. If that happens,
then you can create the data for a histogram yourself by using the
function 'freq', perhaps after 'reclassify' (and then probably
'barplot').
Robert
On Tue, Nov 18, 2014 at 9:56 AM, Nuno Sá nunocesard...@gmail.com wrote:
Hello!
My aim is to add a Median or a Mean line
Hello!
My aim is to add a Median or a Mean line to an histogram plot in R.
The problem is the following:
The hist function from the raster package uses a maximum of 100 000
values for generating the histogram but allows me to edit the plot, so I
can easily add a line within the plot using
:
require(stats)
set.seed(14)
x - rchisq(100, df = 4)
hist(x)
meanx-mean(x)
meanx
[1] 3.734162
abline(v=meanx, col=red)
Cheers!
Tom
On Tue, Nov 18, 2014 at 10:56 AM, Nuno Sá nunocesard...@gmail.com wrote:
Hello!
My aim is to add a Median or a Mean line to an histogram
in more detail, probably using the
grid.lines function. There is also the gridBase package which helps grid
and base graphics play nicely together, though it could be a bit of
overkill for just adding a vertical line.
On Tue, Nov 18, 2014 at 11:21 AM, Nuno Sá nunocesard...@gmail.com
wrote:
Hey
Hey
So, the first question is - is there an implementation of the newer
algorithms for Gap filling in any R package?
If not, I would be available to work with an expert to try to develop it
here - some of the actual IDL code is available through Dr. Xiaolin Zhu's
page:
Version 1.5 Product Documentation, subsection Product Map Projections,
they use an Albers Equal Area projection.
Thanks,
Eric
On Wed, Oct 15, 2014 at 5:16 AM, Nuno Sá nunocesard...@gmail.com wrote:
Hey
So, the first question is - is there an implementation of the newer
algorithms for Gap
and address them individually.
It's too much to ask a general question about doing that, and there is
a lot you could do first.
Cheers, Mike.
On Thu, Oct 16, 2014 at 2:29 AM, Nuno Sá nunocesard...@gmail.com wrote:
Hello Eric
Thank you, I had seen it though. Are you aware if the rgdal able
Change Institute
University of Florida
www.clas.ufl.edu/users/forrest
On Wed, Oct 8, 2014 at 7:58 PM, Nuno Sá nunocesard...@gmail.com wrote:
Hello!
ah! that return(unlist(MannKendall(x))) might have been why i didn't
manage to do it with the calc function, will try it out, thank you
? Am I forced to do series
expansions? would this not be to slow with raster? Or is there a quicker
way to iterate pixel by pixel?
Sorry for the long email and thank you in advance for any
comments/corrections/recommendations!
Best regards to all,
Nuno Sá
--
Nuno César de Sá
+351 91 961 90 37
(2*n+1)
}
phi.aprox - phi-aprox*phi.integ
p.value.rst.neeti - 2*(1-phi.aprox)
---
The result falls within 0 to 1 which is a good indication. But all depends
on everything I've asked before.
Thank you!
On 8 October 2014 22:23, Nuno Sá nunocesard...@gmail.com wrote:
Hello
and Environmental Change Institute
University of Florida
www.clas.ufl.edu/users/forrest
On Wed, Oct 8, 2014 at 6:02 PM, Nuno Sá nunocesard...@gmail.com wrote:
Hello
Using the integration by part summation was quite fast (I owe a beer to
the
ones who've developed the raster package
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