Dear list,
here are my two data frames:
av -
structure(list(DESCRIPTION = c(COFFEE C Sep/10, COPPER Sep/10,
CORN Dec/10, CRUDE OIL miNY Sep/10, GOLD Aug/10, HENRY HUB
NATURAL GAS Sep/10,
PALLADIUM Sep/10, SILVER Sep/10, SOYBEANS Nov/10, SPCL HIGH
GRADE ZINC USD,
SUGAR NO.11 Oct/10, WHEAT
/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
**
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
I have a data frame called pose:
DESCRIPTION QUANITY CLOSING.PRICE
1 WHEAT May/101467.75
2 WHEAT May/102467.75
3 WHEAT May/101467.75
4 WHEAT May/101467.75
5 COTTON NO.2 May/101 78.13
/10 78.133
2 WHEAT May/10 467.754
Op is a data.frame object.The trick is done!
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
__
R-help@r-project.org mailing list
https
Dear group,
Here is a data.frame, lme:
lme
DESCRIPTION CLOSING.PRICE POSITION
4PRIMARY NICKEL USD 04/06/1025,755.71000
5PRIMARY NICKEL USD 10/06/1025,760.86000
6 PRM HGH GD ALUMINIUM USD 09/07/10 2,415.90000
8 SPCL
0
If someone has a better idea, it is welcomed.
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Thursday, April 15, 2010 9:50 AM
To: 'r-help@r-project.org'
Subject: sum rows in a data.frame
Dear group,
Here is a data.frame, lme:
lme
Dear group,
I have this following data.frame:
c
DESCRIPTION CREATED.DATE QUANITY CLOSING.PRICE
26 PRM HGH GD ALU 2010-04-09 -12,415.9000
27 PRM HGH GD ALU 2010-04-09 12,415.9000
28 PRIMARY NICKEL 2010-03-04 1 25,755.7100
29 PRIMARY NICKEL 2010-03-05
Why don't you try something like :
Xd$x=as.date(xd$x,format=%y/%m/%d).
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Christian Raschke
Sent: Thursday, April 15, 2010 8:28 PM
To: r-help@r-project.org
Subject: Re: [R]
Dear group,
Here is my data.frame :
df -
structure(list(DESCRIPTION = c(PRM HGH GD ALU, PRM HGH GD ALU,
PRIMARY NICKEL, PRIMARY NICKEL, PRIMARY NICKEL, PRIMARY NICKEL,
STANDARD LEAD , STANDARD LEAD , STANDARD LEAD , STANDARD LEAD ,
STANDARD LEAD , STANDARD LEAD , STANDARD LEAD , STANDARD
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
***
From: Ista Zahn [mailto:istaz...@gmail.com]
Sent: Friday, April 16, 2010 1:05 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation
Hi,
I'm not sure I understand what you want
Excellent!! You saved me hours and hours of turning around and around.
TY so much.
From: Ista Zahn [mailto:istaz...@gmail.com]
Sent: Friday, April 16, 2010 1:37 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation
It works for me...
DF -
+ structure(list
-1
4 ROBUSTA COFFEE (10) May/10 1,353. 15
5 WHEAT May/10467.75004
It is almost exactly what I want, except I am expecting the POSITION column
before the SETTLEMENT column. How can I modified my code to obtain this?
TY
***
Arnaud
:02 PM
To: arnaud Gaboury; r-help@r-project.org
Subject: Re: [R] data.frame and ddply
You can do something like this after the output from opfut
opfut - data.frame(opfut$CONTRAT,opfut$POSITION,opfut$SETTLEMENT)
names(opfut) - c('CONTRAT','POSITION','SETTLEMENT')
opfut
Felipe D. Carrillo
.
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
***
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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PLEASE do read the posting
, start, stop), but in my case, I need to indicate
I want to start from the end of the vector, and I have no idea how to pass
this argument.
TY for any help
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
:11 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] substract start from the end of the vector
Hi,
On Fri, Apr 23, 2010 at 11:57 AM, arnaud Gaboury
arnaud.gabo...@gmail.com wrote:
Dear group,
Here is my df :
df -
structure(list(DESCRIPTION = c(PRM HGH GD
is the process to save these 2 objects in
order to access them later in another function?
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
***
[[alternative HTML version deleted]]
__
R
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] save a data frame in environment
Don't print them but return() them from your function position() within
a list. Then you will have a list of two data.frames for later usage
assigned to your list.
Uwe Ligges
On 27.04.2010 11
Dear group,
Here is my data.frame :
avprix -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN May/10,
ROBUSTA COFFEE (10) Jul/10, SOYBEANS Jul/10, SPCL HIGH GRADE ZINC USD
Jul/10,
STANDARD LEAD USD Jul/10), prix = c(-1.5, -1082, 11084, 1983.5,
-2464, -118), quantity = c(0, -3, 8, 2, -1, 0)),
Dear group,
I need to modify some characters in a data frame. I want to use gsub and the
regex functionalities to do this.
Here is the data frame (df):
DESCRIPTIONprix quantity
1 CORN Jul/10-1.50
2 CORN May/10 -1082.0
)), .Names = c(DESCRIPTION,
prix, quantity), row.names = c(NA, -6L), class = data.frame)
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Wednesday, April 28, 2010 1:31 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] gsub,regex and replacing
Next time you include a data frame
TY so much david. We are getting close. But I need to keep USD in my
object name (i.e STANDARD LEAD USD)
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
***
-Original Message-
From: David Winsemius [mailto:dwinsem
Dear group,
Here is my df:
avprix -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN May/10,
ROBUSTA COFFEE (10) Jul/10, SOYBEANS Jul/10, SPCL HIGH GRADE ZINC USD,
STANDARD LEAD USD), prix = c(-1.5, -1082, 11084, 1983.5, -2464,
-118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24,
I want the 0s to be at the end or beginning.
-Original Message-
From: Erik Iverson [mailto:er...@ccbr.umn.edu]
Sent: Wednesday, April 28, 2010 5:21 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame move columns
avprix -
structure(list(DESCRIPTION
TY david. Here we go with a correct code!
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Wednesday, April 28, 2010 5:28 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame move columns
On Apr 28, 2010, at 11:14 AM
Dear group,
I know this issue has been already covered, and before you reply I must say
I have read the R-FAQ and search the mailing list archive.
I still can't manage to change my factor to numeric as I couldn't find any
clear answer.
Here is my df :
Pose1 -
structure(list(DESCRIPTION =
TY petr, I was just trying something like that few mn ago :-)
as.numeric(gsub(,, , S)) does exactly what I want.
-Original Message-
From: Petr PIKAL [mailto:petr.pi...@precheza.cz]
Sent: Thursday, April 29, 2010 1:28 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Odp
Dear group,
Here is my data frame:
position100415 -
structure(list(DESCRIPTION = structure(1:9, .Label = c( SUGAR NO.11 Jul/10
,
SUGAR NO.11 May/10 , CORN May/10 , COTTON NO.2 Jul/10 ,
CRUDE OIL miNY May/10 , ROBUSTA COFFEE (10) Jul/10 , SILVER May/10 ,
SOYBEANS Jul/10 , WHEAT May/10 ),
TY so much, I ignored about this argument. Adding stripe.white=T as an
argument in my read.csv does the job.
-Original Message-
From: Uwe Ligges [mailto:lig...@statistik.tu-dortmund.de]
Sent: Friday, April 30, 2010 1:08 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re
Dear group,
I am losing my mind with a simple question. Sorry if obvious, but I maybe
start to be confused after days and days of reading documentations.
Df :
df -
structure(list(a = 1:3, b = 4:6, c = structure(c(1L, 1L, 1L), class =
factor, .Label = w)), .Names = c(a,
b, c), row.names =
$DESCRIPTION).
Can't write the pattern argument in regex.
Any help would be appreciated.
TY
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
TY for the two answers. Both work.
-Original Message-
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Tuesday, May 11, 2010 11:21 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] Regex and gsub
df3$DESCRIPTION =
sub(' [a-z]{3}/[0-9]{2
Dear group,
I have 3 data frames I would like to merge.
Here they are:
pose16 -
structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
6L, 7L, 8L, 9L, 12L), .Label = c(COPPER May/10, COTTON NO.2 Jul/10,
CRUDE OIL miNY May/10, GOLD Jun/10, ROBUSTA COFFEE (10) Jul/10,
SOYBEANS Jul/10,
In fact, that is one solution. I can then do a
ddply(x,DESCRIPTION,summarise, pl=sum(prix),quantity=sum(POSITION)). It
does work. I was just wandering if it exists another solution.
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Tuesday, May 11, 2010 2:14 PM
To: arnaud Gaboury
Cc: r-help
Dear group,
I have these 2 following data frame:
allcon -
structure(list(DESCRIPTION = structure(1:17, .Label = c(COFFEE C Jul/10,
COPPER May/10, CORN Jul/10, CORN May/10, COTTON NO.2 Jul/10,
CRUDE OIL miNY May/10, GOLD Jun/10, HENRY HUB NATURAL GAS May/10,
ROBUSTA COFFEE (10) Jul/10, SILVER
SYSTEMATICALLY add the argument
strip.white=T when I read a csv file, so all blanks are removed.
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Tuesday, May 11, 2010 4:25 PM
To: r-help@r-project.org
Cc: 'arnaud Gaboury'
Subject: merge two data frames
Dear
Dear group,
Here is my df :
pose16 -
structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
6L, 7L, 8L, 9L, 12L), .Label = c(COPPER May/10, COTTON NO.2 Jul/10,
CRUDE OIL miNY May/10, GOLD Jun/10, ROBUSTA COFFEE (10) Jul/10,
SOYBEANS Jul/10, SUGAR NO.11 Jul/10, SUGAR NO.11 May/10,
WHEAT
I was just adding the minus sign to the line when I got your mail.
Yes, it works that way.
TY for the transform function.
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Wednesday, May 12, 2010 5:07 PM
To: Henrique Dallazuanna
Cc: arnaud Gaboury; r
,
244.77, 166.48, 2273.8, 24876, 2985, 80.9, -15.95, 2512.5,
-2423)), .Names = c(DESCRIPTION, POSITION, prix), row.names =
c(1,
2, 3, 4, 5, 6, 7, 8, 9, 51), class = data.frame)
From: Henrique Dallazuanna [mailto:www...@gmail.com]
Sent: Wednesday, May 12, 2010 3:32 PM
To: arnaud Gaboury
Cc: r
TY. Didn't know this function.
From: Henrique Dallazuanna [mailto:www...@gmail.com]
Sent: Wednesday, May 12, 2010 3:32 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame subscription
Try this:
transform(pose16, prix = POSITION * SETTLEMENT, SETTLEMENT = NULL
Dear group,
Here are my objects in my environment:
ls()
[1] Pos100415 Pos100416 posA pose15pose16pose16t
position trade x
I need to pass the object Pos100415 to a function. This element is a
data.frame, obtained through a function: Pos(x)-myfun(x) with x-100415 in
this
Wonderful!!
TY so much for the help.
-Original Message-
From: Patrizio Frederic [mailto:frederic.patri...@gmail.com]
Sent: Thursday, May 13, 2010 10:47 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] access objects in my environment
Hi,
have a look
Dear group,
I have this command line in a function:
zz-merge(transform(merge(value,allcon,all.y=T),SHORTDESCRIPTION=NULL,VALUE=
NULL,PL=-VALUE*pl,quantity=NULL),PosB,all.x=T,sort=F)
I want to cut it in 2 lines (just for convenient purpose). Here is what I
did :
Removing the + sign resolves the problem.
TY
-Original Message-
From: Muhammad Rahiz [mailto:muhammad.ra...@ouce.ox.ac.uk]
Sent: Thursday, May 13, 2010 3:15 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] long command line cut in 2 parts
Dear Arnaud,
Wrap
Dear group,
Here is an object:
z -
c(LSCPos100415.csv, LSCPos100416.csv, LSCPos100419.csv,
LSCPos100420.csv, LSCPos100421.csv, LSCPos100422.csv,
LSCPos100423.csv,
LSCPos100426.csv, LSCPos100427.csv, LSCPos100428.csv,
LSCPos100429.csv,
LSCPos100430.csv, LSCPos100503.csv, LSCPos100504.csv,
Of course this helps!
I didn't noticed the difference between sub and gsub.
TY
-Original Message-
From: Bernd Weiss [mailto:bernd.we...@uni-koeln.de]
Sent: Friday, May 14, 2010 12:23 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] regex and sub
Am 14.05.2010
Dear group,
I am trying to write functions, but as a beginner, everything is not so
obvious.
Let's say I want the results in a list of elemts like this :
tot1, tot2, etc
Here is a function:
toto -
function(x,y)
{
for(i in x:y){
paste(c(tot,i),collapse=)-(i*2)
}
}
If I type this :
-100415 et y-100420, the result I want is 100415,100416,100419,100420.
The object l is a list, but can be of any other kind if it can help.
I tried something like this :
select-l[c(x:y)]
But it doesn't return the needed result
Any help would be appreciated
***
Arnaud
elements in a list
Hi,
This should work:
select - l[which(l==x):which(l==y)]
The problem is that you tried to select the values, but gave x and y as
indexes. That's why you didn't get the expected result.
See ?which for more info.
HTH,
Ivan
Le 5/21/2010 11:07, arnaud Gaboury
Dear group,
Here is my environment :
ls()
[1] l PLglobal Pos100415 Pos100416 Pos100419
Pos100420 position select Trad100415 Trad100416
Trad100419 Trad100420 trade y
With objects :
l
[1] 100415 100416 100419 100420 100421 100422 100423 100426
100427 100428 100429
Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Friday, May 21, 2010 4:00 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] indexing problem
On May 21, 2010, at 9:19 AM, arnaud Gaboury wrote:
Dear group,
Here is my environment :
ls()
[1
This do the trick :
for (i in 1:length(sel) ){
posA-get(paste(c(Pos,sel[i]),collapse=))
posB-get(paste(c(Pos,sel[i]+1),collapse=))
}
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Friday, May 21, 2010 4:00 PM
To: arnaud Gaboury
Cc: r
Dear group,
I have a function, let's call it myfun, wich give me a list of result:
R1,R2,R3...
There is a loop in this function to get my results. Here is the structure of
my function:
Myfun-function()
{
For (i in X ){
---instructions-
Ri
{
{
All Results (R1,R2...) are
,] DailyPL100416 DailyPL100419 DailyPL100420
That's not what I want! I expect DF to be a data.frame binded by row.
I suspect there is an issue with get() or assign(), or something like that.
Any help is appreciated.
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com
Maybe is there a neater solution, but the function mget() does the trick. So
until further advice, I will work with your solution.
Thank you
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 5:07 PM
To: arnaud Gaboury
Cc: r-help@r
Do you think there is a way to add somewhere the argument row.names=NULL ? Or
should I have to write another line to remove the row.names?
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 5:07 PM
To: arnaud Gaboury
Cc: r-help@r
Dear group,
Here is my environment after I run a function, myfun()
myfun()
ls()
[1] allconavprix16 DailyPL100416 DailyPL100419
DailyPL100420 l llmyl PL
PLdaily PLglobal PLmonthly
[13] Pos100415 Pos100416 Pos100419
Thank you so much. You are totally right.
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 6:33 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] writing function
My guess is that either ls(), called inside grep
Dear group,
Here is my function:
#return the daily PL for day y
PLDaily-function(x,y)
{
#find elements in my directory with LSCPos in the name, keep the numeric
part in the name and
#create a list
l-gsub(\\D,,dir()[grep(LSCPos,dir())])
#select in the list the desired elements
help is appreciated
***
Arnaud Gaboury
Mobile: +41 79 392 79 56
BBM: 255B488F
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting
Oops, forgot to give a subject
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Wednesday, May 26, 2010 2:31 PM
To: r-help@r-project.org
Cc: 'arnaud Gaboury'
Subject:
Dear group,
Here is my data frame:
dput(u)
structure(list(DESCRIPTION
element different from zero).
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Wednesday, May 26, 2010 2:48 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] (no subject)
What exactly are you trying to do? If you want to know which position is
wrong, try :
if (sum(u$POSITION
Dear group,
Here is my df :
trade -
structure(list(Trade.Status = c(DEL, INS, INS), Instrument.Long.Name =
c(SUGAR NO.11,
CORN, CORN), Delivery.Prompt.Date = c(Jul/10, Jul/10,
Jul/10), Buy.Sell..Cleared. = c(Sell, Buy, Buy), Volume = c(1L,
2L, 1L), Price = c(15.2500, 368., 368.5000),
Thank you for the answer.
Is there any way to combine if() and switch() in one line? In my case,
something like :
if(trade$Trade.Status==DEL)switch(.)
I would like to avoid the loop .
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Wednesday, May 26, 2010 9:15 PM
To: arnaud Gaboury
Dear group,
Here is my df :
trades -
structure(list(Trade.Status = c(DEL, INS, INS), Instrument.Long.Name =
c(SUGAR NO.11,
CORN, CORN), Delivery.Prompt.Date = c(Jul/10, Jul/10,
Jul/10), Buy.Sell..Cleared. = c(Sell, Buy, Buy), Volume = c(1L,
2L, 1L), Price = c(15.2500, 368., 368.5000),
.
NULL
That's certainly not what I want.
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 8:43 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation change elements meeting criteria
The loop is due to the switch statement
..sum.
NULL
That's certainly not what I want.
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 8:43 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation change elements meeting criteria
The loop is due to the switch statement
, Instrument.Long.Name,
Delivery.Prompt.Date, Buy.Sell..Cleared., Volume, Price,
Net.Charges..sum.), row.names = c(NA, 3L), class = data.frame)
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 10:38 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation change elements meeting criteria
Off course. You put in a matrix to sapply, but sapply is for vectors. You
want to apply the switch command on every entry of the vector
trades$Buy.Sell..Cleared for which trades
,
Instrument.Long.Name, Delivery.Prompt.Date, Buy.Sell..Cleared.,
Volume, Price, Net.Charges..sum.), row.names = c(NA, 3L), class =
data.frame)
From: Joris Meys [mailto:jorism...@gmail.com]
Sent: Thursday, May 27, 2010 10:38 AM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame
: Thursday, May 27, 2010 2:34 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] switch function
try this:
toBuy - trades$Trade.Status == DEL trades$Buy.Sell..Cleared. ==
Sell
toSell - trades$Trade.Status == DEL trades$Buy.Sell..Cleared. ==
Buy
x - trades # make a copy
Dear group,
Here is the kind of data.frame I obtain every day with my function :
futures -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN Jul/10,
CORN Jul/10, CORN Jul/10, CORN Jul/10, LIVE CATTLE Aug/10,
LIVE CATTLE Aug/10, SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10,
SUGAR NO.11 Jul/10, SUGAR
To: arnaud Gaboury
Subject: Re: [R] data frame manipulation with zero rows
On Tue, 1 Jun 2010, arnaud Gaboury wrote:
Dear group,
Here is the kind of data.frame I obtain every day with my function :
futures -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN Jul/10,
CORN Jul/10
Dear group,
Here is my data frame:
futures -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN Jul/10,
CORN Jul/10, CORN Jul/10, CORN Jul/10, LIVE CATTLE Aug/10,
LIVE CATTLE Aug/10, SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10,
SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10, SUGAR NO.11 Jul/10
),
...@uni-bremen.de]
Sent: Tuesday, June 01, 2010 11:38 AM
To: arnaud Gaboury
Subject: Re: [R] data frame manipulation ddply
Hi Arnaud,
maybe aggregate can help:
PosFut - aggregate(futures$QUANTITY, list(DESCRIPTION =
futures$DESCRIPTION,
SETTLEMENT
It is indeed ddply() from package plyr.
-Original Message-
From: Prof Brian Ripley [mailto:rip...@stats.ox.ac.uk]
Sent: Tuesday, June 01, 2010 12:24 PM
To: Peter Ehlers
Cc: arnaud Gaboury; r-help@r-project.org
Subject: Re: [R] data frame manipulation with zero rows
On Tue, 1
Dear group,
Here is my df (obtained with a read.csv2()):
df -
structure(list(DESCRIPTION = c(COTTON NO.2 Jul/10, COTTON NO.2 Jul/10,
PALLADIUM Jun/10, PALLADIUM Jun/10, SUGAR NO.11 Jul/10,
SUGAR NO.11 Jul/10), CREATED.DATE = c(13/05/2010, 13/05/2010,
14/05/2010, 14/05/2010, 10/05/2010,
TY for the tip. The lower case is in fact the culprit.
-Original Message-
From: Erik Iverson [mailto:er...@ccbr.umn.edu]
Sent: Tuesday, June 01, 2010 6:05 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] as.date
Where does the problem comes from?? Maybe from
Maybe not the cleanest way, but I create a fake data frame with one row so
ddply() is happy!!
if (nrow(futures)==0) futures-data.frame(...)
-Original Message-
From: Peter Ehlers [mailto:ehl...@ucalgary.ca]
Sent: Tuesday, June 01, 2010 12:07 PM
To: arnaud Gaboury
Cc: 'Prof
Dear group,
Here is a list of elements :
l -
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426, 100427, 100428, 100429, 100430, 100503,
100504, 100505, 100506, 100507, 100510, 100511, 100512,
100513, 100514, 100517, 100518, 100519, 100520, 100521,
100524, 100525, 100526,
The correct line is :
l[(which(100420==l)-1):which(100420==l)]
[1] 100419 100420
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Wednesday, June 02, 2010 9:41 AM
To: r-help@r-project.org
Cc: 'arnaud Gaboury'
Subject: which function
Dear group
I do really think it is a very good idea.
TY
-Original Message-
From: h.wick...@gmail.com [mailto:h.wick...@gmail.com] On Behalf Of
Hadley Wickham
Sent: Wednesday, June 02, 2010 3:31 PM
To: arnaud Gaboury
Cc: Peter Ehlers; r-help@r-project.org; Prof Brian Ripley
Subject: Re: [R
Dear group,
Here is my environment:
ls()
[1] DailyPL100419 DailyPL100420 DailyPL100421 ddi
l PLglobal Pos100416 Pos100419 Pos100420
Pos100421 position
[13] resultsel Trad100416Trad100419
Trad100420Trad100421trade
With
Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 4:48 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] bind select data frames
Hello,
Does this do what you are looking for?
output - NULL
for(i in paste(DailyPL, sel, sep=)[-1
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 4:48 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] bind select data frames
Hello,
Does this do what you are looking for?
output - NULL
for(i in paste
= ), envir =
.GlobalEnv), :
unused argument(s) (row.names = NULL)
Why this error?
TY for your help
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 5:08 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] bind
Here we go :
dd-data.frame(do.call(rbind,
mget(paste(DailyPL,sel[-1],sep=),envir=.GlobalEnv)),row.names=NULL)
TY so much Joshua and Jorge.
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 5:11 PM
To: arnaud Gaboury
Cc: r-help@r
Jorge,
Your line works and give the desired result. Now I need to be able to work
with i instead of 100419..., as I need to be able to change these numbers.
TY for your help
From: Jorge Ivan Velez [mailto:jorgeivanve...@gmail.com]
Sent: Wednesday, June 02, 2010 5:09 PM
To: arnaud Gaboury
Cc
and renamed it Nbr.Lots. This line works.
What I would like is changing the col names in the same line, thus avoiding
another line with
colnames(exportfile)-c(Contract,Price,Nbr.Lots)
Is there a possibility to change my col names in the same line?
TY
Arnaud Gaboury
A2CT2 Ltd
.
TY for any help.
Trading
A2CT2 Ltd.
Arnaud Gaboury
A2CT2 Ltd.
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented
TY Uwe,
So I will have to write a line for each condition? Right?
In fact I was trying to do something with apply in one line, but couldn't
achieve any result. In fact, all my transformation will be multiplying one
object by a specific number according to the value of df$x.
Arnaud Gaboury
this as result :
df
x y
1 AA 10 if df$x==AA, df$y-1*10
2 BB 50 if df$x==BB, df$y-2*25
3 CC 3 NOTHING
4 AA 40 if df$x==AA, df$y-4*10
5 DD 75 if df$x==DD, df$y-5*15
6 DD 90 if df$x==DD, df$y-6*15
Arnaud Gaboury
A2CT2 Ltd.
-Original Message
clear enough, and YES I have tried many workarounds myself before
posting. Feel free to ignore my post if you think I am lazy and disrespectful
to the list.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: Uwe Ligges [mailto:lig...@statistik.tu-dortmund.de]
Sent: vendredi 24 février
, 14L, 15L, 16L, 17L, 18L,
19L, 8L, 9L, 10L, 11L, 12L, 20L, 21L, 22L, 23L, 35L, 36L, 37L,
38L, 39L, 40L, 41L, 42L, 31L, 32L, 24L, 25L, 26L, 27L, 28L, 29L,
30L, 2L, 3L, 1L, 33L, 34L), class = data.frame)
Have a good weekend.
Arnaud Gaboury
A2CT2 Ltd.
Trade: +41 22 849 88 63
Fax: +41 22 849 88
WORKING
Now day 2 with df2:
df2 - data.frame(x = c(AA,AA,BB,BB,BB,CC,DD,DD), y = 1:8)
df2$y - df2$y * mult[as.character(df2$x)]
df2
x y
1 AA 2
2 AA 4
3 BB 15
4 BB 20
5 BB 25
6 CC 6
7 DD 14
8 DD 16
WORKING
Ty both of you and have a good weekend.
Arnaud Gaboury
A2CT2 Ltd
the openJDK path in your
environment.
Hope this help.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of John Kane
Sent: vendredi 24 février 2012 19:32
To: r-help@r-project.org
Subject: [R] install
TY Elai for your answer. One solution has been given earlier in this list by
Sarah Goslee and William Dunlap.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of ilai
Sent: vendredi 24 février 2012 20:14
= c(NA, 9L), class = data.frame)
As you can see, they have same column names.
My idea was to merge these two df when passing as argument not to take into
account duplicate rows, so I will get one df with rows which are not in both
df.
Is it possible? How to do it?
TY for any help.
Arnaud
I don't understand where is your problem. Are you looking for jaunty as a
package on R Crans?? Are you looking to install R package on your Ubuntu box?
As you know, Jaunty is no more supported by Ubuntu, so packets have been moved
in Archives.
Arnaud Gaboury
A2CT2 Ltd.
-Original
, 24.81, 1273.5, 1276.25), Nbr.Lots = c(-61, -61, 6, 40,
40, -1, -1, -1, 1, -61, -61, 5, 1, 40, 40, -1, -1, -1, 1)), .Names =
c(Product,
Price, Nbr.Lots), row.names = c(1, 2, 3, 4, 5,
6, 7, 8, 9, 11, 21, 31, 41, 61, 71, 51,
10, 81, 91), class = data.frame)
TY for your help
Arnaud Gaboury
A2CT2
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