On 8/21/10 7:44 PM, Jim Gay wrote:
On Sat, Aug 21, 2010 at 1:33 PM, Wes Gamble wrote:
On 8/20/10 5:04 PM, Wes Gamble wrote:
On 8/20/10 3:04 PM, Wes Gamble wrote:
All,
I have a page X, which has several children pages underneath it (say, 10).
Is there any relatively easy way to derive the i
Thanks for the feedback Jim - will look into the children:each:index approach.
W
Sent from my iPhone
On Aug 21, 2010, at 7:44 PM, Jim Gay wrote:
> On Sat, Aug 21, 2010 at 1:33 PM, Wes Gamble wrote:
>> On 8/20/10 5:04 PM, Wes Gamble wrote:
>>
>> On 8/20/10 3:04 PM, Wes Gamble wrote:
>>
>> Al
On Sat, Aug 21, 2010 at 1:33 PM, Wes Gamble wrote:
> On 8/20/10 5:04 PM, Wes Gamble wrote:
>
> On 8/20/10 3:04 PM, Wes Gamble wrote:
>
> All,
>
> I have a page X, which has several children pages underneath it (say, 10).
>
> Is there any relatively easy way to derive the index of a given child of
On 8/20/10 5:04 PM, Wes Gamble wrote:
On 8/20/10 3:04 PM, Wes Gamble wrote:
All,
I have a page X, which has several children pages underneath it (say,
10).
Is there any relatively easy way to derive the index of a given child
of X in the list of children of X? So, for example, for the 3rd
On 8/20/10 3:04 PM, Wes Gamble wrote:
All,
I have a page X, which has several children pages underneath it (say, 10).
Is there any relatively easy way to derive the index of a given child
of X in the list of children of X? So, for example, for the 3rd
child, I need to be able to get a 3 som
All,
I have a page X, which has several children pages underneath it (say, 10).
Is there any relatively easy way to derive the index of a given child of
X in the list of children of X? So, for example, for the 3rd child, I
need to be able to get a 3 somehow in order to construct links.
I'm