Dear all
I have a question about debug function. I did not use it for long time but my
vague memory tell me, that when I used debug(myfunction) in past, only
myfunction was debugged and browser ignored any embedded function.
example (simple)
fff <- function(x) mean(x, na.rm=T)
when I issue
>
On 06/06/2019 4:55 a.m., PIKAL Petr wrote:
Dear all
I have a question about debug function. I did not use it for long time but my
vague memory tell me, that when I used debug(myfunction) in past, only
myfunction was debugged and browser ignored any embedded function.
example (simple)
fff <-
Thanks Duncan.
I think you found it. I have an object called s within my function. I wanted to
check it, so I hit "s". This did not bring the object but instead it change
behaviour of debug function. I did not find this in help pages nor in R exts or
R intro manual. Maybe it would be worth cons
Hello,
You are confusing some of the values of L1 with L1 itself.
If you just want two of those values in your plot, "onepctCO2MEDIAN" and
"RCP8.5MEDIAN", you need to subset the data filtering out the rows with
L1 == "RCP4.5MEDIAN".
And please forget geom_jitter, it is completely inappropriat
On Wed, 5 Jun 2019 18:07:15 +0200
Frank Schwidom wrote:
> +> path.expand("a ~ b")
> [1] "a /home/user b"
> How can I switch off any file crippling activity?
It doesn't seem to be possible if readline is enabled and works
correctly.
Calls to path.expand [1] end up [2] in R_ExpandFileName [3],
On Mon, 3 Jun 2019 06:37:46 +0200
Nicola Lunardon wrote:
> R seems to be running, but simulations do not progress further.
Have you tried message() (or REprintf() in C code) to narrow down the
specific part of the code where simulations stop in their progress?
It's less convenient than a good de
On 06/06/2019 6:00 a.m., PIKAL Petr wrote:
Thanks Duncan.
I think you found it. I have an object called s within my function. I wanted to check it,
so I hit "s". This did not bring the object but instead it change behaviour of
debug function. I did not find this in help pages nor in R exts or
Hi Rui (and everyone),
Thank you for this! Yes, this did work fine, as I can see my scatter plots and
regression lines on the same plot, along with the appropriate coloring scheme!
:)
Just one last question concerning this - I melted other dataframes into my new
"NewestdataUltra". I now have 4 o
> Duncan Murdoch
> on Thu, 6 Jun 2019 07:38:40 -0400 writes:
> On 06/06/2019 6:00 a.m., PIKAL Petr wrote:
>> Thanks Duncan.
>>
>> I think you found it. I have an object called s within my function. I
wanted to check it, so I hit "s". This did not bring the object but
Hi
Probably missing quotation marks in geom_smooth
geom_smooth(method = "lm", se = FALSE)
Cheers
Petr
> -Original Message-
> From: R-help On Behalf Of rain1290--- via R-
> help
> Sent: Thursday, June 6, 2019 4:35 PM
> To: ruipbarra...@sapo.pt; r-help@R-project.org
> Subject: Re: [R] Pl
Is there any way of taking a line of r code (eg y<-x^2) and pasting that line
of code, as is, into a label, so that for example I could then have a plot
label "Plot of y<-x^2"?
Thanks Nick Wray
[[alternative HTML version deleted]]
__
R-help@r
Hello,
1) In the text you say your dataset is named NewestdataUltra but in the
ggplot instruction it's Newestdata. One of these is wrong.
2) Is it onepctCO2MEDIAN or RCPonepctCO2MEDIAN?
3) You are filtering out the value in point ) above. So you only plot 3
regression lines, you don't need 4
> On Jun 6, 2019, at 11:19 AM, Nick Wray via R-help
> wrote:
>
> Is there any way of taking a line of r code (eg y<-x^2) and pasting that line
> of code, as is, into a label, so that for example I could then have a plot
> label "Plot of y<-x^2"?
>
> Thanks Nick Wray
Hi,
See ?plotmath
A
Hi Rui,
Yes, you are right. It should be this, but I tried with only 3 colors, as you
suggested:
ggplot(subset(NewestdataUltra, L1 != 'onepctCO2MEDIAN'), aes(x, value, colour =
L1)) + geom_point() + scale_color_manual(values =c("green", "blue" "red")) +
geom_smooth(method = lm, se=FALSE)
I stil
Hello,
It's impossible to say without seeing the data.
What is the return value of
df_tmp <- subset(NewestdataUltra, L1 != 'onepctCO2MEDIAN')
unique(df_tmp$L1)
The number of colors must be the same as
length(unique(df_tmp$L1))
Hope this helps,
Rui Barradas
Às 16:49 de 06/06/19, rain1...@a
The well known deparse(substitute(...)) construction.
plot(1:9, main = paste("plot of",deparse(substitute(y <- x^2
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip
Thanks but that's not quite what I meant
I am trying out different functions and they don't necessarily vary in a
regular way (like say all being powers of x where it'd be simple to just have a
vector for the powers you want)
So I might have
y<-x^2
y<-cos(x)
y<-exp(x+1)
What I am after is a way o
... and if you wanted too streamline the process, something like the
following could be encapsulated in a function:
fun <- quote(exp(x))
z <- 1:9
y <- eval(fun,list(x = z) )
plot(x, y, main = paste("Plot of y =", deparse(fun)))
Further details can be found in the "Computing on the Language" secti
Thanks Bert, that is exactly what I wanted. I think that you meant plot(z,y...
in the last line?
Nick
> On 06 June 2019 at 17:13 Bert Gunter wrote:
>
> ... and if you wanted too streamline the process, something like the
> following could be encapsulated in a function:
>
> fun <- qu
> On Jun 6, 2019, at 3:59 AM, Ivan Krylov wrote:
>
> On Wed, 5 Jun 2019 18:07:15 +0200
> Frank Schwidom wrote:
>
>> +> path.expand("a ~ b")
>> [1] "a /home/user b"
>
>> How can I switch off any file crippling activity?
>
> It doesn't seem to be possible if readline is enabled and works
>
Hi Rui,
NewestdataUltra looks like this (Note that "HistoricalMEDIAN" is hidden, but it
follows "RCP8.5MEDIAN" listing the same way):
x variable value L1
1 0.0y 0. onepctCO2MEDIAN
2 0.006794447y 4.90024902 onepctCO2MEDIAN
3
Yes, plot(z,y,..)
Bert
On Thu, Jun 6, 2019 at 9:21 AM Nick Wray wrote:
> Thanks Bert, that is exactly what I wanted. I think that you meant
> plot(z,y... in the last line?
>
> Nick
>
> On 06 June 2019 at 17:13 Bert Gunter wrote:
>
> ... and if you wanted too streamline the process, something
See here for almost the same issue:
http://r.789695.n4.nabble.com/Pasting-R-code-lines-into-labels-td4757446.html
Same answer: pass the unevaluated formula (i.e. an R expression) using
substitute/quote. Then evaluate it appropriately using eval. Same
references.
Bert Gunter
"The trouble with ha
It is perhaps worth saying that my prior suggestion may not be the best
strategy for doing what you want. The previous poster needed the actual
expression to deparse as a label. If you only need the expression as a
function to be evaluated, it may be better to pass the argument as a
function -- a f
Hi,
Sorry for the misfire on the first attempt.
After seeing the clarifications, I thought about a possible way to do this,
perhaps a little more simply, while encapsulating the plotting in a function:
plotFx <- function(x, fun) {
plot(x, fun(x), main = paste0("Plot of y = ", deparse(fun)[2])
Hello,
Try this.
values_to_plot <- c("onepctCO2MEDIAN", "RCP4.5MEDIAN", "RCP8.5MEDIAN")
sub_df <- subset(NewestdataUltra, L1 %in% values_to_plot)
ggplot(sub_df, aes(x, value, colour = L1)) +
geom_point() +
scale_color_manual(values = c("green", "red", "blue")) +
geom_smooth(method = lm)
The first idea works perfect.
Thank you!.
El mié., 5 jun. 2019 a las 1:07, peter dalgaard ()
escribió:
> Two ideas:
>
> nn <- names(wageszm14)
> lvadd <- nn[grep("^lvacb", nn)]
>
> or
>
> lvadd <- paste0("lvacb", 23:81)
> lvadd <- lvadd[lvadd %in% names(wageszm14)]
>
> > On 5 Jun 2019, at 06:46
Technically "opening" a file does not involve reading it into memory at all, so
any limits would arise from the OS.
As for "reading" the file, the amount of virtual memory [1] is the key factor,
but different file formats can require more or less overhead memory to parse
the data. Also, differe
Hi Rui,
Yes! This worked just fine! Thank you so, so much for your time and patience!
-Original Message-
From: Rui Barradas
To: rain1290 ; r-help
Sent: Thu, Jun 6, 2019 3:25 pm
Subject: Re: [R] Plotting more than one regression line in ggplot
Hello,
Try this.
values_to_plot <- c("o
Well, if you want to do it this way, note that as written, the y axis
default label isn't "nice," and you should anyway allow for additional
graphical arguments (either way). Also, slightly better I think is to use
the built-in access function, body():
plotFx <- function(x, fun, ...) {
plot(x,
How can expanding tildes anywhere but the beginning of a file name NOT be
considered a bug?
On Thu, 6 Jun 2019 at 23:04, Ivan Krylov wrote:
> On Wed, 5 Jun 2019 18:07:15 +0200
> Frank Schwidom wrote:
>
> > +> path.expand("a ~ b")
> > [1] "a /home/user b"
>
> > How can I switch off any file cri
On 06/06/2019 5:04 p.m., Richard O'Keefe wrote:
How can expanding tildes anywhere but the beginning of a file name NOT be
considered a bug?
It looks like a bug in R, but not necessarily a bug in libreadline: we
may just be using tilde_expand improperly.
Duncan Murdoch
On Thu, 6 Jun 2019
These look like very fragile suggestions. Allow x^2 to be an argument
(named expr, for example) to plotFx, don't force a user to write a
function in a very particular way. Then use deparse(substitute(expr))
in the title.
Duncan Murdoch
On 06/06/2019 4:33 p.m., Bert Gunter wrote:
Well, if y
Hello Guys!
I am wondering about below function which automatically simulates
random numbers - given below that manual calculation too. Anyone help me to fix
that error. I got that error "object of type 'closure' is not subsettable" So
Do you have any ideas?
Regards
Mayooran
###
Yes, Now fixed it. Thanks for your help. So my function is given by
start<-function(n){
#startn <- vector("list", n)
indx <- 1:N
start <-sort(sample(indx,1))
for (i in 1:n) {
if (i<2) {
start[i] <- sort(sample(indx,1))
} else {
start[i] <- sort(sample(start[i-1]+1,1))
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