-project.org
Subject: Re: [R] String split and concatenation
paste( '(', paste( ', rep(letters[1:3],2), ', sep=,
collapse=','), ')', sep= )
[1] ('a','b','c','a','b','c')
If you need the space after the comma then just change ',' to ', '.
The outer paste can be replaced with sprintf
On Wed, Sep 29, 2010 at 4:15 AM, Steven Kang stochastick...@gmail.com wrote:
x - rep(letters[1:3], 2)
Are there any ways to transform assign the above as the one shown below
to an object? (in exact format; i.e length of 1 class of character),
i.e
x
('a', 'b', 'c', 'a', 'b', 'c')
Highly
x - rep(letters[1:3], 2)
Are there any ways to transform assign the above as the one shown below
to an object? (in exact format; i.e length of 1 class of character),
i.e
x
('a', 'b', 'c', 'a', 'b', 'c')
Highly appreciate for any advice.
On Wed, Sep 29, 2010 at 3:33 PM,
-project.org
Subject: Re: [R] String split and concatenation
x - rep(letters[1:3], 2)
Are there any ways to transform assign the above as the one shown
below
to an object? (in exact format; i.e length of 1 class of character),
i.e
x
('a', 'b', 'c', 'a', 'b', 'c')
Highly appreciate
Hi Steven,
This should do it:
paste('', unlist(strsplit(x, split=)), c(rep(',', length(x)-1), ), sep=)
-Ista
On Wed, Sep 29, 2010 at 1:11 AM, Steven Kang stochastick...@gmail.com wrote:
Hi R users,
I desire to transform the following vector consisting of repeated characters
x -
dump(x, file = x.R)
file.show(x.R)
will get you most of the way.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Steven Kang
Sent: Wednesday, 29 September 2010 3:11 PM
To: r-help@r-project.org
Subject: [R] String split and
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