Re: [racket-users] confusion about call-with-current-continuation

, for example: >> >> assume exp1 is: >> (+ 1 (call/cc >> (lambda (k) ; k is the captured continuation >> (set! saved-k k) >> 0))) >> >> exp2 is: >> (println 'hello) >> >> Whether exp2 is the continuation o

[racket-users] confusion about call-with-current-continuation

may be stupid, forgive my ignorance... Thanks. Br, serioadamo97 -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-users+unsubscr...@google

Re: [racket-users] confusion about call-with-current-continuation

> (println 'hello) >>>> >>>> (saved-k 100) >>>> >>>> ;; why 'hello not print more than once?? >>>> >>>> ) >>>> >>>> The execution result of this codeis: >>>> >>>> 1 &g

Re: [racket-users] confusion about call-with-current-continuation

t;>> Dear all, > >>>>> > >>>>> I am learning call/cc in racket, so I wrote some experiment code: > >>>>> > >>>>> #lang racket > >>>>> > >>>>> (begin > >>>>> > >