Hi all,
...think, I have to apologize
I screwed it upit is a language (spoke one...not "programming" )
thing:
I read "List of strings" which in german is "Liste von Zeichenketten".
THIS expression means this:
"A" "B" "C"
(for example).
This applied to string-join in a germenglish head for
Hi Meino,
Could you give an example of lst or line? Unlike string-append, most of the time
string-join doesn't really require an 'apply'. As we can see:
> (string-append "a" "b" "c")
"abc"
> (string-join '("a" "b" "c") ":")
"a:b:c"
While string-append takes all its arguments and concatenates the
On Sat, Oct 29, 2016 at 5:31 PM, wrote:
> At the certain point of the program I get
> a list as parameter 'lst', which contains
> the sublists of strings. I wrote this
> function:
>
>
> (define (to-txt lst)
> (if (empty? lst)
> lst
> (let ((line (car lst)))
> (begin
> (di
Hi Stephen,
thanks for yoru reply ! ::)
At the certain point of the program I get
a list as parameter 'lst', which contains
the sublists of strings. I wrote this
function:
(define (to-txt lst)
(if (empty? lst)
lst
(let ((line (car lst)))
(begin
(displayln (apply string-
Yeah that is much more concise than mine. My newbie lack of knowledge on the
stdlib is showing.
Ken
On Saturday, October 29, 2016 at 11:12:50 AM UTC-4, Stephen Chang wrote:
> string-join already expects a list of strings, so are you sure you want apply?
> Can you give a more specific example?
>
string-join already expects a list of strings, so are you sure you want apply?
Can you give a more specific example?
Perhaps map or some other iteration is what you want?
(for ([strs '(("a" "b") ("c" "D" "E"))])
(displayln (string-join strs " ")))
=>
a b
c D E
On Sat, Oct 29, 2016 at 10:27 AM
Hi,
...still improving my shortwave-broadcaster-dumper... :)
I have a list with sublists of strings, which I want to concatenate.
Each sublist shall form one line of output.
I tried 'string-append', but this gives me something like this
(excerpt):
"189RikisutvarpidRas1+2-24001234567Icelandic"
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