Re: [racket-users] Assigning a new value to a global variable in Rachet - how?

[Daniel Prager]

The mutator form in Racket is *set! *as in

(define (smaller)
  (set! *big* (- (guess-my-number) 1)))

Also you may find it helpful to learn from Realm of Racket
 rather than Land of Lisp.

Dan



On Sat, Sep 17, 2016 at 10:22 PM, Angus  wrote:

> I am reading Chapter 2 Creating your first lisp program in the Land of
> Lisp book and attempting to use the code in Racket.  The syntax is slightly
> different and the smaller function is defined in Land of Lisp as:
>
> (defun smaller ()
>   (setf *big* (1- (guess-my-number)))
>
> where *big* is a global variable.
>
> In Racket I defined the other vars/functions like this:
> (define *small* 1)
> (define *big* 100)
> (define (guess-my-number)
>   (arithmetic-shift (+ *small* *big*) -1))
>
>
> My attempts at defining smaller in Rachet (which didn't work):
>
> (define (smaller)
>   (define *big* (- (guess-my-number) 1)))
>
> (define (smaller)
>   (set *big* (- (guess-my-number) 1)))
>
> How can I translate this function into Rachet syntax?
>
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-- 
*Daniel Prager*
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[racket-users] Assigning a new value to a global variable in Rachet - how?

[Angus]

I am reading Chapter 2 Creating your first lisp program in the Land of Lisp 
book and attempting to use the code in Racket.  The syntax is slightly 
different and the smaller function is defined in Land of Lisp as:

(defun smaller ()
  (setf *big* (1- (guess-my-number)))

where *big* is a global variable.

In Racket I defined the other vars/functions like this:
(define *small* 1)
(define *big* 100)
(define (guess-my-number) 
  (arithmetic-shift (+ *small* *big*) -1))


My attempts at defining smaller in Rachet (which didn't work):

(define (smaller)
  (define *big* (- (guess-my-number) 1)))

(define (smaller)
  (set *big* (- (guess-my-number) 1)))

How can I translate this function into Rachet syntax?

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