Carmen Meier wrote:
Hi to all
I would to determinate whether bits is a binary code and I would to find
out the which bit is set to 1
bits -00110110
I found to detect whether there are only numbers
all.digits(bits)
but is there any function to detect whether there are only 0 and 1 in
the
Dear Carmen,
length(grep([^01], bits)) == 0
should do the trick, returning TRUE if the string contains only 0's and 1's.
I hope this helps,
John
John Fox
Department of Sociology
McMaster University
Hamilton, Ontario
Canada L8S 4M4
905-525-9140x23604
Hi
gregexpr can be used
bits -0011011aaa0
gregexpr([01], bits)
[[1]]
[1] 1 2 3 4 5 6 7 11
attr(,match.length)
[1] 1 1 1 1 1 1 1 1
or
grep([^01], bits)
if you want to know that there is any other character then 0 or 1
gregexpr(1, bits)
if you want to know location of 1's
HTH
Petr
On
Try:
# TRUE if all 0 and 1
regexpr(^[01]*$, bits) 0
# positions of 1s
gregexpr(1, bits)[[1]]
On 11/29/06, Carmen Meier [EMAIL PROTECTED] wrote:
Hi to all
I would to determinate whether bits is a binary code and I would to find
out the which bit is set to 1
bits -00110110
I found to
