Re: [R] unable to download library

> On 17 Dec 2015, at 01:05 , David Winsemius wrote: > >> >> On Dec 16, 2015, at 3:44 PM, peter dalgaard wrote: >> >> >>> On 17 Dec 2015, at 00:00 , David Winsemius wrote: >>> >>> When I attempt to open that with Chrome I

Re: [R] Applying a function to a matrix using indexes as arguments

Also A %*% t(B) / C Which works because when a vector is converted to a matrix, it becomes a 1-column matrix. The documentation for t() points this out but there is a typo: "When x is a vector, it is treated as a column, i.e., the result is a 1-row matrix." Should be a "1-column matrix" >

Re: [R] Stop the notices about the r-forum

On Thu, Dec 17, 2015 at 6:30 AM, bruno higa wrote: > Hey, i cant stop the emails about the forum, i delete my account and i want > it. Can you help me ? Att. > [[alternative HTML version deleted]] > > __ >

Re: [R] Filtering Cases with != NA

You need the is.na() function: > dataset <- data.frame(No = 1:4, Name = c("Smith", "Mayor", "Miller", > "Baltic"), Turnover = c(1500, 200, NA, 750)) > dataset No Name Turnover 1 1 Smith 1500 2 2 Mayor 200 3 3 Miller NA 4 4 Baltic 750 [1] TRUE TRUE FALSE TRUE >

[R] Filtering Cases with != NA

Dear All, I am new to "R" and search for a solution to exclude cases if a certain variable contains NA for a case. Example No Name Turnover 1 Smith 1500 2 Mayor 200 3 Miller 4 Batic 750 I would like to create a subset excluding case 3 Miller NA. I tried to following: new_dataset <-

Re: [R] Filtering Cases with != NA

use the 'is.na' function: new_dataset <- subset(dataset, subset = !is.na(Turnover)) Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Thu, Dec 17, 2015 at 7:50 AM, wrote: > Dear

[R] Variable Selection for Logistic Regression

Hi, I have a dataset with approx 400K Rows and 900 columns with a single dependent variable of 0/1 flag. The independent variables are both categorical and numerical. I have looked as SO/Cross Validated Posts but couldn't get an answer for this. Since I cannot try all possible combinations of

Re: [R] Filtering Cases with != NA

On Thu, Dec 17, 2015 at 01:50:29PM +0100, g.maub...@weinwolf.de wrote: > Dear All, > > I am new to "R" and search for a solution to exclude cases if a certain > variable contains NA for a case. > ... > I would like to create a subset excluding case 3 Miller NA. > > I tried to following: > >

Re: [R] Applying a function to a matrix using indexes as arguments

> On Dec 17, 2015, at 8:38 AM, David L Carlson wrote: > > Also > > A %*% t(B) / C > Which would be equivalent to: > outer(A, B)/C [,1] [,2] [,3] [1,] 10863.03 -14390.53 -287691.41 [2,] -127580.06 -13576.77 83597.56 And perhaps even more

[R] Gather columns based on multiple columns using tidyr

Hi, Sorry for this direct approach but I am stuck with a stupid data that I would like to reformat. The datafile is location at: fileURL <- http://www.metoffice.gov.uk/pub/data/weather/uk/climate/datasets/Rainfall/ranked/Scotland.txt You can read the data by:

Re: [R] Gather columns based on multiple columns using tidyr

Hi Fahad, Easier than what? You didn't tell us what you tried, nor why you were unhappy with it. I'm only passingly familiar with tidyr, but I came up with library(tidyr) library(dplyr) read.table("scotland_rainfall.txt", skip = 7, header=TRUE, fill = TRUE) %>% select(-WIN, -SPR, -SUM, -AUT,

Re: [R] Variable Selection for Logistic Regression

Lasso is an obvious choice by it may also be interesting to look at the variable importance from a random forest model On 17 Dec 2015 17:28, "Manish MAHESHWARI" wrote: > Hi, > > I have a dataset with approx 400K Rows and 900 columns with a single > dependent variable of 0/1

Re: [R] Error in linear regression

> On Dec 17, 2015, at 7:58 PM, Saba Sehrish wrote: > > Hi > > Please find the attachment with (.txt) extension and I hope the command is > visible now. > > library(lmtest) Why is this library loaded? I see no calls to functions from that package. >

Re: [R] Cannot subset a specific mean from this function

Hi Bradley, I think I can see one or two reasons why you are getting creamed. First, pollutantmean is a function, and there is no method for taking the mean of a function. Second, nitrate is unlikely to be an extractable element of pollutantmean given the above code (that's the error). I

Re: [R] Help needed in plotting 2d histogram

Hi Saikat, I don't know whether this can be done with ggplot, but if you don't get another answer, have a look at the second example for the "barp" function in the plotrix package. This shows how to get a specified range on the color legend using the "xrange" argument. Jim On Fri, Dec 18, 2015

[R] Help needed in plotting 2d histogram

Hello. I have more than one phi-psi time series data files each having 5 time points. I am trying to create density plots (2d histograms) for each and then I would like to compare them. But to be able to compare one plot with the other I need to have similar colour densities (i.e colour

[R] Would you please help me to create a table in R?

Hi R users, I am struggling to create a table in R. I did in Excel but I have a lots of data and thought it might be easy in R but I am new in R. How to get "output table" for this example data? This is an example. # raw.data<-structure(list(Time1 = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L,

[R] Cannot subset a specific mean from this function

HI, I am very new to R (and programming in general) and am taking a class in it now. I am getting creamed. I want the last part of the function statement below to give me the mean of the data set of nitrates. When I do it I get an error statement stating: Error in pollutantmean$nitrate :

Re: [R] Would you please help me to create a table in R?

Hi Marna, A bit hard to understand. If raw.data is a record of 11 individuals released at site A at Time 1 and recaptured at either A or B or neither at Time2 or Time3, it doesn't seem to bear any consistent relationship to the numeric coding in table.format or the output at the bottom. Could you

[R] How to use the options "usecommand" and "command" of tktable?

How to capture the output from the "command" option of tktable and how to send input to it? As far as I understand, the most appropriate way to use the tktable is through the flag usecommand and command. It fires the string information and cell coordinates and wait for a new string to set a

[R] Course: Introduction to GAM and GAMM

We would like to announce the following statistics course: Course: Introduction to GAM and GAMM Where: University of Konstanz, Konstanz, Germany When: 7-11 March 2016 Course website: http://www.highstat.com/statscourse.htm Course flyer: http://highstat.com/Courses/Flyer2016_03Konstanz.pdf

Re: [R] Converting from Continuous 2D Points to Continuous 2D Vectors

Ok. And what is the problem now? B. On Dec 17, 2015, at 4:25 PM, Sidoti, Salvatore A. wrote: > Greetings! > > I have a fairly large dataframe (df) with pathing information in the form of > continuous x,y coordinates: > > df$x > df$y > > With these data, I

Re: [R] Error in linear regression

Hi Please find the attachment with (.txt) extension and I hope the command is visible now. library(lmtest)data<-read.csv(file="---",header=T,sep=",")A<-as.matrix(data$DODGX)B<-as.matrix(data$TRMCX) nrow<-nrow(A)A1<-matrix(NA,nrow,1)A2<-matrix(NA,nrow,1) A3<-matrix(NA,nrow,1) A4<-matrix(NA,nrow,1)

Re: [R] NIPALS & categorical variables

Hi Hana, If you are using nipals from the plsdepot package, the answer seems to be maybe. If your categorical variables are at least ordinal level, and you can arrange the values so that the factor numbering reflects this, it may be possible to use the numeric values. "...the variables are

Re: [R] Applying a function to a matrix using indexes as arguments

Hi David, that's a great answer, thanks so much. I imagined apply() was involved in the solution, but I was unable to find how myself. Thanks again. Matteo On 17 December 2015 at 01:37, David Winsemius wrote: > > > On Dec 16, 2015, at 5:34 PM, David Winsemius

Re: [R] Gather columns based on multiple columns using tidyr

Here's another approach, but it doesn't use tidy or dplyr: > Rain.col <- seq(1, 24, by=2) > Year.col <- seq(2, 24, by =2) > Scotland.lst <- lapply(1:12, function(x) data.frame(Year = + scotland_weather[ , Year.col[x]], month = month.abb[x], + rainfall_mm = scotland_weather[ ,

Re: [R] Error in linear regression

> On Dec 17, 2015, at 1:13 PM, Saba Sehrish via R-help > wrote: > > Hi I am trying to apply linear regression on the attached data The is no attached data; please read the posting guide. Do not post with .csv or .doc files. You can have commas as separators but an

Re: [R] Hexbin: Counting Bins That Meet Certain Criteria

Thank you, David! I adapted this code and it works very nicely with my data. Just to give you a bit of background, I am a behavioral ecologist. I am currently studying the general search patterns of wolf spiders and I have a lot of tracking data to process. I am not a coder, although I am

[R] Converting from Continuous 2D Points to Continuous 2D Vectors

Greetings! I have a fairly large dataframe (df) with pathing information in the form of continuous x,y coordinates: df$x df$y With these data, I would like to: 1. Calculate a set of continuous vectors 2. Determine the angle between each of these vectors (in degrees) 3. Count the number of

[R] Error in linear regression

Hi I am trying to apply linear regression on the attached data of two variables (DODGX, TRMCX) in R by taking into account time lag=5 for both of them. Each time I run this command, it gives me following error: Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) :  

[R] Error-linear regression

Hi  I am trying to apply linear regression on the attached data of two variables (DODGX, TRMCX) in R by taking time lag=5 for both of them. Each time I run this command, it gives me following error: Error in lm.fit(x,y,offset = offset, singular.ok = singular.ok, ...) :  NA/NaN/lnf in 'y'  In

Re: [R-es] Añadir encabezados a un archivo TXT

Hola Gerard, En Windows puedes hacer lo siguiente: Suponiendo que "fichero.txt" es el archivo de texto con tus variables, que se encuentra en el directorio de trabajo [compruébalo con dir()] y que "nombres" es un vector que tienes en R con los nombres que quieres poner a las variables de

Re: [R-es] Añadir encabezados a un archivo TXT

Gerard, dos preguntas: 1) Porqué quieres directamente especificar los encabezados en el fichero? Es porqué tus ficheros no tienen las columnas igualmente ordenadas? 2) Qué sistema operativo tienes? Un saludo. Olivier - Mensaje original - De: "Reverté Calvet, Gerard"