What do you get from the following:
max(with(df1, table(Subj, Time)))?
With cases like this, lme gives an answer with a bogus distinction
between variance components for time and residuals. I don't know
about aov or JMP, but I know that varcomp in S-Plus also
Hello,
I'm not sure if I'm in the right place with my question...
I'm running R on Windows and wrote a function and saved it as .R file.
It looks like this:
bmi - function(weight, height) {
bmi - weight / height^2
bmi
}
If I want to use this function, I have to mark everything and then
Hello everyone.
Currently I am running R 2.2.1 (windows), and I will like to update to
2.3. I wanted to ask if it is possible to update without having to removed
2.2.1; or do I first need to delete 2.2.1?
Thank you very much.
Tony
[[alternative HTML version deleted]]
Version 1.9-4 of package 'spatstat' has been sent to CRAN.
It includes new code for perfect simulation of point processes
and various improvements.
The release notes are available at
http://www.spatstat.org/spatstat/current/spatstatRELEASE-NOTES-1.9-4
Adrian Baddeley
Hi,
I would like to put a math expression in the header of a panel.
Acctually, I need to substitute the 'a' to a script-a in a
transcription contained in the factor by which the data set is
divided. So, /spak/ should be /spAk/ where A should be a script-a.
I guessed that math expressions would be
On Wed, 2 Aug 2006, [EMAIL PROTECTED] wrote:
Hello everyone.
Currently I am running R 2.2.1 (windows), and I will like to update to
2.3. I wanted to ask if it is possible to update without having to removed
2.2.1; or do I first need to delete 2.2.1?
There is no such version as `2.3', as
http://cran.r-project.org/bin/windows/base/rw-FAQ.html#What_0027s-the-best-way-to-upgrade_003f
[EMAIL PROTECTED] wrote:
Hello everyone.
Currently I am running R 2.2.1 (windows), and I will like to update to
2.3. I wanted to ask if it is possible to update without having to removed
2.2.1;
Hello
Am Mittwoch, 2. August 2006 17.11 schrieb Thomas Lumley:
This sounds like a conflict between encodings -- eg if R is assuming UTF-8
and the file is encoding in Latin-1 then the sequence
U+00FC : LATIN SMALL LETTER U WITH DIAERESIS
U+0072 : LATIN SMALL LETTER R
is coded as FC72 in the
Hello
Am Donnerstag, 3. August 2006 09.36 schrieb Antje:
Hello,
I'm not sure if I'm in the right place with my question...
I'm running R on Windows and wrote a function and saved it as .R file.
It looks like this:
bmi - function(weight, height) {
bmi - weight / height^2
bmi
}
At 21:04 02.08.2006 +0100, Prof Brian Ripley wrote:
On Wed, 2 Aug 2006, Christian Hennig wrote:
Thank you Brian!
I'm updating my fpc package at the moment and will add some new
functions.
I learned that there should be print and summary methods for the key
functions.
for
Hi,
has anyone ever seen implemented in R the following geodesic
distance between positive definite pxp matrices A and B?
d(A,B) = \sum_{i=1}^p (\log \lambda_i)^2
were \lambda is the solution of det(A -\lambda B) = 0
thanks
stefano
__
HeinzT == Heinz Tuechler [EMAIL PROTECTED]
on Thu, 03 Aug 2006 09:39:35 +0100 writes:
HeinzT At 21:04 02.08.2006 +0100, Prof Brian Ripley wrote:
On Wed, 2 Aug 2006, Christian Hennig wrote:
Thank you Brian!
I'm updating my fpc package at the moment and will
Hi
I am following the model building strategy that is outlined in the Pinheiro and
Bates book wrt including covariates but am having a problem with the plot.
Basically I am using 4 covariates (1 of them is continuous) and 3 of them are
fine but the 4th one is being shown as a scatterplot
I have ported some R code to C to make it faster.
I can perform .Call(foobar,) once and it
works fine. Absolutely correct answer.
If I put a loop inside foobar and run the main code
routine more than 100 times, it crashes R.
Or if I call .Call(foobar) seperately more than
two tims it
Thanks, I'll look at that.
In the meantime, the code below is what I came up with myself. It does
what I want
# SelectCases(dat,crit) == subset(dat, crit, drop=FALSE)
SENSICK.AvScores- function( dat=SENSICK.items.tr )
{
n-nlevels(dat$Symptom)
data.frame(
I read two questions: physical meaning and how to display only
significant differences.
PHYSICAL MEANING
A p value is the probability of obtaining by chance alone a result at
least as extreme as what we observe. A simultaneous or adjusted p
value is the probability that
On Tuesday 01 August 2006 19:24, John McHenry wrote:
[...]
Yes, I built R myself. I couldn't find a debian package for R 2.3.1. The
latest available is 2.2.1.
Oh, but there is... right on CRAN. For Dapper just add this line to your
sources.list:
deb
Dear All,
is there a possibility to provide a default for the first argument in an
assignment function?
I could not find out if and how. You see in the example below that not
explicitly stating the first argument leads to errors.
Thanks,
Heinz Tüchler
### example of assignment function
Greg,
be careful using attach() and detach(). From the syntax snippets you
showed it seems that you did create an object pcat (factor
variable), but you did not change the respective variable in your
data frame.
Try to remove pcat and see what happens do the results of lme()!
Dirk
In theory, 'lme' may be able to handle crossed random effects, but I
don't know how to do it. I've used 'lmer' for such models, and your
'lmer' code looks plausible to me. Therefore, I would be inclined to
believe the 'lmer' results.
To remove any lingering doubt, I
Perhaps Destroy key is unknown by Tcl; it is not in the
Event modifiers table in Welch Book...
But try with Control-L or Shift-Control_L, it runs
(but not with Control_L-Shift ??).
Use xmodmap to see the current mappings from keys to modifiers.
Jean Coursol
On Wed, 2 Aug 2006, Franco Mendolia
I have 2 questions on ANOVA with 1 between subjects factor and 2 within factors.
1. I am confused on how to do the analysis with aov because I have seen two
examples
on the web with different solutions.
a) Jon Baron (http://www.psych.upenn.edu/~baron/rpsych/rpsych.html) does
6.8.5 Example 5:
Hi!
Perhaps Destroy key is unknown by Tcl; it is not in the
Event modifiers table in Welch Book...
I think the Destroy key is known, because when destroying the window with
Alt-F4
or the littel x in the topcorner my function exitProg is executed.
What I actually search for is a possibility
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Jean Coursol [EMAIL PROTECTED] writes:
Perhaps Destroy key is unknown by Tcl; it is not in the
Event modifiers table in Welch Book...
But try with Control-L or Shift-Control_L, it runs
(but not with Control_L-Shift ??).
I don't think that is it. As I read it, Tk catches the Destroy event
I don't think that is it. As I read it, Tk catches the Destroy event
alright, but the problem is that it is too late: the window
destruction is already in motion at the time and there's no way to
undestroy it from within binding. I think you need to create a wm
protocol handler for
Hello
I try to ignore the problems with the umlaut.
I read the file in with:
library(foreign)
daten - read.spss(filename)
Then I want select a Vorlage (vote), but if I want select for example [6]
and not 6 and 7 how can I select it? The real name is a other problem, but I
can solve this via
--- jim holtman [EMAIL PROTECTED] wrote:
?which
which(Df = 50, arr.ind=T)
row col
5 5 4
This works very nicely as has some other suggestions
on how to replace a value. Assuming that I have more
than one correction to make where Df = 50, can I use
vectors in the Df[] to do this.
My
Dear friends,
In R, the help of bic.glm tells the difference between postmean(the
posterior mean of each coefficient from model averaging) and
condpostmean(the posterior mean of each coefficient conditional on the
variable being included in the model), But it's still unclear about the
results
John Kane [EMAIL PROTECTED] writes:
--- jim holtman [EMAIL PROTECTED] wrote:
?which
which(Df = 50, arr.ind=T)
row col
5 5 4
This works very nicely as has some other suggestions
on how to replace a value. Assuming that I have more
than one correction to make where Df =
Hi all who know R on Windows,
Quick question: Is there a way to do bringToTop(stay=TRUE) without giving
focus? I would like to pop a graph window but I would like to preserve focus
in the window which I was in before.
Thanks for any lead,
Chris
__
On 8/3/2006 9:13 AM, [EMAIL PROTECTED] wrote:
Hi all who know R on Windows,
Quick question: Is there a way to do bringToTop(stay=TRUE) without giving
focus? I would like to pop a graph window but I would like to preserve
focus in the window which I was in before.
No, there's no way to do
Dear All
My data consists in 96 groups, each one with 10 observations. Levene's
test suggests that the variances are not equal, and therefore I have
tried to apply the classical transformations to have homocedasticity
in order to be able to use ANOVA. Unfortunately, no transformation
that I have
On Thu, 3 Aug 2006, Thomas Kuster wrote:
Hello
Am Mittwoch, 2. August 2006 17.11 schrieb Thomas Lumley:
This sounds like a conflict between encodings -- eg if R is assuming UTF-8
and the file is encoding in Latin-1 then the sequence
U+00FC : LATIN SMALL LETTER U WITH DIAERESIS
U+0072 : LATIN
Paul Smith [EMAIL PROTECTED] writes:
Dear All
My data consists in 96 groups, each one with 10 observations. Levene's
test suggests that the variances are not equal, and therefore I have
tried to apply the classical transformations to have homocedasticity
in order to be able to use ANOVA.
Dear All,
applying some function within a with() function I wanted to use also
sapply() and get() to form a data.frame, but did not succede.
Below is a simplified example.
It is possible to use sapply() within a with() function, it is also
possible to use get() within a with() function, but when
On 03 Aug 2006 15:45:10 +0200, Peter Dalgaard [EMAIL PROTECTED] wrote:
My data consists in 96 groups, each one with 10 observations. Levene's
test suggests that the variances are not equal, and therefore I have
tried to apply the classical transformations to have homocedasticity
in order
Dear all,
I have some csv-files (originating from Excel-files) containing empty
cells. In my example file I have four variables of different classes,
each with some empty cells in the original csv-file:
test - read.csv2(test.csv, dec=.)
test
id id2 x y
1 a 1 NA
2 b e NA 2.2
Thanks for fast response.
'Had another look at the problem and found a partial but nice solution which
will solve my present problem and might be useful to others.
Here is the context:
In fact I have all my data and stuff in Excel and I use R(D)COM with Rexcel to
communicate with R and do some
Hello all,
Consider the following problem:
There are two vectors:
rows - c(1, 2, 3, 4, 5)
columns - c(10, 11, 12, 13, 14)
I want to create a matrix with dimensions length(rows) x length(columns):
res - matrix(nrow = length(rows), ncol = length(columns))
If i and j are the row and column
Hi,
i've two questions concerning the plot of a dendrogram. first, i use
hclust for clustering and if i plot the dendrogram, then the maximal
height is the maximal dissimilarity found in my data. but i want to have
a arbitary maximal height. for example if the maximal dissimilarity in
my data
Hi,
i've two questions concerning the plot of a dendrogram. first, i use
hclust for clustering and if i plot the dendrogram, then the maximal
height is the maximal dissimilarity found in my data. but i want to have
a arbitary maximal height. for example if the maximal dissimilarity in
my data
try to use the 'na.strings' argument of read.csv(), e.g.,
test - read.csv(test.csv, na.strings = )
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Hi,
Try this:
rows - c(1, 2, 3, 4, 5)
columns - c(10, 11, 12, 13, 14)
expanded -expand.grid(rows,columns)
abslist -abs(ex$Var1-ex$Var2)
res - matrix(abslist,nrow = length(rows), ncol = length(columns))
Neurorox
From: Daniel Gerlanc [EMAIL PROTECTED]
Reply-To: [EMAIL PROTECTED]
To:
On Thu, 3 Aug 2006, Daniel Gerlanc wrote:
Hello all,
Consider the following problem:
There are two vectors:
rows - c(1, 2, 3, 4, 5)
columns - c(10, 11, 12, 13, 14)
I want to create a matrix with dimensions length(rows) x length(columns):
res - matrix(nrow = length(rows), ncol =
Hi
outer(rows, columns, function(x,y) abs(x-y))
shall do it.
HTH
Petr
On 3 Aug 2006 at 10:10, Daniel Gerlanc wrote:
Date sent: Thu, 3 Aug 2006 10:10:46 -0400
From: Daniel Gerlanc [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Subject:
Sorry,
I used ex instead of expanded (was working name).
rows - c(1, 2, 3, 4, 5)
columns - c(10, 11, 12, 13, 14)
expanded -expand.grid(rows,columns)
abslist -abs(expanded$Var1-expanded$Var2)
res - matrix(abslist,nrow = length(rows), ncol = length(columns))
Désolé encore
Neuro
From: Daniel
On Thu, 2006-08-03 at 10:10 -0400, Daniel Gerlanc wrote:
Hello all,
Consider the following problem:
There are two vectors:
rows - c(1, 2, 3, 4, 5)
columns - c(10, 11, 12, 13, 14)
I want to create a matrix with dimensions length(rows) x length(columns):
res - matrix(nrow =
res-outer(rows,columns,FUN=function(x,y) abs(x-y))
will help you.
Am Thu, 03 Aug 2006 16:10:46 +0200 schrieb Daniel Gerlanc
[EMAIL PROTECTED]:
Hello all,
Consider the following problem:
There are two vectors:
rows - c(1, 2, 3, 4, 5)
columns - c(10, 11, 12, 13, 14)
I want to create a
try this:
abs(outer(rows, columns, -))
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
On 03 Aug 2006 16:32:38 +0200, Peter Dalgaard [EMAIL PROTECTED] wrote:
My data consists in 96 groups, each one with 10 observations. Levene's
test suggests that the variances are not equal, and therefore I have
tried to apply the classical transformations to have homocedasticity
in
Paul Smith [EMAIL PROTECTED] writes:
On 03 Aug 2006 15:45:10 +0200, Peter Dalgaard [EMAIL PROTECTED] wrote:
My data consists in 96 groups, each one with 10 observations. Levene's
test suggests that the variances are not equal, and therefore I have
tried to apply the classical
On Thu, 3 Aug 2006, Heinz Tuechler wrote:
Dear All,
applying some function within a with() function I wanted to use also
sapply() and get() to form a data.frame, but did not succede.
Below is a simplified example.
It is possible to use sapply() within a with() function, it is also
possible
I have data for several rings of a left heart chamber, and which I would like
to display in concentric rings, with color-encoding of the values. Each ring
corresponds to one slice through the heart, and the rings correspond to
positions from the base to the apex of the heart as you move from
On Thu, 3 Aug 2006, Benn Fine wrote:
I have ported some R code to C to make it faster.
I can perform .Call(foobar,) once and it
works fine. Absolutely correct answer.
If I put a loop inside foobar and run the main code
routine more than 100 times, it crashes R.
Or if I call
Thank you, Thomas!
It helps a lot to know that something is impossible and that I have to look
for a different kind of solution.
Heinz
At 07:33 03.08.2006 -0700, Thomas Lumley wrote:
On Thu, 3 Aug 2006, Heinz Tuechler wrote:
Dear All,
applying some function within a with() function I wanted
Hi
try to set
na.strings =
in calling read.csv2. Works for me
is.na(read.delim(clipboard, na.strings=)$mono)
[1] FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE TRUE
read.delim(clipboard, na.strings=)$mono
[1] hruby hruby jemny jemny nejhrubsi nejhrubsi
standard standard
Antje niederlein-rstat at yahoo.de writes:
I'm not sure if I'm in the right place with my question...
I'm running R on Windows and wrote a function and saved it as .R file.
It looks like this:
bmi - function(weight, height) {
bmi - weight / height^2
bmi
}
If I want to use this
Reading a csv file (db.csv) as:
yes,full
no,full
no,empty
I can use the command 'levels' to extract
the different values appearing for each
column as follows:
d-read.csv(db.csv)
levels(d[,2])
which returns
[1] empty full
while, doing the same with a numerical csv file as:
1,6
0,6
0,7
On Thu, 2006-08-03 at 07:46 -0700, Michael Jerosch-Herold wrote:
I have data for several rings of a left heart chamber, and which I
would like to display in concentric rings, with color-encoding of the
values. Each ring corresponds to one slice through the heart, and the
rings correspond to
--- Peter Dalgaard [EMAIL PROTECTED] wrote:
John Kane [EMAIL PROTECTED] writes:
--- jim holtman [EMAIL PROTECTED] wrote:
?which
which(Df = 50, arr.ind=T)
row col
5 5 4
This works very nicely as has some other
suggestions
on how to replace a value. Assuming
On Thu, 3 Aug 2006, Thomas Lumley wrote:
On Thu, 3 Aug 2006, Benn Fine wrote:
I have ported some R code to C to make it faster.
I can perform .Call(foobar,) once and it
works fine. Absolutely correct answer.
If I put a loop inside foobar and run the main code
routine more
I know I'm coming late to this, but ...
Is someone able to suggest to me a transformation to overcome the
problem of heterocedasticity?
It is not usually useful to worry about this. In my experience, the gain in
efficiency from using an essentially ideal weighted analysis vs. an
approximate
I have gone and looked at the code for reading SPSS portable files, and
the file format appears to specify that you cannot read many legal
characters.
Part of the header information in the file format is a 256-byte
translation table apparently designed for translating between character
Hello all,
I've tried to build my linux source package with the following commands
and then run it through the RCrossBuild package with R 2.3.1, but I get
errors about how the built field is incorrect and that my Rd file has a
non-empty \name. I've looked through the Rd file and it seems to
Alessandro Antonucci wrote:
Reading a csv file (db.csv) as:
yes,full
no,full
no,empty
I can use the command 'levels' to extract
the different values appearing for each
column as follows:
d-read.csv(db.csv)
levels(d[,2])
which returns
[1] empty full
while, doing the same
see in line
Petr Pikal wrote:
See
?aov
?lm
something like
lm(result~yourfactor1+yourfactor2+yourfactor3+yourfactor5,
data=yourdataframe)
or
lm(result~(yourfactor1+yourfactor2+yourfactor3+yourfactor5)^2,
data=yourdataframe)
if you want all interactions. Make sure all yourfactors
Peter
You question is difficult to answer without more information about the
distribution of your residuals. Different residual patterns call for
different transformations to stabilize the variance. One very common
form of heterocedasticity is increasing variance with increasing values
of an
Thank you for your answer.
I did try this but got similar errors. I tried all the other
spss-specific formats with same result.
A way to get access to the data is: save in sas-xport format (though
all labels are lost) then save in another sas-format and asking spss to
also save value labels
Thank you Michael
I think you point to the real cause of the problem.
I solved my own immediate problem by using StatTransfer to transfer from
sav to sav.
My real concern is that the read.spss() function will become obsolete.
Most of the data I have received in the last year have had those
Could someone give me a hand with the format of the gsummary function?
Basically, I have a large set of xyz coordinates generated by LiDAR data (37
million points) and I am trying to derive various summary statistics on the
z-coordinates by a grid cell. I wrote a function to do this by
Dear all,
I am analyzing some data that requires a mixed model. I have been
reading Pinheiro and Bates' book,
but cannot find the notation to fit the following model:
Suppose I have the dataset below. Here I am fitting variable p as a
fixed effect, variable h
as a random effect and variable t as
The gsummary function was intended to apply a summary function to each
column in each of the groups of observations. The (implicit)
definition of a summary function is that it produces a scalar from a
vector. (See the groupings of functions in Table A.1, p. 472 of
Statistical Models in S, a.k.a.
[Resending -- recipient list length issue]
John Sorkin [EMAIL PROTECTED] writes:
Peter
Erm, that was Paul's question, not mine! If you want to help, please
look at the pattern of residuals which he put up on the web on my
request
You question is difficult to answer without more
Hi all,
Is there any way to access a column of a data frame by its label (title)
rather than its column index? For example, I'd like to be able to select
animals[,weight] rather than animals[,3], if the third column of the
animals data frame has the label weight.
Thank you!
On Thu, 3 Aug 2006, Finn Sand? wrote:
My real concern is that the read.spss() function will become obsolete.
Most of the data I have received in the last year have had those
problems (and increasingly so), now they have become so serious that the
import process fails all together.
Therefore I
On 8/3/06, Frank Johannes [EMAIL PROTECTED] wrote:
Dear all,
I am analyzing some data that requires a mixed model. I have been
reading Pinheiro and Bates' book,
but cannot find the notation to fit the following model:
Suppose I have the dataset below. Here I am fitting variable p as a
fixed
?colnames
hih
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R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
On Thu, 2006-08-03 at 14:44 -0400, Neil McLeod wrote:
Hi all,
Is there any way to access a column of a data frame by its label (title)
rather than its column index? For example, I'd like to be able to select
animals[,weight] rather than animals[,3], if the third column of the
animals data
This works OK, but there is some extra spacing between the panels, the
top axis and the strip on the top, and the left labels and panel.
How can I remove these extra spaces?
I've tried changing various layout.widths settings with no luck. It
seems the spaces are calculated based on the number
Paul: It is too bad that most peoples statistical thought processes lead
them to thinking heterogeneity is something to overcome so that a simple
test of differences in means with ANOVA can be made. If you have that
much heterogeneity among 96 groups (hard for me to imagine otherwise),
Hi,
I need to read in some files. The file names contain come meta characters such
as @, #, and white spaces etc, In read.csv, file= option, is there any way that
one can make the function to recognize a file path with those characters?
Thanks
Johnny
[[alternative HTML version
What is the problem you are having? Seems to work fine for me running
under Windows2000:
write.table(data.frame(a=1:3,b=4:6), file=@# x.csv, sep=,)
read.csv(file=@# x.csv)
a b
1 1 4
2 2 5
3 3 6
sessionInfo()
Version 2.3.1 (2006-06-01)
i386-pc-mingw32
attached base packages:
[1]
(out - lmer(p ~ f - 1 + (1|h/t) + (1|j), set))
Doug:
It seems the nesting syntax is handled a bit differently. Is (1|h/t)
equivalent to the old lme nesting syntax?
__
R-help@stat.math.ethz.ch mailing list
On 7/21/06, Thomas Lumley [EMAIL PROTECTED] wrote:
On Fri, 21 Jul 2006, Valentin Dimitrov wrote:
Dear Leaf,
I modified your code as follows:
gamma.fun - function(mu,sd,start=100)
{
f.fn - function(alpha)
I found the answer to my problem.
stefano
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
Hi Sam,
How do I change the font size in the facet labels along the edges of the
plot?
Unfortunately, you can't currently change the size of those fonts.
However, it is on my todo list (as well as completely custom strip
functions) and should be available in the near future.
One thing you
You don't need to find out the column index. This works:
Df[5,'bat'] - 100
-Don
At 5:01 PM -0400 8/2/06, John Kane wrote:
Simple problem but I don't see the answer. I'm trying
to clean up some data
I have 120 columns in a data.frame. I have one value
in a column named blaw that I want to
Hi Adrian,
Thanks for the tip. I re-installed and everything seems to work just fine.
Thanks,
Jack.
Adrian DUSA [EMAIL PROTECTED] wrote: On Tuesday 01 August 2006 19:24, John
McHenry wrote:
[...]
Yes, I built R myself. I couldn't find a debian package for R 2.3.1. The
latest available is
--- Don MacQueen [EMAIL PROTECTED] wrote:
You don't need to find out the column index. This
works:
Df[5,'bat'] - 100
-Don
Thanks, I'd tried
Df[5, bat] - 100 :(
I never thought of the ' ' being needed.
At 5:01 PM -0400 8/2/06, John Kane wrote:
Simple problem but I don't see
I'm new to the list and I've been playing about with R for some months
now, mostly using the power analysis routines including the pwr
package.
I'm currently looking at a project which will require a
repeated-measures MANCOVA.
I've been reviewing the files available at CRAN, including
I'm not familiar with 'aov', but I have two observations that might
help you:
1. UNESTIMABLE VARIANCE COMPONENT
The variance component 'soiltype' is not estimable in your 'lme'
model:
lme(NA.1~soiltype*habitat,random=~1|destination/soiltype)
That's because each
On 8/3/06, John Kane [EMAIL PROTECTED] wrote:
--- Don MacQueen [EMAIL PROTECTED] wrote:
You don't need to find out the column index. This
works:
Df[5,'bat'] - 100
-Don
Thanks, I'd tried
Df[5, bat] - 100 :(
I never thought of the ' ' being needed.
Right -- the quotes are
I'm studying R in my free time. I want to build a vector where each
element is equal to the element before it in the sequence plus some
random tweak.
In python, I would write:
vec = [100] * 50 # make a 50-element list with each element set to 100
from random import randint
for i, v in
Evening all:
I'm taking a little time to experiment with R, Sweave, and Miktex/LaTex but
I've run up against some problems and -well- I hope that there are some on
the list who might have some suggestions. This will be kind of wordy as I
will include the complete files involved as I'm just not
When I run gnls I get the error:
Error in nls(y ~ cbind(1, 1/(1 + exp((xmid - x)/exp(lscal, data = xy, :
step factor 0.000488281 reduced below 'minFactor' of 0.000976563
My first thought was to decrease minFactor but gnlsControl does not contain
minFactor nor nlsMinFactor
On 8/3/2006 9:17 PM, Matthew Wilson wrote:
I'm studying R in my free time. I want to build a vector where each
element is equal to the element before it in the sequence plus some
random tweak.
In python, I would write:
vec = [100] * 50 # make a 50-element list with each element set to
On 4 August 2006 at 01:17, Matthew Wilson wrote:
| I'm studying R in my free time. I want to build a vector where each
| element is equal to the element before it in the sequence plus some
| random tweak.
|
| In python, I would write:
|
| vec = [100] * 50 # make a 50-element list with each
If you are willing to use grid then you could create only the sex
factor in the left strips since its already in the desired position
but when displaying it output a factor.level, i.e. label of A.
(my.strip.left is modified from the prior post to do that.)
Then after the plot is drawn, looping
Just sending this to you. One thing that might be easy to do
yet give a lot of flexibility is to:
1. put meaningful names on the grobs. Even with just this it would be
possible to do a getNames() in grid and then from inspection grid.edit
the appropriate one(s).
2. create a routine that
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