Cameron,
In your example, I think P is the only matrix with 0-1 entries that
has the given row and column sums.
In general, I would solve the problem simulating a Markov Chain. Start
from a given incidence matrix A and iterate the following steps:
(1) select two rows, a, b, and two columns, i, j, at random.
(2) If A[c(a,b), c(i,j)] is of one of the forms
1 0 or0 1
0 1 1 0
then set it to the other, i.e. set
A[c(a,b), c(i,j)] - A[c(b,a), c(i,j)].
After sufficiently many iterations, A will have a uniform
distribution.
Giovanni
Date: Thu, 19 Oct 2006 15:49:55 -0400
From: Guenther, Cameron [EMAIL PROTECTED]
Sender: [EMAIL PROTECTED]
Precedence: list
Thread-topic: [R] randomize a matrix
Thread-index: Acbzt8BjJUXZEHZgQNaMi9gYYuh3Sg==
Hello everyone,
If I have an incidence matrix of 0 and 1's
P=[1 1 1 1 1 1
1 1 1 1 0 0
1 1 1 0 0 0
1 1 1 0 0 0
1 1 0 0 0 0]
I want to create a new uniform random matrix [a] that is filled with 0's
and 1's but constrained so that the row and column sums are the same as
in [P]. Does anyone know how to accomplish this?
Thanks in advance
Cameron Guenther, Ph.D.
Associate Research Scientist
FWC/FWRI, Marine Fisheries Research
100 8th Avenue S.E.
St. Petersburg, FL 33701
(727)896-8626 Ext. 4305
[EMAIL PROTECTED]
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[ Giovanni Petris [EMAIL PROTECTED] ]
[ Department of Mathematical Sciences ]
[ University of Arkansas - Fayetteville, AR 72701 ]
[ Ph: (479) 575-6324, 575-8630 (fax) ]
[ http://definetti.uark.edu/~gpetris/ ]
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