Dear List,
I have fitted a spherical function to my variogram using variofit(...)
from GeoR. Now I would like to predict some data with the function
predict(object,...) from package stats. Does anyone know wether this
works and if it does how to do it?
Thanks a lot!
Anna
Hello,
I want to replace specific values in a STFDF object from the spacetime package.
As example consider the following stfdf object out of the vignette.
sp = cbind(x = c(0,0,1), y = c(0,1,1))
row.names(sp) = paste(point, 1:nrow(sp), sep=)
sp = SpatialPoints(sp)
time = xts(1:4,
Hi Xin,
Yes, I came across this exact problem. The bug has been fixed in the latest
release (1.8-0), but it isn't fixed in the stable release (1.7-46).
You can pick up the latest, by typing:
install.packages(raster, repos=http://R-Forge.R-project.org;)
But be sure to either unload the raster
Hi Martin,
You put the brackets in the wrong place. You want to subset the dataframe,
right, not the stfdf object, so:
stfdf@data$values[1] - stfdf@data$values[1] + 1
would increase the value in the first row of the stfdf@data data frame.
stfdf@data[,1]
would get you the first column of the
Hi,
thank you very much. But actually that is not exactly what I want to do. I want
to select a specific time
range and spatial points and manipulate the corresponding data. When I subset
the dataframe I must do
the selection manually and that is not that nice.
Any idea how I could do this?
Hi Martin,
Yeah, you can't replace values like that... here is a way to think about it.
Consider:
stfdf[,1]
This returns a *completely new* spacetime object. You cannot set anything in
this object because it has not been assigned to any variable.
So, if you select
stfdf[ , 1]@data$values
What Martin wants, replacing a subset, is not possible for STFDF (or
other ST*) objects, just as with Spatial* objects:
library(sp)
data(meuse)
coordinates(meuse)=~x+y
meuse[1, zinc] = 500
Error in meuse[1, zinc] = 500 : object of type 'S4' is not subsettable
Indeed, as Aman suggests, this could
