On Aug 20, 2013, at 3:04 PM, David Winsemius wrote:
On Aug 20, 2013, at 12:06 PM, Beaulieu, Jake wrote:
Hi,
I would like to include the greek letter mu, in italics, in an axis title.
The following gets close, but the mu isn't italicized.
x - 1:10
y - 1:10
plot(y ~x, ylab =
Hello James,
Does this answer your question:
http://stackoverflow.com/questions/14956887/problems-executing-script-from-command-line-in-r-error-message-cannot-find-pat
?
Contact
Details:---
Contact me: tal.gal...@gmail.com |
Just a quick note, mainly to warn off maintainers of the recommended packages,
that we intend to release R-3.0.2 on Wednesday, September 25.
We'll be following the usual schedule from
http://developer.r-project.org/release-checklist.html
Notice in particular that new versions of recommended
On 22/08/2013 09:24, Sachinthaka Abeywardana wrote:
Hi all,
I get the expected behaviour of getting a useful model if I do the following
This is an 'expectation problem', not a 'stepAIC problem'.
And stepAIC is not part of R and you are not crediting the tools you use.
fit-lm(
Tal,
please quote the whole message!
I had to look for the original one now.
And then I found that code was not reproducible for me:
exe_URL = 'http://pandoc.googlecode.com/files/pandoc-1.11.1.msi'
exe_filename - file.path(tempdir(), file.name.from.url(exe_URL))
Error in
I have a 70363 x 5 double matrix that I am playing with.
head(df)
GR SP SN LN NEUT
1 1.458543 1.419946 -0.2928088 -0.2615358 -0.5565227
2 1.432041 1.418573 -0.2942713 -0.2634204 -0.5927334
3 1.406642 1.418226 -0.2958296 -0.2652920 -0.6267121
4 1.382284
On Aug 22, 2013, at 7:39, Ben Harrison h...@student.unimelb.edu.au wrote:
I have a 70363 x 5 double matrix that I am playing with.
head(df)
GR SP SN LN NEUT
1 1.458543 1.419946 -0.2928088 -0.2615358 -0.5565227
2 1.432041 1.418573 -0.2942713 -0.2634204
Below are two ways to accomplish this. The last() function will not
pad with NA if you request more days than available, so you may need
to handle that if it's an issue. I prefer the period.apply method
because it keeps the data in an xts object, which I find easier to
work with.
From POSIXct to numeric and back with time zone
I am running regressions on data which has time series with different time
resolution. Some data has hourly resolution, while most has either daily or
weekly resolution. Aggregation is used to make the hourly data daily, while
liner
Hello,
I must tell you once again to address your questions to
r-help@r-project.org
And since there was no subject line, I've made up one.
Your question seems to be a question about excel, and I really can't
help you. Maybe someone else can.
But if you write.table(etszP) can't you read that
This works:
expression(paste('Greek', italic('\uo3bc'))
thanks!
Jake
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Thursday, August 22, 2013 2:01 AM
To: David Winsemius
Cc: Beaulieu, Jake; r-help@r-project.org
Subject: Re: [R] italic(mu)
On Aug 20,
Issue:
Usage of ETS R codes through RExcel macros in VBA
Given below is my command code:
Rinterface.runrcodefromrange Range(“Sheet1!B2:D8”)
Following are the codes written in the given cell reference:
#!rput zz 'Sheet1'!$B$2:$B$22
library(forecast)
zz -
HI Samuel,
Based on the output you wanted:
(It would be better to use ?dput() to show the example dataset)
dat1- structure(list(SiteID = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L), SiteName = c(Big Platte Lake, Big Platte Lake,
Big Platte Lake, Big Platte Lake, Big Platte
Hi,
Also, you could use:
library(data.table)
dt1- data.table(dat1,key=c('SampDate','DepthM'))
unique(dt1)
# SiteID SiteName SampDate DepthM PDesc MAbbr Measure DNU
#1: 1 Big Platte Lake 2006-09-20 0.000 TP Grab 6.58 FALSE
#2: 1 Big Platte Lake 2006-09-20 2.286
Hello,
I am trying to plot a few correlograms on the same figure, with the function
corrgram() from the package corrgram. However, the function does not seem to
use the base graphic system, as setting out the multiple figure layout with,
e.g., par(mfrow=c(2, 2,)) does not work.
Does anybody
Hi!
I am looking to choose a condom based on its pleasure score.
I received some summarised data from 10 individuals:
structure(list(Ramses = c(4, 4, 5, 5, 6, 3, 4, 4, 3, 4), Sheiks = c(5,
5, 6, 4, 7, 6, 4, 5, 6, 3), Trojans = c(7, 8, 7, 9, 6, 3, 2,
2, 2, 3), Unnamed = c(2, 1, 1, 3, 3, 4, 5, 4,
This is not on topic for this mailing list. See the Statconn website for
support for RExcel.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#.
Free support for RExcel is available by subscribing to the mailing list at
rcom.univie.ac.at
and posting questions to the list.
On Aug 22, 2013, at 7:04 PM, Jeff Newmiller jdnew...@dcn.davis.ca.us wrote:
This is not on topic for this mailing list. See the Statconn website for
support for
Dear Uwe,
Here is the updated code and error massage I get:
exe_URL = 'http://pandoc.googlecode.com/files/pandoc-1.11.1.msi'
exe_filename - file.path(tempdir(), basename(exe_URL))
download.file(exe_URL, destfile = exe_filename, mode = wb, method=
internal)
#
### Error massage:
trying
I have the following code and data
data.csv
,Goal,Frequency,Weight,Group
1,Move,13,0.245283018867925,Public
2,Create,10,0.188679245283019,Public
3,Strengthen,30,0.566037735849057,Public
4,Move,6,0.6,Board
5,Create,0,0,Board
6,Strengthen,4,0.4,Board
7,Move,19,0.301587301587302,Total
I used the codes below trying to fit a model at .95 c.i. of size relationship
but it fails.
library(quantreg)
range(len$length)
range(len$preyl)
x-rq(len$preyl~len$length,tau=0.95)
plot(x, type=b, xlab=length (cm),ylab=preyl (cm),ylim=c(5,35),
xlim=c(10,100), data=len)
Cheers,
Nuru
Quick update - I think most of the problem is resolved.
After more checks (following Uwe comments):
1) I see that the installer file runs properly when I set mode='wb', and
fails when mode='w' (so that solves why some of the time the installer
didn't run)
2) I still get the error massage mentioned
It is not hard to create a basic function for that purpose:
map.vec - function(x, y) {
dfa - data.frame(a=x, x0=rep(1, length(x)),
y0=length(x):1)
dfamap - data.frame(a=y, x1=rep(2, length(y)),
y1=length(y):1)
vec - merge(dfa, dfamap, by=1)
Dear all,
I have a plot with two lines and I'm using labcurbe (package Hmisc) to show
the legend.
Everything works well, except that the line displayed in legend box should
have same style (plotting character) as the line in the plot. This is
achieved by pch parameter and looks like that it's only
*Issue:*
Usage of ETS R codes through RExcel macros in VBA
Given below is my command code:
Rinterface.runrcodefromrange Range(Sheet1!B2:D8)
Following are the codes written in the given cell reference:
#!rput
zz
'Sheet1'!$B$2:$B$22
library(forecast)
zz -
Dear R-users
I applied vegan's varpart function to partition the effects of
explanatory matrices. Adj. R square for the unique fraction [a] is
0.25. Does anyone know why the decomposition by hand using rda gives
me a different result for [a] (constrained proportion is 0.32)? I used
On Aug 22, 2013, at 9:23 AM, Garkuwa, Nuru Adamu wrote:
I used the codes below trying to fit a model at .95 c.i. of size relationship
but it fails.
library(quantreg)
range(len$length) # [1] 28 98
range(len$preyl)
x-rq(len$preyl~len$length,tau=0.95)
plot(x, type=b, xlab=length
On 22.08.2013 19:52, Tal Galili wrote:
Dear Uwe,
Here is the updated code and error massage I get:
exe_URL = 'http://pandoc.googlecode.com/files/pandoc-1.11.1.msi'
exe_filename - file.path(tempdir(), basename(exe_URL))
download.file(exe_URL, destfile = exe_filename, mode = wb, method=
Dear R-help list members,
Version 2.0-0 of the Rcmdr package is now on CRAN and should appear
presently on the various CRAN mirrors. As its number implies, this version
represents a milestone in the development of the package, which first
appeared on CRAN more than 10 years ago. The transition to
On 08/23/2013 04:32 AM, Jie wrote:
Dear All,
I would like to draw a graph to illustrate the mapping between two vectors.
For instance,
a = c(2, 8, 5) ; mapped.a = c(8, 2, 5)
I would like to get some picture as
http://www.flickr.com/photos/96546690@N02/9569526581/
Basically, plot all points of
On Wed, 21 Aug 2013 10:35:53 -0400
SH empti...@gmail.com wrote:
It looks like your problem has already been answered, however, as a
rule of thumb anytime you see a peculiarity like this you should look
for minor variations between what you expected to export and what Excel
really exported as
I tried your suggestion on the toy example that was posted by David Carlson
a while back:
set.seed(42)
x - 1:15
y - x/(1+x) + rnorm(15,0,0.02)
I found that I had to:
(a) Wrap the 1/x inside I().
(b) Set the offset term to be rep(1,length(x)).
Bottom line:
fit - glm(y ~
On Aug 22, 2013, at 4:17 PM, Jim Lemon wrote:
On 08/23/2013 04:32 AM, Jie wrote:
Dear All,
I would like to draw a graph to illustrate the mapping between two vectors.
For instance,
a = c(2, 8, 5) ; mapped.a = c(8, 2, 5)
I would like to get some picture as
On 22/08/13 21:57, Michael Weylandt wrote:
On Aug 22, 2013, at 7:39, Ben Harrison h...@student.unimelb.edu.au wrote:
No idea about the problem specifics but what are your OS and version of R? You
might be limited there.
I have 64-bit Ubuntu 12.04, R version 3.0.1.
More likely,
Dear all,
I have a couple of questions regarding the survival:::cch function.
1) I notice that Prentice and Self-Prentice functions are giving identical
standard errors (not by chance but by programming design) while their estimates
are different. My guess is they are both using the
Hello Joshua:
First of all, I thank you for the solution. The solution is quite
elegant and concise. I have one follow-up question/comments. Everything
seems ok but the problem comes if the last month stops somewhere in the
middle of the month. For instance, if I run the data as of
Hello,
I am confused with the design of experiment and I need your help. I study
macroinvertebrates from 40 lakes. Each lake was sampled employing stratified
random technique. Each lakes was divided into 3 different lake zones based on
light penetration: near-shore area, transitional, and the
Dear all,
I have a couple of questions regarding the survival:::cch function.
1) I notice that Prentice and Self-Prentice functions are giving identical
standard errors (not by chance but by programming design) while their beta
estimates are different. My guess is they are both using
for example I have data frame m as below:
m=as.data.frame(outer(1:5,6:9))
colnames(m)=c('a','b','c','d')
and I define the function
myf=function(df, colname){
suppose colname is a, then:
how can I get the column 'a'
and how to get the colname as a string, 'a'
}
Thank you!
m=as.data.frame(outer(1:5,6:9))
colnames(m)=c('a','b','c','d')
tf=function(df, col){list(mean(eval(substitute(col),df,parent.frame())),col
)}
tf(m,a) will issue error: Error in tf(m, a) : object 'a' not found
How can I replace the col as char 'a' in the function?
Thank you
Please don't post in HTML format... it messes with code examples.
Use character indexing (please read the Introduction to R... again if
necessary).
myf - function(df, colname){
df[ ,colname ]
}
colname - a
myf(m,colname)
Until you learn simple R syntax, I strongly recommend avoiding
Hi all R mailing listers:
I am using the coda package. I tried to view the source of HPDinterval code
by typing fix(HPDinterval), it dispalys as follows:
function (obj, prob = 0.95, ...)
UseMethod(HPDinterval)
Then I search the answers about this case (see below), it still failed.
Thank you in
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