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http://nagoya.apache.org/bugzilla/show_bug.cgi?id=22928 subst() with REPLACE_BACKREFERENCES cuts first 2 characters Summary: subst() with REPLACE_BACKREFERENCES cuts first 2 characters Product: Regexp Version: unspecified Platform: Other OS/Version: Other Status: NEW Severity: Normal Priority: Other Component: Other AssignedTo: [EMAIL PROTECTED] ReportedBy: [EMAIL PROTECTED] Just tried the new subst()-Method with the pattern "http://[\.\w\-\?/~_@&=%]+";, input "visit us: http://www.apache.org!"; and substitution "1234<a href="$0">$0</a>". The call of subst (input,substitute,RE.REPLACE_BACKREFERENCES) produces "visit us: 34<a href="http://www.apache.org";>http://www.apache.org</a>!", the first two numbers are cut away. Another Try: "variable=value" against "(.*?)=(.*)" and "$1_test=$2" produces following: String index out of range: -2 java.lang.StringIndexOutOfBoundsException: String index out of range: -2 at java.lang.String.substring(String.java:1480) at org.apache.regexp.RE.subst(Unknown Source) ..... Same call, just "12$1_test=$2" as the substitution produces the right result: "variable_test=value" Another Question: Why does "subst()" use $x as backreference, otherwise "\x" is used? -Sascha Spiekermann --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
