In a package, i type a function name and got the following message:
...
tmp - .Fortran(master, x = as.double(x), y = as.double(y),
sort = as.logical(sort), rw = as.double(rw), npd = as.integer(npd),
ntot = as.integer(ntot), nadj = integer(tadj), madj =
as.integer(madj),
On Fri, 14 Oct 2005, Sam R. Smith wrote:
In a package, i type a function name and got the following message:
...
tmp - .Fortran(master, x = as.double(x), y = as.double(y),
sort = as.logical(sort), rw = as.double(rw), npd =
as.integer(npd),
ntot =
Sam R. Smith [EMAIL PROTECTED] writes:
In a package, i type a function name and got the following message:
...
tmp - .Fortran(master, x = as.double(x), y = as.double(y),
sort = as.logical(sort), rw = as.double(rw), npd =
as.integer(npd),
ntot = as.integer(ntot),
Hi,
Yesterday, I have analysed data with 16 rows and 10 columns.
Aggregation would be impossible with a data frame format, but when converting
it to a matrix with *numeric* entries (check, if the variables are of class
numeric!) the computation needs only 7 seconds on a Pentium III. I´m
Dear R users,
Suppose I have 2 parts of a dataframe, say
ABCD
2143
3245
2154
(the real dataframe is 160 columns with each 120 rows)
and I want to multiply every element in [,A:B] with every element in [,C:D];
What is the most elegant way to do this?
I´ve been thinking of converting [,A:B] to
where is the problem?
input:
A-c(2,3,2); B-c(1,2,1); C-c(4,4,5); D-c(3,5,4)
df-data.frame(A,B,C,D)
c1-1:2; c2-3:4
df[,c1]*df[,c2]
output:
A B
1 8 3
2 12 10
3 10 4
Peter Wolf
Christoph Scherber wrote:
Dear R users,
Suppose I have 2 parts of a dataframe, say
ABCD
2143
3245
2154
(the
Here is the way that I would do it. Using 'lapply' to process the list and
create a matrix; take less than 1 second:
dat - data.frame(D=sample(32000:33000, 33000, T),
+ Fid=sample(1:10,33000,T), A=sample(1:5,33000,T))
system.time({
+ result - lapply(split(seq(nrow(dat)), dat$D), function(.d){ #
Dear all
I can not understand how to install the package lpsolve_1.1.9.zip
I have read the FAQ and the help pages carefully, but it still not
clear for me.
I have tried the following (and obtained the respective error
messages):
It's a bug: the code has 1:arma[1], i.e. 1:0. Replace by
seq(length=arma[1]).
On Thu, 13 Oct 2005, John Maindonald wrote:
I am puzzled by the warning message in the output below. It appears
whether or not I fit the seasonal term (but the precise point of doing
this was to fit what is
Many thanks for all your answers. Converting to a matrix didn't help,
I tried with Hmisc but didn't get anywhere (different summary
functions, multiple levels).
2005/10/14, jim holtman [EMAIL PROTECTED]:
Here is the way that I would do it. Using 'lapply' to process the list and
create a
Sara,
Could it be that you have to unzip the package? If you are using a PC you can
probably find a free (or trial version) of one of many versions of unzip (e.g.
WINZIP). If you are familiar with Unix, unzipping is similar to using TAR.
John
John Sorkin M.D., Ph.D.
Chief, Biostatistics and
Sara Mouro wrote:
Dear all
I can not understand how to install the package lpsolve_1.1.9.zip
I have read the FAQ and the help pages carefully, but it still not
clear for me.
I have tried the following (and obtained the respective error
messages):
hi all
i have a quick question
i would like to use the source command but i keep on getting an error
eg
source(c:/research file/model.txt)
the problem seems to be because of the space in the file name but this
is how windows references the folder name.
i dont want to change the folder
Dear Sara,
It looks to me as if there are three problems here: (1) Is the zip file for
the package really at c:/ProgramFiles/R/rw2011/library/lpSolve_1.1.9? That
is, isn't there a space in Program Files? (2) You have to specify
repos=NULL to install from a local zip file, as ?install.packages
Use file.choose() instead
source(file.choose())
This will open a dialogue box and might be easier for you to find your
file.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Clark Allan
Sent: Friday, October 14, 2005 7:06 AM
To:
Uwe Ligges [EMAIL PROTECTED] writes:
Sara Mouro wrote:
Dear all
I can not understand how to install the package lpsolve_1.1.9.zip
I have read the FAQ and the help pages carefully, but it still not
clear for me.
I have tried the following (and obtained the
Dear useRs,
I am wondering what is the most fast and stable way to read data (pretty
large) into R. Right now, the methods I could think of are:
1) use read.table to read *.csv or *txt
2) use RODBC to read excel or access
But I don't know which is better.
Thanks for your sugggestion.
--
WenSui
On Fri, 14 Oct 2005, Wensui Liu wrote:
Dear useRs,
I am wondering what is the most fast and stable way to read data (pretty
large) into R. Right now, the methods I could think of are:
1) use read.table to read *.csv or *txt
2) use RODBC to read excel or access
But I don't know which is
Dear Andrew and R-list,
I guess Fournier is addressing the properties of the numerical routines
underlying the various packages, not the statistical properties of the MLE
itself.
For this purpose using a small tricky dataset makes sense. Clearly,
a true unique MLE exists (except in pathological
On 10/14/05, Clark Allan [EMAIL PROTECTED] wrote:
hi all
i have a quick question
i would like to use the source command but i keep on getting an error
eg
source(c:/research file/model.txt)
the problem seems to be because of the space in the file name but this
is how windows
Hello,
i am trying to subset a dataframe multiple times:
something like:
stats - by(df, list(items), ttestData)
ttestData - function(df){
t.test( df[,c(2,3,4), df[,c(5,6,7)]
}
While this works for small data, it is to slow for my
actual data: 50 rows dataframe with
about 135000
Recently, I was trying to make an inward-facing label for a vertical
axis on the right-hand side of a plot. The inward-facing label was
required by a journal. I searched R-help, but the only solution I found
was to use text, which requires fiddling with the x-coordinate for each
plot. What
Jonathan Dushoff wrote:
Recently, I was trying to make an inward-facing label for a vertical
axis on the right-hand side of a plot. The inward-facing label was
required by a journal. I searched R-help, but the only solution I found
was to use text, which requires fiddling with the
Hi.
I am a consultant at KAE: Marketing Intelligence (http://www.kae.co.uk) working
on market evaluation and forecasting. Working on large datasets I am looking
for a solution to use R on datasets stored in an OLAP engine (like MIS Alea,
Applix TM1 or Mondrian). Have you ever heard about
On Fri, 14 Oct 2005, Ido M. Tamir wrote:
Hello,
i am trying to subset a dataframe multiple times:
something like:
stats - by(df, list(items), ttestData)
ttestData - function(df){
t.test( df[,c(2,3,4), df[,c(5,6,7)]
}
While this works for small data, it is to slow for my
actual
But,
foo - 'ls'
system(foo)
is valid.
Is foo a string or a quoted string?
Without a doubt, it is the former. But I don't see any quote marks in
system(foo)
-Don
At 12:39 AM +0200 10/14/05, Benedict P. Barszcz wrote:
Dnia piàtek, 14 paêdziernika 2005 00:13, Sundar Dorai-Raj
Hi Emmanuel,
We are doing some work along these lines. See www.OpenI.org for
details of our open souce OLAP solution contact our CTO, Sandeep
Giri (via link on that site), for details. We haven't released any R
integration yet, but we are doing some things internally it is on
the OpenI
the help page says:
'is.list' returns 'TRUE' iff its argument is a 'list' _or_ a
'pairlist' of 'length' 0, whereas 'is.pairlist' only returns
'TRUE' in the latter case.
does the latter case mean a 'pairlist' of 'length' 0?
but
is.pairlist(pairlist())
[1] TRUE
length(pairlist())
Le ven 14/10/2005 à 00:39, Benedict P. Barszcz a écrit :
Dnia piÄ
tek, 14 października 2005 00:13, Sundar Dorai-Raj napisaÅ:
Don't you mean system(ls)? See ?system.
Arguments:
command: the system command to be invoked, as a string.
This is the kind of obstacles a newbie has to
R function
lm(response ~ term)
allows me to run a linear regression on a single response vector. For
example, I have recent one year historical prices for a stock and SP
index. I can run regression of the stock prices (as response vector)
against the SP index prices (as term vector).
Now
Hi Peter,
Apologies - I ran the script using S-Plus 6.2. I am happy to run it in R, but
my feeling is that there may be something wrong with the code itself. I have
included the dataset and script, in case you can help.
Jindi Singh.
Jatinder Singh
Senior Manager, Analysis and Reporting
PRA
This runs a regression of each column (except the first)
of matrix state.x77 against the first:
lm(state.x77[,-1] ~ state.x77[,1])
On 10/14/05, Heng Sun [EMAIL PROTECTED] wrote:
R function
lm(response ~ term)
allows me to run a linear regression on a single response vector. For
example, I
Dear all,
I am a beginner with lpSolve package (and not an expert in the others).
I can not understand why I am doing wrong, and I would be very grateful if
anyone could please help me on this.
I am trying to optimize (min) the sum of columns/variables, constrained to
=1. Each column/variables
I have always used lsfit() for this, but have been told that lm() is
preferred, and I note the help for lm() states
If 'response' is a matrix a linear model is fitted separately by
least-squares to each column of the matrix.
Reid Huntsinger
-Original Message-
From: [EMAIL
Dear lattice wizards,
I am trying to figure out how to plot predicted values in xyplot,
where the intercept, but not the slope, varies among conditioning
factor levels. I am sure it involves the groups, but I have been
unsuccessful in my search in Pinhiero and Bate, in the help files, or
Thank you Gabor.
I suspected R could do that. But I tried a data frame and it did not work.
Now I test for matrix and it works. So it seems performing many
regressions in one shot works for a matrix, but not a data frame.
Heng
Gabor Grothendieck [EMAIL PROTECTED]
10/14/2005 12:05 PM
To
Is there anyway to have a function prompt the user for a working
directory, equivalent to file.choose()?
--Paul
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
Chris Buddenhagen schrieb:
Dear all
I am using R to produce ordinations library(vegan) and the plot function
produced looks great on the screen but when I send it to jpg or pdf or eps
the resolution is not so good. Can you tell me how to get high resolution
images out of R for publication?
?setwd
e.g. setwd(file.choose())
BTW, you could have found this on your own via help.search('working
directory') . Base R has quite good docs -- you should try them first.
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
The business of the statistician is to catalyze
On 10/14/2005 12:55 PM, Paul Baer wrote:
Is there anyway to have a function prompt the user for a working
directory, equivalent to file.choose()?
It's relatively easy to get a text prompt, but I don't think we've got a
function that's equivalent to the Windows menu item File|Change
dir
Marc Schwartz [EMAIL PROTECTED] 10/13/05 06:07PM
On Fri, 2005-10-14 at 00:39 +0200, Benedict P. Barszcz wrote:
Dnia piatek, 14 pazdziernika 2005 00:13, Sundar Dorai-Raj napisal:
Don't you mean system(ls)? See ?system.
Arguments:
command: the system command to be invoked, as a
On 10/14/2005 1:08 PM, Berton Gunter wrote:
?setwd
e.g. setwd(file.choose())
BTW, you could have found this on your own via help.search('working
directory') . Base R has quite good docs -- you should try them first.
-- Bert Gunter
That won't work in Windows, where the dialogs don't
Hi,
I think I'm missing something very obvious, but I am missing it, so I
would be very grateful for help. I'm using rpart to analyse data on
skull base morphology, essentially predicting sex from one or several
skull base measurements. The sex of the people whose skulls are being
studied is
Anthony. Look at ?predict.rpart, I think this might be the kind of table you
are looking for.
data(iris)
sub - c(sample(1:50, 25), sample(51:100, 25), sample(101:150, 25))
fit - rpart(Species ~ ., data=iris, subset=sub)
fit
table(predict(fit, iris[-sub,], type=class),
Hi!
I was just reading Uwe Ligges write up on extending R-WinEdt for Sweave from
2003; I was wondering if there were updates on it? Are people seriously thiking
about it?
I really use WinEdt a lot, and for not just R, and hence this kind of extension
would be really cool for a whole range
Oops. Thanks, all. Egg on my face. I forgot about that little detail (on
Windows, anyway).
However, you can still do it via dirname(file.choose()) to get the
directory, on Windows,anyway, right? If that isn't implemented on another
platform, than you could mimic the dirname() code by using gsub()
library(tcltk)
setwd(tclvalue(tkchooseDirectory()))
On 10/14/05, Paul Baer [EMAIL PROTECTED] wrote:
Is there anyway to have a function prompt the user for a working
directory, equivalent to file.choose()?
__
R-help@stat.math.ethz.ch mailing list
Arnab mukherji wrote:
Hi!
I was just reading Uwe Ligges write up on extending R-WinEdt for Sweave from
2003; I was wondering if there were updates on it? Are people seriously
thiking about it?
I really use WinEdt a lot, and for not just R, and hence this kind of
extension would be
On 10/14/2005 1:08 PM, Berton Gunter wrote:
?setwd
e.g. setwd(file.choose())
BTW, you could have found this on your own via help.search('working
directory') . Base R has quite good docs -- you should try them first.
-- Bert Gunter
That won't work in Windows, where the dialogs don't
Hi,
I have not been able to find answers to these questions in the FAQs,
manuals, or R-help archives. If answers are available somewhere, please
direct me to them.
1.) Is there a way to convert a table (e.g. represented as a data frame)
to a function, specifying which columns are input and
On 10/14/05, Andy Bunn [EMAIL PROTECTED] wrote:
Given:
foo - data.frame(bar = rnorm(100),
fac1 = factor(rep(1:2, 50)),
fac2 =
factor(c(rep(c(a,b,SomethingReallyReallyReallyLong), 33),a)))
bwplot(bar~fac1|fac2, data = foo)
How do I change the size of
On 10/14/05, Martin Henry H. Stevens [EMAIL PROTECTED] wrote:
Dear lattice wizards,
I am trying to figure out how to plot predicted values in xyplot,
where the intercept, but not the slope, varies among conditioning
factor levels. I am sure it involves the groups, but I have been
Hello,
I'm a new R user and I like to ask somethig about boxplots.
Is it possible to manipulate the Y axis scale? for instance if the default
scale was from 1 to 7, is it possible to change it to 1 to 10?
Thanks!
Rodrigo Medel P.
__
Hello:
Are there any libraries that will do a subset selection for glm's? I looked
through leaps, but seems like it is specifically for linear regressions.
Thank you.
-Dhiren
__
R-help@stat.math.ethz.ch mailing list
# Dear R list,
#
# I'm needing help with lattice, regression and respective lines.
# My data is below:
bra = gl(2, 24, label = c('c', 's'))
em = rep(gl(3, 8, label = c('po', 'pov', 'ce')), 2)
tem = rep(c(0, 0, 30, 30, 60, 60, 90, 90), 6)
tem2 = tem^2
r= rep(1:2, 24)
y= c(40.58,
Dear Hans,
these are interesting points. I guess that I'm approaching it from
the point of view of a decision: I'd be more comfortable using a
fitting routine that has stability under a wide range of identifiable
circumstances. Obtaining the MLE exactly in any instance is a function
of the data
I am new to R and really like to get a handle of basics in short period of
time. What I am trying to do is get myself a list of must-do's (read in
data, batch execution, delimiters, basic modeling commands) in R as in Stata
or SAS. I am just wondering how to execute a R batch file in RGui. Suppose
Web User a écrit :
1.) Is there a way to convert a table (e.g. represented as a data frame)
to a function, specifying which columns are input and which column is
output? It would seem that this would be useful for plotting
experimental results, since e.g. contour(x, y, f) requires f to be
jun xu wrote:
I am new to R and really like to get a handle of basics in short period of
time. What I am trying to do is get myself a list of must-do's (read in
data, batch execution, delimiters, basic modeling commands) in R as in Stata
or SAS. I am just wondering how to execute a R batch
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