On Thu, Nov 29, 2012 at 4:42 PM, Regis d'Aubarede wrote:
>> def n_min(l,n) (1..n).map {a=l.min ; l=l-[a]; a } end
>>
>> array.sort[0, n]
>> n_min array, n
>
>
> You compar ruby implementation for n_min() with c implementation for
> sort...
Is that forbidden? You are making us
On Thu, Nov 29, 2012 at 12:02 PM, Regis d'Aubarede wrote:
>>> def n_min(l,n) (1..n).map {a=l.min ; l=l-[a]; a } end
> => nil
>>> n_min([1,2,-1,3,4],2)
> => [-1, 1]
Without having measured it that's quite an inefficient way to do it IMHO:
- you are creating a lot temporary arrays (two for each ste
Try this:
n = [4, 6, 7, 2, 15]
def min(n)
minimum = n[0]
n.each do |element|
if element < minimum
minimum = element
end
end
return minimum
end
puts min(n)
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On Thu, Nov 29, 2012 at 10:32 AM, Prog Rammer wrote:
> Joel Pearson wrote in post #1087040:
>> It looks like your browser can't establish a connection. Firewall?
>
> I can see that it opens few ie window and then throws the error. Even on
> irb i can atart a browser and go to url etc..
You may al
If you want to go through all rows then you type:
@csv.each do |row|
# do something with row
end
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It's beginner question. My advice is that you go through some beginners
tutorial about Ruby. After that you will know to implement it. Here is your
starting code:
require 'csv'
class ParseCSV
def initialize
@csv = CSV.read "data.csv"
end
def test
@csv[0] # it's first row
end
end
pc = ParseCSV
https://www.edx.org/courses/BerkeleyX/CS169.1x/2012_Fall/about is great
online course for Software as a Service with Ruby in mind.
There is 2nd part of it on edx.org site, but it's advanced. You will learn
Ruby by example, and best practices. 2nd part course:
https://www.edx.org/courses/BerkeleyX/C
