heiman, Thomas J. wrote:
Hi Y'all,
I have some data in a table with 2 columns. There are two values:
Reduction and No Reduction. I am trying to make a new variable
change which recode the combinations from column 1 and 2 into a
single number. Here is a
litao.ext wrote:
I try to utilize some operations on rows in a matrix using command 'apply'
but find a problem.
First I write a simple function to normalize a vector (ignore error
handling) as follows:
normalize = function( v ) {
return( ( v-min(v) ) / ( max(v) - min(v) ) )
}
I don't know if this works in OSX, but in XP:
plot(0)
title('\u00ae - \u2122')
On Tue, Jul 20, 2010 at 2:22 PM, Dennis Fisher fis...@plessthan.com wrote:
Colleagues,
What is the easiest means to embed a:
® (registered)
or
⢠(trademark)
sign in text in a graphic. I
Try this, assuming your data is consistent:
x - read.table(textConnection('NoReduction NoReduction
+ ReductionReduction
+ NoReduction NoReduction
+ NoReduction NoReduction
+ ReductionReduction
+ Reduction
Hi Mike,
Probably the simplest way from what you have done would be to just set
any NA values in the column to 0:
DF$ANYEF[is.na(DF$ANYEF)] - 0
Alternately, you can try this. It should work, but it is far from elegant.
DF$ANYEF - with(DF, ifelse(
rowSums(cbind(PSOUGHT1, PSOUGHT2, PSOUGHT3)
Thank you very much for your effort!
But is there a measure, which can compare the goodness of fit of regression
models with and without the intercept? Can I only compare them in terms of
sum of squares residual?
--
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Works on OSX 10.5.8 + R2.11.1
--
David.
On Jul 20, 2010, at 1:36 PM, Henrique Dallazuanna wrote:
I don't know if this works in OSX, but in XP:
plot(0)
title('\u00ae - \u2122')
On Tue, Jul 20, 2010 at 2:22 PM, Dennis Fisher
fis...@plessthan.com wrote:
Colleagues,
What is the easiest
Dears,
do you know whether it is possible to include any square parantheses (brackets)
in an expression to use it as an axis label?
e.g. I would like to have a label like (with the sub and superscripts correct):
speed [m s^-1]
I know how to combine an expression with text via paste, but as I
On Jul 20, 2010, at 12:42 PM, Jannis wrote:
Dears,
do you know whether it is possible to include any square parantheses
(brackets) in an expression to use it as an axis label?
e.g. I would like to have a label like (with the sub and
superscripts correct):
speed [m s^-1]
Not exactly
On 20/07/2010 12:42 PM, Jannis wrote:
Dears,
do you know whether it is possible to include any square parantheses (brackets)
in an expression to use it as an axis label?
e.g. I would like to have a label like (with the sub and superscripts correct):
speed [m s^-1]
I know how to combine an
I found a form of the if statement that works but it is very long. I'm
attempting to check the value of of two different variables to see if
they evaluate to either of two different values, which will result in a
division by 0 in the final equation. This first if statement works for me
plotrix can do it.
There is a post about axis break.
http://r.789695.n4.nabble.com/template/NodeServlet.jtp?tpl=replynode=2295499
-
A R learner.
--
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http://r.789695.n4.nabble.com/Y-axis-break-tp2295499p2295998.html
Sent from the R help mailing list archive at
On Mon, Jul 19, 2010 at 11:12 PM, Christian Raschke
cras...@tigers.lsu.edu wrote:
snip
but in the end I have other cases, where the logical vector is
obtained from other operations or where the value that is assigned is
different case by case; for example,
I try to utilize some operations on rows in a matrix using command 'apply'
but find a problem.
First I write a simple function to normalize a vector (ignore error
handling) as follows:
normalize = function( v ) {
return( ( v-min(v) ) / ( max(v) - min(v) ) )
}
The function works fine for
Hi,
I could not locate library ts in the CRAN website. Please help.
Yolande
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Dear R users,
I have some question about Varimax rotation of the loadings obtained from a
PCA.
Imagine X is a field where the rows are the observations and the columns are
the variables. I obtain the loadings (L), the principal components (PC) and
the percentage of the variance for each mode
Hi there,
I entered over 2000 lines of data into R from SQLite and saved it in R as a
data.frame, but the data.frame only gives the first 500 lines. Is there any
way to either increase the default limit or to determine which of the
original lines should be in the output (e.g. maybe the last 500
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