Yep, that works, thank you.
I did not know that EOF alone could be there.
On Monday, April 23, 2018 at 2:16:52 AM UTC+2, Sam Tobin-Hochstadt wrote:
>
> Typed Racket is reminding you that `read-line` can produce EOF. If you
> handle that (for example, with `(assert something string?)`) then it
>
That is an interesting and probably much better way to do it.
Of course I did remember -0/42 … *clears throat* (not) :D
Thank you!
On Monday, April 23, 2018 at 12:03:38 AM UTC+2, Matthew Butterick wrote:
>
> On Apr 22, 2018, at 1:40 PM, Zelphir Kaltstahl > wrote:
>
> Ah OK, I understand that add
Typed Racket is reminding you that `read-line` can produce EOF. If you
handle that (for example, with `(assert something string?)`) then it
works correctly.
Sam
On Sun, Apr 22, 2018 at 4:40 PM, Zelphir Kaltstahl
wrote:
> Ah OK, I understand that additional newline. Since the code matching the
>
> On Apr 22, 2018, at 1:40 PM, Zelphir Kaltstahl
> wrote:
>
> Ah OK, I understand that additional newline. Since the code matching the
> regex is run before that newline gets in, the newline will be on the
> input port.
>
> In DrRacket I observe the following:
>
> (I remembered that there are
On Sun, Apr 22, 2018 at 10:40 PM, Zelphir Kaltstahl
wrote:
> Ah OK, I understand that additional newline. Since the code matching the
> regex is run before that newline gets in, the newline will be on the
> input port.
>
> In DrRacket I observe the following:
>
> (I remembered that there are negat
Ah OK, I understand that additional newline. Since the code matching the
regex is run before that newline gets in, the newline will be on the
input port.
In DrRacket I observe the following:
(I remembered that there are negative numbers :D and my regex got a bit
more complicated.)
~~~
(regexp-tr
At Sun, 22 Apr 2018 14:54:26 +0200, Zelphir Kaltstahl wrote:
> I am sorry, I think I am still misunderstanding it.
>
> When I try:
>
> (regexp-try-match #rx"^[1-9]+[0-9]*$" (current-input-port))
>
> It also results immediately in:
>
> #f
Using stdin both for reading an expresion and getting i
I am sorry, I think I am still misunderstanding it.
When I try:
(regexp-try-match #rx"^[1-9]+[0-9]*$" (current-input-port))
It also results immediately in:
#f
> "^" doesn't match the beginning of the input
Is there something else I should use to start matching from the
beginning of whatever
Try `regexp-try-match`.
The `regexp-match` function on an input port consumes non-matching
input, which means that it consumes all input if a pattern that starts
"^" doesn't match the beginning of the input.
(This behavior is mentioned in the docs for `regexp-match`, but the
docs have to say so m
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