-devel] Splitting a matrix by its rows into a list
There is a sleazy hack which works, but wastes a fair amount of memory: take
the transpose of the matrix in R, and use the fact that the columns of that
transpose are the rows of the original.
On Mon, Feb 18, 2013 at 5:37 PM, Dirk Eddelbuettel
This was a bug, and is fixed in rev 4262.
Romain
Le 19/02/13 00:37, Søren Højsgaard a écrit :
I want to split a matrix by its rows into a list as:
a<- matrix(letters[1:6],ncol=2)
split(a,row(a))
$`1`
[1] "a" "d"
$`2`
[1] "b" "e"
$`3`
[1] "c" "f"
I do as follows and get a strange result. An
There is a sleazy hack which works, but wastes a fair amount of memory:
take the transpose of the matrix in R, and use the fact that the columns of
that transpose are the rows of the original.
On Mon, Feb 18, 2013 at 5:37 PM, Dirk Eddelbuettel wrote:
>
> On 18 February 2013 at 17:02, Kevin Ushe
On 18 February 2013 at 17:02, Kevin Ushey wrote:
| One solution: X.row(ii) is actually generating a CharacterMatrix::Row ; ie, a
| view of that row in the CharacterMatrix, and I think you need to explicitly
| copy it to a CharacterVector and then assign that CharacterVector to the list.
|
| You c
One solution: X.row(ii) is actually generating a CharacterMatrix::Row ; ie,
a view of that row in the CharacterMatrix, and I think you need to
explicitly copy it to a CharacterVector and then assign that
CharacterVector to the list.
You could write something like:
src <- '
CharacterMatrix X(XX_
I want to split a matrix by its rows into a list as:
> a<- matrix(letters[1:6],ncol=2)
> split(a,row(a))
$`1`
[1] "a" "d"
$`2`
[1] "b" "e"
$`3`
[1] "c" "f"
I do as follows and get a strange result. Any suggestions?
Thanks in advance!
Søren
---
src <- '
CharacterMatrix X(XX_);
