Please, experiment a little bit :-)
I have trouble using Win metafile graphics, so I just converted it to
jpeg. The code works - there was a copy/paste error. Try this with your
'total' dataframe - it works with my 'total' given there:
total -
Patrick Callier napsal(a):
rownames is the command you want, I think.
rownames(A) - seq(1:8)
Yes. More generally
rownames(A) - 1:length(A[,1])
And keep in mind that nobody is going to help you next time, if you
won't give a clear and informative SUBJECT in your message. Here it
should
On Tue, 17 Apr 2007, Petr Klasterecky wrote:
Patrick Callier napsal(a):
rownames is the command you want, I think.
rownames(A) - seq(1:8)
Yes. More generally
rownames(A) - 1:length(A[,1])
Better
rownames(A) - seq_len(nrow(A))
which works correctly if the length is 0 or there are zero
Thank You for answer. I Tried code that You provided in reply to my question
on both PC's with Linux and Widows OS.
On linux box output is:
xtable(diag(c($\\sigma_1^2$,$\\sigma_2^2$)))
% latex table generated in R 2.4.0 by xtable 1.4-3 package
% Tue Apr 17 09:18:31 2007
\begin{table}[ht]
Jorge Cornejo-Donoso wrote:
I'm using R in a winXp machine. I have problems with the size of my database
(xyz), anyone know if is possible to use some kind of swap memory, in order
to expand my real RAM and use HD space for the processes?
This is done automatically by your operating system.
Dear List,
How do I extract the approximate Wald test for the
frailty (in the following example 17.89 value)?
What about the P-values, other Chisq, DF, se(coef) and
se2? How can they be extracted?
##
kfitm1
Call:
coxph(formula = Surv(time,
Hi Jose,
Jose I'd like to simply add column-wise using Matrix objects (Csparse).
Jose It looks like one can apply mosty any base function to these objects
Jose (i.e., apply, colSums), but there is a nasty conversion to
traditional
Jose matrix objects if one does that.
not
hi,
I want to add different colors on the background of a classical plot. Each
color is associated to an interval of the x axis.
example: the background is red on the interval [1,10], blue on [11,20].
I try the rect function but it isn't appropriate for the background.
Can any one can
On Tue, 17 Apr 2007, Uwe Ligges wrote:
Jorge Cornejo-Donoso wrote:
I'm using R in a winXp machine. I have problems with the size of my database
(xyz), anyone know if is possible to use some kind of swap memory, in order
to expand my real RAM and use HD space for the processes?
This is
Dear R users,
I am new to R and I would like to ask your help with the following
topic. I have three sets of numeral data, 2 sets are paired and a
third is independent of the other two. For each of these sets I have
obtained their basic statistics (mean, median, stdv, range ...).
Now I
What do you mean by background? Maybe this is enough:
plot(seq(-3,3,.01), dnorm(seq(-3,3,.01)), type=n, xlab=x,
ylab=f(x), main=Normal density)
polygon(x=c(-4,0,0,-4), y=c(-1,-1,.5,.5), col=red)
polygon(x=c(4,0,0,4), y=c(-1,-1,.5,.5), col=blue)
lines(seq(-3,3,.01), dnorm(seq(-3,3,.01)), type=l,
Dear R list,
I've read the function writing sections on both An introduction to R and R
language Definition manuals but still don't understand why the following gives
an error message:
fun - function(x, ...) x + y
fun(1, y=2)
I get:
Error in fun(1, y = 2) : object y not found
I'd appreciate
Dear Juan,
You have to define your function like this:
fun - function (x,y=0, ...) {
x+y
}
The ... means that u can use the other parameters in par!
The variables, which you want to use, these you have to define in your
function!
In this function i put y=0 on a standard value zero,
if
Juan Lewinger wrote:
Dear R list,
I've read the function writing sections on both An introduction to R and R
language Definition manuals but still don't understand why the following
gives an error message:
fun - function(x, ...) x + y
fun(1, y=2)
I get:
Error in fun(1, y = 2) :
hi
+++
Now I want to compare if these sets differ. I could compare the mean
doing a basic T test . However, I was looking for a test to compare
the medians using R.
+++
@@@i hope but i am not sure that wilcoxon signed rank test may help :-)
cheers
Pedro A Reche [EMAIL PROTECTED]
ÇÎËÎÒÀß ÑÅÐÜÃÀ - ÈÇÁÀÂËÅÍÈÅ ÎÒ ËÈØÍÈÕ ÊÈËÎÃÐÀÌÌÎÂ (4 ÊÃ Â ÌÅÑ.)!!
ÎÃÐÎÌÍÎÅ ÊÎËÈ×ÅÑÒÂÎ ËÞÄÅÉ ÂÎ ÂÑÅÌ ÌÈÐÅ ÏÎÕÓÄÅËÈ ÁËÀÃÎÄÀÐß ÇÎËÎÒÎÉ ÑÅÐÜÃÅ
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ÑÒÎÈÌÎÑÒÜ ÂÑÅÃÎ ËÈØÜ ÇÎÎÎ ÐÓÁËÅÉ!!!
Ïðèíöèï ìåòîäà «Çîëîòàÿ Ñåðüãà» ñîçäàí íà îñíîâå
Pedro A Reche wrote:
Dear R users,
I am new to R and I would like to ask your help with the following
topic. I have three sets of numeral data, 2 sets are paired and a
third is independent of the other two. For each of these sets I have
obtained their basic statistics (mean, median,
Hello Sir/Mam
I am Nitish Kumar Mishra from IMTECH, Chandigarh, India. I want to
calculate the Principal Component Analysis(PCA), PLS of the input file and
find top 30 PCAs of this file using PLS in R. I am asking regarding
Linux(Red Hat 9) operating system.
I have downloaded PLS from Crains site
Robin Hankin wrote:
If iterative methods are appropriate,
it's perhaps worth pointing out that Newton-Rapheson
works nicely for complex functions.
Hmmm... I think there are many cases where Newton-Raphson
diverges for complex functions, like those that generate
beautiful fractals.
Alberto
Thomas Lumley wrote:
On Tue, 17 Apr 2007, Robert McFadden wrote:
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Jim Lemon
Sent: Tuesday, April 17, 2007 12:37 PM
To: Pedro A Reche
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] help comparing two
Hi,
Is there a way, documented or not, to extract the intercept term (the alpha_0
the MASS book) from a ppr() (Projection Persuit Regression) fit?
Thanks,
Vadim
## Example:
n - 1000
data - data.frame(x=rnorm(n), y=rnorm(n))
a - 10
data$z - evalq(a + atan(x + y) + rnorm(n), data)
I think there are many who can help, but this question is quite vague.
This assumes we have access to the book you note and can make sense of
your question w/o sample data.
If you cannot find a sample data set please create a sample data file.
However, there are so many sample data sets in the
Hi,
Is there a way, documented or not, to extract the intercept term (the alpha_0
the MASS book) from a ppr() (Projection Persuit Regression) fit?
Thanks,
Vadim
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing
From within R, you can give the command
install.packages(pls)
and R will download and install it for you (as long as you have access
to the Internet).
To install an already downloaded package, you can use
R CMD INSTALL pls_2.0-0.tar.gz
in a terminal window.
--
Bjørn-Helge Mevik
On Tue, 17 Apr 2007, Robert McFadden wrote:
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Jim Lemon
Sent: Tuesday, April 17, 2007 12:37 PM
To: Pedro A Reche
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] help comparing two median with R
Pedro
On 4/17/07, yannig goude [EMAIL PROTECTED] wrote:
I want to add different colors on the background of a classical plot. Each
color is associated to an interval of the x axis.
example: the background is red on the interval [1,10], blue on [11,20].
I try the rect function but it isn't
Hi R-users,
I want to calculate the sample size needed to carry out a 2-sample
proprotion test (with alfa=0.05, beta=0.8)
1.- probability of success in subpopulation A: 0.8
2.- probability of success in subpopulation B: 0.05
3.- percentage of population in subpopulation A = 5%,
4.- percentage
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Dear Partecipants to the list,
I am searching a R function, which can calculate the inverse of one real value
function.
Does it exists a R code in order to make it?
Many thanks for any kind of help and for Your availability.
Enrico Foscolo
Weiwei Shi writes:
I cannot reproduce the error w/o the data called probands
I realized this when I posted; sharing the data with anyone is not
possible (I hope you understand). I'm hoping a more experienced useR
can spot a syntax or procedural error that I made.
I have made some progress.
Dear All
Suppose a sequence of length 10 generated by the following rule: the
first element is 0 with 50% of probability or 1 with the same
probability; the second element likewise; and so on.
Is there some R command to obtain all possible different sequences
formed by the above rule? I am aware
On 4/17/07, Robin Hankin [EMAIL PROTECTED] wrote:
f - function(n){expand.grid(rep(list(0:1),n))}
f(10)
[snip]
Thanks, Robin, that is it!
Paul
On 17 Apr 2007, at 15:26, Paul Smith wrote:
Dear All
Suppose a sequence of length 10 generated by the following rule: the
first element is
In February (2/26) Jonathan Lees asked a question about plotting symbols
whose shape/aspect ratio is independent of of the user coordinate
system. A couple of other posts have also been made asking about
plotting symbols of a given fixed size/aspect ratio.
The latest version of the
Paul
f - function(n){expand.grid(rep(list(0:1),n))}
f(10)
[snip]
HTH
Robin
On 17 Apr 2007, at 15:26, Paul Smith wrote:
Dear All
Suppose a sequence of length 10 generated by the following rule: the
first element is 0 with 50% of probability or 1 with the same
probability; the second
On Tue, 17 Apr 2007, Greg Tarpinian wrote:
Hello,
I am using WinXP, R version 2.3.1, and SAS for PC version 8.1.
I have mostly used SAS over the last 4 years and would like to
compare the output of PROC DISCRIM to that of lda( ) with respect
to a very specific aspect. My data have k=3
On Tue, 17 Apr 2007, Robert McFadden wrote:
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Jim Lemon
Sent: Tuesday, April 17, 2007 12:37 PM
To: Pedro A Reche
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] help comparing two median with R
Pedro A
You didn't describe the exact format of the .gpr files.
There are 32 heading lines in each file, which are now hidden from R
community.
You 'skip' 31 of them in read.table, and one more plays header ('header=T').
Since you are using read.table, your files are usual ascii files.
You shoud use
--- Charilaos Skiadas [EMAIL PROTECTED] wrote:
On Apr 16, 2007, at 10:41 AM, John Kane wrote:
--- Charilaos Skiadas [EMAIL PROTECTED] wrote:
It is not an export option, it is a save as
option. I don't have
a 14 to check, but on a 15 I just go to File -
Save
As, and change
the
On 17-Apr-07 14:26:15, Paul Smith wrote:
Dear All
Suppose a sequence of length 10 generated by the following rule:
the first element is 0 with 50% of probability or 1 with the
same probability; the second element likewise; and so on.
You don't say whether the elements of the sequence are
Roger Bivand wrote:
Andris Jankevics andza at osi.lv writes:
Thank You for answer. I Tried code that You provided in reply to my question
on both PC's with Linux and Widows OS.
On linux box output is:
...
System information:
sessionInfo ()
R version 2.4.0 (2006-10-03)
On Tue, 17 Apr 2007, James W. MacDonald wrote:
Roger Bivand wrote:
Andris Jankevics andza at osi.lv writes:
Thank You for answer. I Tried code that You provided in reply to my question
on both PC's with Linux and Widows OS.
On linux box output is:
...
System information:
John Kane wrote:
--- Charilaos Skiadas [EMAIL PROTECTED] wrote:
On Apr 16, 2007, at 10:41 AM, John Kane wrote:
--- Charilaos Skiadas [EMAIL PROTECTED] wrote:
It is not an export option, it is a save as
option. I don't have
a 14 to check, but on a 15 I just go to File -
Save
As, and
Hello,
I import datas from an file with: readLines
But I need only a part of all measurments of this file. These are between
two borders START and END.
Can you tell me the syntax of grep(), to choose values between two borders?
My R Code was not succesful, and I can't finde anything in the help.
I am not sure what the question is but maybe this provides a starting point?
http://cran.r-project.org/bin/linux/ubuntu/README
HTH,
Roland
On 4/16/07, Erin Hodgess [EMAIL PROTECTED] wrote:
__
R-help@stat.math.ethz.ch mailing list
Assign the output of coxph to some object, and use the $ extractor function
to obtain what you need.
ie:
rtfm - coxph(formula = Surv(time, status) ~ age + sex + disease +
frailty(id, dist = gauss), data = kidney)
Age - coef(rtfm)[age]
OR
Sex - rtfm$coef[sex]
Hope this helps.
Paul
Mohammad
On Tue, 17 Apr 2007, Mohammad Ehsanul Karim wrote:
Dear List,
How do I extract the approximate Wald test for the
frailty (in the following example 17.89 value)?
The example you give silently invokes print.coxph() to produce that
output.
You _can_ use
tmp - capture.output( print(
Paul Smith wrote:
Dear All
Suppose a sequence of length 10 generated by the following rule: the
first element is 0 with 50% of probability or 1 with the same
probability; the second element likewise; and so on.
Is there some R command to obtain all possible different sequences
formed by
Hello,
I am using WinXP, R version 2.3.1, and SAS for PC version 8.1.
I have mostly used SAS over the last 4 years and would like to
compare the output of PROC DISCRIM to that of lda( ) with respect
to a very specific aspect. My data have k=3 populations and there
are 3 variates in the feature
Andris Jankevics andza at osi.lv writes:
Thank You for answer. I Tried code that You provided in reply to my question
on both PC's with Linux and Widows OS.
On linux box output is:
...
System information:
sessionInfo ()
R version 2.4.0 (2006-10-03)
i686-redhat-linux-gnu
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Jim Lemon
Sent: Tuesday, April 17, 2007 12:37 PM
To: Pedro A Reche
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] help comparing two median with R
Pedro A Reche wrote:
Dear R users,
I am new
I have problems with Tcl/Tk in R 2.4.1, when running it on Windows Vista
(see error message below).
Regards, Sofia
library(tcltk)
Loading Tcl/Tk interface ... Error in fun(...) : Can't find a usable
init.tcl in the following directories:
{C:\Program\R\R-2.4.1/Tcl/lib/tcl8.4}
May I suggest the Exam data from the mlmRev package as an example.
If you wish to have a random effect for Sex by school you could write
the model as
lmer(test.result ~ homework + Sex + (Sex|school))
which gives correlated random effects for the overall achievement in
schools and the
You can adapt this to your situation:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/22195.html
On 4/17/07, Felix Wave [EMAIL PROTECTED] wrote:
Hello,
I import datas from an file with: readLines
But I need only a part of all measurments of this file. These are between
two borders START and
2007/4/16, elyakhlifi mustapha [EMAIL PROTECTED]:
bonjour,
je vous écris pour savoir si vous aviez trouver réponse pour l'écriture du
test de Newman Keuls sous R car j'en ai aussi besoin
merci encore
cordialement.
-
[[alternative HTML
Dear Sir/Madam:
Could you please let me know which function shall I use to get the
Greatest common divisor of two numbers.
Thank you so much for your attention to this matter, and i look forward
to hear from you soon.
Regards;
Abou
==
AbouEl-Makarim Aboueissa, Ph.D.
S Poetry has a function for that.
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)
AbouEl-Makarim Aboueissa wrote:
Dear Sir/Madam:
Could you please let me know which function shall I use to get the
Greatest
Dear all,
I can use the very nice drc package (multdrc()) to model and plot a
dataframe containing dose and response values. I can also use
predict.drc() to yield response values given a dose. I need to do the
opposite, estimate a dose given the response. The general predict
documentation
Hi all R-users
Please, I would like to learn about 'contrasts'.
I do not know much about importance and several types (of contrasts)
over regression and data analysis.
I would like references for my study!
Thanks in advanced...
klebyn
Hi,
wouldn't it be enough for simple purposes (as stated in the original
message: Greatest common divisor of two numbers) to use:
gcd - function(a,b) ifelse (b==0, a, gcd(b, a %% b))
gcd(12,4)
[1] 4
gcd(4,12)
[1] 4
gcd(123456789,987654321)
[1] 9
gcd(987654321,123456789)
[1] 9
Best,
Roland
Hi,
What is the optimum range to look for a value of lambda while doing ridge
regression. Can/ should lambda be greater than 1 ?
I have conflicting (or what appears conflicting to me) sources that use lambda
= 0, without any upper limit, but that makes the search space infinite.. right
??
Hi everyone,
I am not sure this is the appropriate list I should put this question to,
but I hope you will re-direct me to the most appropriate one if necessary.
I am doing an independent component analysis on a dataset that represents
different metrics for patchreefs such as depth, area,
I have found a strange ifelse behaviour (I think)
This works:
ifelse(T,1+1,1+2)
[1] 2
ifelse(F,1+1,1+2)
[1] 3
Maybe I missed something about R internals, but why
ifelse(T,print(hello),print(goodbye))
[1] hello
[1] hello
ifelse(F,print(hello),print(goodbye))
[1] goodbye
[1] goodbye
values
one is returned value, the other one is the result from print
t0 - ifelse(T, print(h), print(e))
[1] h
t0
[1] h
HTH,
weiwei
On 4/17/07, Luca Braglia [EMAIL PROTECTED] wrote:
I have found a strange ifelse behaviour (I think)
This works:
ifelse(T,1+1,1+2)
[1] 2
ifelse(F,1+1,1+2)
[1]
On 4/17/07, Luca Braglia [EMAIL PROTECTED] wrote:
I have found a strange ifelse behaviour (I think)
Don't you think it is rather consistent behavior?
ifelse(T,1+1,1+2)
[1] 2
ifelse(F,1+1,1+2)
[1] 3
ifelse(T,hello,goodbye)
[1] hello
ifelse(F,hello,goodbye)
[1] goodbye
Thank you so much All.
It works.
Abou
==
AbouEl-Makarim Aboueissa, Ph.D.
Assistant Professor of Statistics
Department of Mathematics Statistics
University of Southern Maine
96 Falmouth Street
P.O. Box 9300
Portland, ME 04104-9300
Tel: (207) 228-8389
Email: [EMAIL
Thomas Lumley wrote:
There actually is an exact test for the median that does not assume a
location shift: dichotomize your data at the pooled median to get a 2x2
table of above/below median by group, and do Fisher's exact test on the
table.
Fascinating. But can one be sure that the
On 17/04/07 - 14:59, Roland Rau wrote:
On 4/17/07, Luca Braglia [EMAIL PROTECTED] wrote:
ifelse(T,1+1,1+2)
[1] 2
ifelse(F,1+1,1+2)
[1] 3
ifelse(T,hello,goodbye)
[1] hello
ifelse(F,hello,goodbye)
[1] goodbye
ifelse(T,print(hello),print(goodbye))
[1] hello
[1] hello
I suspect tcl's own version of 'access', but can you please confirm that
this still happens under 'Run as Administrator', assuming 'C:\Program' is
a system area in Swedish Windows Vista?
I will be able to take a closer look, but not before 2.5.0 (which is in
code freeze and I have limited
Hi,
I have a question regarding the impact of the pilot experiment on the
overall statistic interpretation of the subsequent work.
The context is as following:
In a lab there are one Professor and three graduate students A, B, and
C. They are working on analysis of some disease to discover
On Mon, 16-Apr-2007 at 10:12PM +0100, Prof Brian Ripley wrote:
| On Mon, 16 Apr 2007, Duncan Murdoch wrote:
| The name change happens in the conversion to a dataframe, so why not
| change the name afterwards? That is:
|
| df - data.frame(mat)
| names(df)[3] - 5T
| boxplot(df, main=blah blah
Sorry for triple-posting : I seem to have a problem w/ my mail client.
Hi,
Is there a way, documented or not, to extract the intercept term (the alpha_0
the MASS book) from a ppr() (Projection Persuit Regression) fit?
Thanks,
Vadim
## Example:
n - 1000
data - data.frame(x= rnorm (n),
Hello!
I am having issues trying to plot to a ong (or jpg) when the R-code in a
bash script is executed from cron.
I can generate a pdf file, but when I try to write to a png, the file is
created, but nothing is written. If I execute the bash script from my
console, everything works file. Any
Bruce,
Far below you ask for comment on an issue of statistical interpretation
of a collection of biological experiments.
Your university (judging from your email handle) has one of the best
statistics departments in the world and some of the best biostatisticians
in the galaxy.
You would
Ulrik Stervbo wrote:
Hello!
I am having issues trying to plot to a ong (or jpg) when the R-code in a
bash script is executed from cron.
I can generate a pdf file, but when I try to write to a png, the file is
created, but nothing is written. If I execute the bash script from my
Dear list,
I need to extract the approximate Wald test (Chisq) so
that I can put it in a loop. str seemed like a great
idea, but I cannot seem to find the approximate Wald
test for frailty (in the example data below: 17.89 and
its p-value 0.12000) there. I cannot seem to find it
in capture.output
Hi Mohammed,
Here's one way to get the information you need.
First I examined the output of your coxph() call:
library(survival)
kfitm1-coxph(formula = Surv(time, status) ~ age +
+ sex +disease + frailty(id, dist = gauss),
+ data = kidney)
class(kfitm1)
[1] coxph.penal coxph
On Tue, 17 Apr 2007, Frank E Harrell Jr wrote:
The points that Thomas and Brian have made are certainly correct, if one is
truly interested in testing for differences in medians or means. But the
Wilcoxon test provides a valid test of x y more generally. The test is
consonant with the
Or see png2() in R.utils, which imitates png() but uses bitmap(),
which in turn uses postscript-to-png via ghostscript. BTW, personally
I think PNGs generated via bitmap() look way better than the ones
generated via png().
/Henrik
On 4/17/07, Jeffrey Horner [EMAIL PROTECTED] wrote:
Ulrik
Dear Friends,
I have data set with around 220,000 rows and 17 columns. One of the columns is
an id variable which is grouped from 1000 through 9000. I need to perform the
following operations.
1) Remove all the observations with id's between 6000 and 6999
I tried using this method.
remdat1
(Versione italiana più sotto)
Sehr geehrte Damen und Herren
Wir haben bemerkt, dass viele Firmenemailadressen keine HTML-Emails
empfangen dürfen. Aus diesem Grund senden wir Ihnen unsere Einladung
auch in Textformat zu, damit Sie diese rechtzeitig erhalten, denn die
Anmeldefrist läuft bald ab.
Try this:
library(drc)
# get dose corresponding to response (y = 2)
model1 - multdrc(rootl ~ conc, data = ryegrass)
f - function(x, y) y - predict(model1, data.frame(conc = x))[1]
uniroot(f, c(0, 10), y = 2)
On 4/17/07, John McNeil [EMAIL PROTECTED] wrote:
Dear all,
I can use the very nice
On Apr 17, 2007, at 8:03 PM, Anup Nandialath wrote:
Dear Friends,
I have data set with around 220,000 rows and 17 columns. One of the
columns is an id variable which is grouped from 1000 through 9000.
I need to perform the following operations.
1) Remove all the observations with id's
Wow, thanks, that does it perfectly
John
On Apr 17, 2007, at 5:51 PM, Gabor Grothendieck wrote:
Try this:
library(drc)
# get dose corresponding to response (y = 2)
model1 - multdrc(rootl ~ conc, data = ryegrass)
f - function(x, y) y - predict(model1, data.frame(conc = x))[1]
uniroot(f,
Hi,
I often get a following error with R
*** caught segfault ***
address 0x78807e00, cause 'memory not mapped'
Possible actions:
1: abort (with core dump)
2: normal R exit
3: exit R without saving workspace
4: exit R saving workspace
Selection:
The system is OSX 4.9 and R-version 2.4.1.
Is
As I har problems installing the Cairo package, I went for Henriks solution
- and it works almost perfect. I would like to have been able to generate
transparent png.
Thanks for the help
Ulrik
On 18/04/07, Henrik Bengtsson [EMAIL PROTECTED] wrote:
Or see png2() in R.utils, which imitates png()
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