On 7/12/07, Pete Kazmier [EMAIL PROTECTED] wrote:
I'm an R newbie but recently discovered the ggplot2 and reshape
packages which seem incredibly useful and much easier to use for a
beginner. Using the data from the IMDB, I'm trying to see how the
average movie rating varies by year. Here is
Dear list members
I am still a newbie so might be asking a stupid question, but I can't get
ggplot to work in a loop (or a while statement for that matter).
# to take a minimal example -
mydata$varc = c(1,2,3)
for (i in 1:1){
jpeg(test3.jpg)
plot(mydata$varc)
Hi Steve,
You need to explicitly print the ggplot object:
ggplot(mydata, aes(x=mydata$varc)) + geom_bar()
(this is a R-faq for lattice plots, and ggplot works the same way)
In the latest version of ggplot (0.5.4) you can construct the plot
before hand and modify the aesthetics in each instance
Hi: I am trying to migrate from Systat to R but I am facing my first
challenge. While I easily can get weekly co-variance for my data, I can't
seem to acomplish this with R ( I can't figure out how is done) If
interested in looking a sample of my data, please check the data
below. In Systat
Hi, dear R-users,
I am computing a liner regression by rating category using the 'by' function
as stated below:
tmp - by(projet, rating, function(x) lm(defaults ~ CGDP+CSAVE+SP500, data =
x))
I would like to get not only the coefficients but also their p-values. I
can't find the command in the
On 7/12/07, Benoit Chemineau [EMAIL PROTECTED] wrote:
Hi, dear R-users,
I am computing a liner regression by rating category using the 'by' function
as stated below:
tmp - by(projet, rating, function(x) lm(defaults ~ CGDP+CSAVE+SP500, data =
x))
I would like to get not only the
On 7/11/07, Leigh E Alexander [EMAIL PROTECTED] wrote:
i have a 3 x 4 x 2 repeated measures design. All of the IVs are within
subjects.I do also have missing values (unequal N), as I have to
remove any incorrect trials for each subject.
Hum, you mean there are empty cells in table(sid,
try the following:
tmp - by(projet, rating, function (x) Thursday, 12.July.2007{
fit - lm(defaults ~ CGDP + CSAVE + SP500, data = x)
summary(fit)$coefficients
})
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Dear friends,
I am having some doubts about the amount of memory that is being used by
R in my Mac (MacBook Pro, 2Gig). Is there a way to increase the amount
of memory used?
When I type:
mem.limits()
the result is:
nsize vsize
NANA
and I can't change it, tough my computing in R
The aliasing problem arises in alias(), which is what Anova uses to detect
aliasing. It is simply the fact that anova more or less blithely ignores the
NA's that makes anova behave apparently more 'sensibly' than Anova.
But like Carsten, I found this difficult to understand. Unordered factors
Hi Massimo,
Professor Ripley has given you your answer.
It may help you further to know that factor levels aren't automatically
dropped when you subset a data set; you have to do it manually. Some time
ago I scrounged the following command from Andy Liaw's randomForest package:
it removes all
On Thu, 12 Jul 2007, hadley wickham wrote:
On 7/12/07, Benoit Chemineau [EMAIL PROTECTED] wrote:
Hi, dear R-users,
I am computing a liner regression by rating category using the 'by' function
as stated below:
tmp - by(projet, rating, function(x) lm(defaults ~ CGDP+CSAVE+SP500, data =
x))
2007/7/12, Carlos Guerra [EMAIL PROTECTED]:
Dear friends,
I am having some doubts about the amount of memory that is being used by
R in my Mac (MacBook Pro, 2Gig). Is there a way to increase the amount
of memory used?
When I type:
mem.limits()
the result is:
nsize vsize
NANA
On 7/12/07, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Thu, 12 Jul 2007, hadley wickham wrote:
On 7/12/07, Benoit Chemineau [EMAIL PROTECTED] wrote:
Hi, dear R-users,
I am computing a liner regression by rating category using the 'by'
function
as stated below:
tmp -
I have the following problem. I have measured a dose response curve
(binary response, continuous dose) on a grid of x,y positions. I would
like to produce a grey-level plot that shows the LD50 at each (x,y)
position.
I am thinking that I have to do something like
fit-glm(resp ~ x*y + dose, family
Hi,
many thanks for the answer.
It ist true, that for example
m1 - SMO(Species ~ ., data = iris, control = Weka_control( K =
weka.classifiers.functions.supportVector.PolyKernel))
m2 - SMO(Species ~ ., data = iris, control = Weka_control( K =
A question about vectorized operations (avoiding loops, for speed)...
I need to run a simple recursive (autoregressive) filter with a
time-varying coefficient. It is just a one-step recursive filter, so
it would be an exponential decay if the filter was constant.
I just want to do this, where
Hi, I would like to use the function pairs() to plot a matrix of
scatterplots. For each scatterplot, the data are plotted in circles, can I
add some argument to change the circles into dots?
Could anyone give me some advice?Many thanks
--
View this message in context:
Hello everybody,
I have a problem similar to that reported by Felipe. I installed R
2.5.0, Rcmdr from CRAN and SciViews-R 0.8-9 (with all the required and
optional components).
When accessing the R Commander menu from within
SciViews, the links cannot be clicked. When pointing at them, the mouse
Hello,
I got this email address from
http://tolstoy.newcastle.edu.au/R/e2/help/06/10/2516.html, I got started to
use R recently, Can I ask you a question ?
this is what I am using:
platform i686-pc-linux-gnu
arch i686
os linux-gnu
system i686, linux-gnu
status
m - matrix( rnorm(300), nc=3 )
pairs(m, pch=20)
or pairs(m, pch=.)
See help(par) for more details.
livia wrote:
Hi, I would like to use the function pairs() to plot a matrix of
scatterplots. For each scatterplot, the data are plotted in circles, can I
add some argument to change the circles
As explained on the web page from where you downloaded SciViews 0.8-9,
this version is not compatible with R 2.5.0.
Best,
Philippe Grosjean
..∞}))
) ) ) ) )
( ( ( ( (Prof. Philippe Grosjean
) ) ) ) )
( ( ( ( (Numerical Ecology of
Hi,
is there any function in R that shifts elements of a vector to the
opposite direction of what Lag() of the Hmisc package does? (something
like, Lag(x, shift = -1) )
Thanks
Zava
This is not an offer (or solicitation of an offer)
--- Donatas G. [EMAIL PROTECTED] wrote:
Hi, I am trying to learn some basic statistics stuff
but I cannot find any
elementary statistics exercises using R language.
Using RKward would be even
better...
I need that in analysing sociological data, obtained
through questionnairres -
Hi Bill,
have a look at the following artificial example:
## Loading the package 'drc' (on CRAN)
library(drc)
## Generating dataset with four dose-response curves
finneyx4 - rbind(finney71, finney71, finney71, finney71)
## Generating artificial points (x,y)
## different pairs for each of the 4
This is the R-help mailing list. See help(BATCH).
You will need to write the required R commands in a separate script, say
script.R and then execute it as
R --no-save script.R logfile
You may need to augment the code above to include directory paths etc.
There are other useful
Well.. plans are there from a long time to rewrite SciViews completely
and make it platform independent (to work on Linux/Unix and MacOS X, as
well as Windows). I have done some work in this direction when time
permitted, but I am pretty busy with other work. During the holidays, I
will continue
Thank you very much for your help.
Adaikalavan Ramasamy wrote:
m - matrix( rnorm(300), nc=3 )
pairs(m, pch=20)
or pairs(m, pch=.)
See help(par) for more details.
livia wrote:
Hi, I would like to use the function pairs() to plot a matrix of
scatterplots. For each scatterplot, the
Thank you for the pointer.
On the SciViews official site
(http://www.sciviews.org/SciViews-R/index.html) I could not find any
indications on this incompatibility. At any rate, I would have two
questions related to the future of SciViews-R.
Are there any developments planned in some near future
Hi everyone,
I did my homework and read the posting guideline :-)
I want to eMail the results of a computing automatically. So I get the results
(the parameters of a garch process) and I want to eMail them to another person.
How can I do that?
Thx
__
Thomas
How about
revLag - function(x, shift=1) rev( Lag(rev(x), shift) )
x - 1:5
revLag(x, shift=2)
As a matter of fact, here is a generalized version of Lag to include
negative shifts.
myLag - function (x, shift = 1){
xLen - length(x)
ret - as.vector(character(xLen), mode =
Hi
I wonder if anyone has had any thoughts about rendering R graphical output
into XAML?
Gordon M. Morrison
HSBC Bank plc
8 Canada Square
London
E14 5HQ
-
SAVE PAPER - THINK
Dear Carsten
In this test, factor B would be representing to a factor of block or repetition
according to as the levels of A, B, and C are in the data. Factor C this nested
in A, then the model should include: B, A and C nested in A, the difference it
is the error.
Model:
B 1
A 2
The question was how to get the p-value from the fit below, as an S object
sr-survreg(s~groups, dist=gaussian)
Coefficients:
(Intercept) groups
-0.02138485 0.03868351
Scale= 0.01789372
Loglik(model)= 31.1 Loglik(intercept only)= 25.4
Chisq= 11.39 on 1 degrees of freedom, p=
Hi there, I hope someone can help me before I tear all my hair out. I have a
set transition intensities and when plotted the curve looks like a gamma
density. I want to fit a gamma density curve to these intensities. It is
just a curve fitting problem but whats causing the trouble is that I need
The lag.zoo method of lag in the zoo package supports positive, negative
and multiple lags and has an na.pad= argument. (zoo also has a
lag.zooreg method, not shown, for zooreg objects):
library(zoo)
z - zoo(11:15)
z
1 2 3 4 5
11 12 13 14 15
lag(z, na.pad = TRUE)
1 2 3 4 5
12 13 14
Hi users,
I need to calculate .632 (and .632+) bootstrap and the cross-validation of
area under curve (AUC) to compare my models. Is there any package for the
same. I know about 'ipred' and using it i can calculate misclassification
errors.
Please help. It's urgent.
--
View this message in
On 7/12/07, Terry Therneau [EMAIL PROTECTED] wrote:
The question was how to get the p-value from the fit below, as an S object
sr-survreg(s~groups, dist=gaussian)
Coefficients:
(Intercept) groups
-0.02138485 0.03868351
Scale= 0.01789372
Loglik(model)= 31.1 Loglik(intercept only)=
hadley wickham [EMAIL PROTECTED] writes:
On 7/12/07, Pete Kazmier [EMAIL PROTECTED] wrote:
I'm an R newbie but recently discovered the ggplot2 and reshape
packages which seem incredibly useful and much easier to use for a
beginner. Using the data from the IMDB, I'm trying to see how the
We use a program called Blat (www.blat.net) on Windows to email out
results of overnight runs. If you're on Unix/Linux you can definitely do
a similar thing using one of the hundreds of command line utils.
The R code is similar to below:
sendEmail - function(from, to, subject, body)
{
BLAT -
On 7/12/2007 9:52 AM, [EMAIL PROTECTED] wrote:
Hi everyone,
I did my homework and read the posting guideline :-)
I want to eMail the results of a computing automatically. So I get the
results (the parameters of a garch process) and I want to eMail them to
another person. How can I do
Hi,
There is a paper in the April 2007 issue of R News that might be of help
here.
http://##cran mirror##/doc/Rnews/Rnews_2007-1.pdf
Romain
Duncan Murdoch wrote:
On 7/12/2007 9:52 AM, [EMAIL PROTECTED] wrote:
Hi everyone,
I did my homework and read the posting guideline :-)
I want to
Here is a small function that I used on Debian. It requires exim4 :
send.mail-function(addr='[EMAIL PROTECTED]',subject='A
message from R',
text=paste(I have finished to work
,Sys.time(),coll=)){
# send an email
# it requires the reconfiguration of exim4
# you
Hi
I recently imported data from r into Stata. I then ran the linear
regression model I've been working on, only to discover that the results are
somewhat (though not dramatically different). the standard errors vary more
between the two programs than do the coefficients themselves. Any
Thank you very much for the prompt reply. Seems like I had not fully
understood what the k-parameter to stepAIC is doing.
Your suggested approach looks indeed fine to me, actually I do not
quite understand why you say that it's only an approximation to the
LRT?
Best wishes-
Lutz
On 7/11/07, Ravi
On 12-Jul-07 13:52:56, [EMAIL PROTECTED] wrote:
Hi everyone,
I did my homework and read the posting guideline :-)
I want to eMail the results of a computing automatically. So I get the
results (the parameters of a garch process) and I want to eMail them to
another person. How can I do
On Thu, 12 Jul 2007, Duncan Murdoch wrote:
On 7/12/2007 9:52 AM, [EMAIL PROTECTED] wrote:
Hi everyone,
I did my homework and read the posting guideline :-)
But failed to follow it, and not telling us the OS makes this very much
harder to answer adequately.
I want to eMail the results of a
On 12-Jul-07 16:10:46, Stéphane Dray wrote:
Here is a small function that I used on Debian. It requires exim4 :
send.mail-function(addr='[EMAIL PROTECTED]',subject='A
message from R',
text=paste(I have finished to work
,Sys.time(),coll=)){
# send an email
#
Can anyone help me?
I'm having problems with the following code where I want to test the null
hypothesis that regression slopes are the same among regressions. Here's the
code I've written with comments that include the final error I get. ...
initial.dir - getwd()
library(systemfit)
On 7/12/07, hadley wickham [EMAIL PROTECTED] wrote:
Hi Steve,
You need to explicitly print the ggplot object:
ggplot(mydata, aes(x=mydata$varc)) + geom_bar()
(this is a R-faq for lattice plots, and ggplot works the same way)
In the latest version of ggplot (0.5.4) you can construct the
Hello,
I'm trying to overlap a contour and a filled.contour:
as I read in a previous post this can be done
calling contour() in the plot.axes of filled.contour.
When I do it (see example below) the contour is placed
instead of the color bar, while the filled.contour
is not drawn at all, which is
spime wrote:
Hi users,
I need to calculate .632 (and .632+) bootstrap and the cross-validation of
area under curve (AUC) to compare my models. Is there any package for the
same. I know about 'ipred' and using it i can calculate misclassification
errors.
Please help. It's urgent.
See
David Kaplan-2 wrote:
Greetings,
I'm interested in generating data from various bivariate or
mulitivariate distributions (e.g. gamma, t, etc), where I can specify
the parameter values, including the correlations among the variables. I
haven't been able to dig anything up on the
Hi, All;
I tried to load the 'genetics' library but it failed with the
following message. Can you help me with this? Thanks in advance.
library(genetics)
Loading required package: gdata
Error in dyn.load(x, as.logical(local), as.logical(now)) :
unable to load shared library
Hi,
I have to generate 10 cdfs in a graph. I need to compare the cdf's
nature by plotting ten cdfs in a graph. Thus, I need multiple plots in a
graph.
I would appreciate if you could give some solution to the problem asap.
Thanking you,
Sincerely,
Ajay.
--
Ajay Singh
Research Scientist,
Hello,
I believe this is an easy scripting problem, but one I am stumbling on.
I have a known vector of 3 colors with nrow=10:
known-c(red, blue, red, red, yellow, blue, yellow, blue,
blue, yellow)
and a model output vector:
modelout-c(red, red, red, blue, yellow, blue, blue, red,
blue, yellow)
This must be a very simple question, but I can't find any information
on it elsewhere, sorry. When extracting information from a list using
column headers, how do I get R to interpret something as a variable
rather than a string? For example:
xx$YAL002
works, but this doesn't:
gene - YAL002
Is there a way in ggplot to make a histogram with the left-hand y-axis
label as frequency, and a right-hand y-axis label as percentage?
Thanks!
Pete
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Hi,
I have a data.frame which is ordered by score, and has a factor column:
Browse[1] wc[c(report,score)]
report score
9 ADEA 0.96
8 ADEA 0.90
11 Asylum_FED9 0.86
3 ADEA 0.75
14 Asylum_FED9 0.60
5 ADEA 0.56
13 Asylum_FED9 0.51
16
On 7/12/07, Pete Kazmier [EMAIL PROTECTED] wrote:
hadley wickham [EMAIL PROTECTED] writes:
On 7/12/07, Pete Kazmier [EMAIL PROTECTED] wrote:
I'm an R newbie but recently discovered the ggplot2 and reshape
packages which seem incredibly useful and much easier to use for a
beginner. Using
Use xx[[gene]] instead of xx$gene (the $ is a shorthand for [[ with some
extra magic to be more convenient, the magic is getting in your way, so
go back to the [[ syntax (make sure you double the braces)).
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain
Try something like:
mytable - table(known, modelout)
prop.table( mytable, 1 )
Also look at ?addmargins and the CrossTable function in the gmodels
package.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
Hi, All;
I simply upgraded my R from version 2.5.0 to 2.5.1 and the whole
problems disappeared.
So I am closing the question myself. It could have been the R version
problem.
Tae-Hoon Chung
Post-Doctoral Researcher
Computational Biology Division, TGEN
445 N 5th St. Phoenix, AZ 85004 USA
O:
Look at ?ave and try something like:
wc$rank - ave( wc$score, wc$report, FUN=rank )
This works even if the dataframe is not pre sorted.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
-Original
On Thu, 12 Jul 2007, Lutz Ph. Breitling wrote:
Thank you very much for the prompt reply. Seems like I had not fully
understood what the k-parameter to stepAIC is doing.
Your suggested approach looks indeed fine to me, actually I do not
quite understand why you say that it's only an
On 7/12/07, Pete Kazmier [EMAIL PROTECTED] wrote:
Is there a way in ggplot to make a histogram with the left-hand y-axis
label as frequency, and a right-hand y-axis label as percentage?
Not currently. I did a quick exploration to see if it was feasible to
draw another axis on with grid, but it
Ajay Singh wrote:
Hi,
I have to generate 10 cdfs in a graph. I need to compare the cdf's
nature by plotting ten cdfs in a graph. Thus, I need multiple plots in a
graph.
I would appreciate if you could give some solution to the problem asap.
plot(ecdf(rnorm(10)))
Seems to work, if I unlist the argument at first ;-)
Atte
Hi,
What's wrong here?:
v=c(`-`,`+`,1,`^`,`^`,NA,NA,X,9,X,2)
i2=16
v[i2]
[[1]]
NULL
is.null(v[i2])
[1] FALSE
Is it a bug or have I misunderstood something?
Atte Tenkanen
University of Turku, Finland
On 12-Jul-07 17:32:03, Scott Bearer wrote:
Hello,
I believe this is an easy scripting problem, but one I am stumbling on.
I have a known vector of 3 colors with nrow=10:
known-c(red, blue, red, red, yellow, blue, yellow,
blue,
blue, yellow)
and a model output vector:
modelout-c(red,
Is this what you are looking for:
x
report score
9 ADEA 0.96
8 ADEA 0.90
11 Asylum_FED9 0.86
3 ADEA 0.75
14 Asylum_FED9 0.60
5 ADEA 0.56
13 Asylum_FED9 0.51
16 Asylum_FED9 0.51
2 ADEA 0.42
7 ADEA 0.31
17 Asylum_FED9 0.27
1
Hi,
What's wrong here?:
v=c(`-`,`+`,1,`^`,`^`,NA,NA,X,9,X,2)
i2=16
v[i2]
[[1]]
NULL
is.null(v[i2])
[1] FALSE
Is it a bug or have I misunderstood something?
Atte Tenkanen
University of Turku, Finland
__
R-help@stat.math.ethz.ch mailing list
Hello, R experts,
Sorry for asking this question again again since I really want a help!
I have a two-factor experiment data and like to calculate estimates of
interation contrasts say factor A has levels of a1, a2, and B has
levels of b1, b2, b3, b4, and b5 with 3 replicates. I am not sure the
hadley wickham [EMAIL PROTECTED] writes:
On 7/12/07, Pete Kazmier [EMAIL PROTECTED] wrote:
Is there a way in ggplot to make a histogram with the left-hand y-axis
label as frequency, and a right-hand y-axis label as percentage?
Not currently. I did a quick exploration to see if it was
Why are you using order instead of rank?
If the data is pre sorted then they tend to give the same result (unless
there are ties), but if your data is not presorted, then the results
will be different.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL
Hi All,
I want to automatically generate a number of data frames, each with an
automatically generated name and an automatically generated number of
rows. The number of rows has been calculated before and is different for
all data frames (e.g. c(4,5,2)). The number of columns is known a priori
Sorry if this isn't the correct list, but I couldn't find any mailing
lists on the JRI site. I am able to install JRI on a 32 bin linux
machine without any problem, but I am unable to isntall on a 64 bit
machine. I have R installed with the correct option, R_HOME is set up
and libR.so is in
Ken Williams wrote:
Hi,
I have a data.frame which is ordered by score, and has a factor column:
Browse[1] wc[c(report,score)]
report score
9 ADEA 0.96
8 ADEA 0.90
11 Asylum_FED9 0.86
3 ADEA 0.75
14 Asylum_FED9 0.60
5 ADEA
Replace
assign(nam, 1:auto.length[i])
with
assign(nam,data.frame(matrix(1:auto.length[i], ncol=3)))
Verify if the matrix (and hence the data frame) is filled the way you
intended. Otherwise, use the argument byrow=T.
Julian M. Burgos
Fisheries Acoustics Research Lab
School of Aquatic and
Hi All,
I want to automatically generate a number of data frames, each with an
automatically generated name and an automatically generated number of
rows. The number of rows has been calculated before and is different for
all data frames (e.g. c(4,5,2)). The number of columns is known a priori
On 7/12/07, Atte Tenkanen [EMAIL PROTECTED] wrote:
Seems to work, if I unlist the argument at first ;-)
Atte
Hi,
What's wrong here?:
v=c(`-`,`+`,1,`^`,`^`,NA,NA,X,9,X,2)
i2=16
v[i2]
[[1]]
NULL
is.null(v[i2])
[1] FALSE
Is it a bug or have I misunderstood something?
Hi.
I have defined a function, f1, that calls another function, f2. Inside f1
an intermediate variable called nm1 is created; it is a matrix. f2 takes a
matrix argument, and I defined f2 (schematically) as follows:
f2-function(nmArg1=nm1,...){nC-ncol(nmArg1); ... }
so that it expects nm1 as
On 12/07/2007 7:23 PM, Talbot Katz wrote:
Hi.
I have defined a function, f1, that calls another function, f2. Inside f1
an intermediate variable called nm1 is created; it is a matrix. f2 takes a
matrix argument, and I defined f2 (schematically) as follows:
Is this what you want to do:
auto.length - c(12,15,6)
for(i in 1:3) {
+ nam - paste(auto.data,i, sep=.)
+ assign(nam, as.data.frame(matrix(1:auto.length[i], ncol=3)))
+ }
auto.data.1
V1 V2 V3
1 1 5 9
2 2 6 10
3 3 7 11
4 4 8 12
auto.data.2
V1 V2 V3
1 1 6 11
2 2 7 12
3 3 8 13
'v' appears to be a list:
v=c(`-`,`+`,1,`^`,`^`,NA,NA,X,9,X,2)
i2=16
v[i2]
[[1]]
NULL
str(v)
List of 11
$ :function (e1, e2)
$ :function (e1, e2)
$ : num 1
$ :function (e1, e2)
$ :function (e1, e2)
$ : logi NA
$ : logi NA
$ : chr X
$ : num 9
$ : chr X
$ : num 2
because you
Its desirable to put the data frames into a list so they can be easily
iterated over in the future. Try this:
auto.length - 2:4 # replace with desired row lengths
f - function(names, nr) {
x - rep(0, nr)
data.frame(X1 = x, X2 = x, X3 = x)
}
auto.names - paste(auto.data,
Is there a way, maybe using Duncan TL's RCurl, to efficiently test whether
an URL such as
http://$CRAN/src/contrib/
has changed? I.e. one way is via a test of a page in that directory as per
(sorry about the long line, and this would be on Linux with links and awk
installed)
Hi Dirk,
Dirk Eddelbuettel [EMAIL PROTECTED] writes:
Is there a way, maybe using Duncan TL's RCurl, to efficiently test whether
an URL such as
http://$CRAN/src/contrib/
has changed? I.e. one way is via a test of a page in that directory as per
(sorry about the long line, and this
On 12 July 2007 at 19:46, Seth Falcon wrote:
| Hi Dirk,
|
| Dirk Eddelbuettel [EMAIL PROTECTED] writes:
| Is there a way, maybe using Duncan TL's RCurl, to efficiently test whether
| an URL such as
|
| http://$CRAN/src/contrib/
|
| has changed? I.e. one way is via a test of a page
Hello all.
I'm working on a PhD thesis analyzing reproducibility/repeatability of a
nuclear medicine examination. I have two sets of data (50 patients each)
and 3 observers. In each case (patient), two variables are evaluated,
first with a range of 0..100 and second 1..3. Each case is also
Hello all,
I am using lme4 to fit some mixed logistic regressions. I need to
impose an identification constraint of the following form:
(1sig12)
(sig12 sig22)
and have not figured out how to do it, i.e., sig11 = 1 but the rest of
the parameters are free to vary. Is this possible and,
I'm not sure why you want to do it this way (it would probably help if
we had a more complete picture of what you were really trying to do, but
here are a few possibilities for the questions you ask.
1. generating data frames.
rw - c(4,5,2)
cl - c(3,3,3)
for(i in 1:length(rw))
Hi,
I have two problems in R.
1. I need 10 cdfs on a graph, the graph needs to have legend. Can you let
me know how to get legend on the graph?
2. In ecdf plot, I need to know the x and y co-ordinates. I have to get
corresponding y coordinate values to x coordinate value so that I could be
Our experience (and that of several others) is that you need Java 1.6 on
x86_64 Linux for any of the JNI-using R packages to work correctly. E.g.
the CRAN check machine is using 1.6.
On Thu, 12 Jul 2007, chuckanut wrote:
Sorry if this isn't the correct list, but I couldn't find any mailing
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