On Monday, June 30, 2014 1:52:50 AM UTC-4, John Cremona wrote:
Be careful though:
sage: (sqrt(-2)*sqrt(-3)).simplify_radical()
-sqrt(3)*sqrt(2)
i.e. you cannot use sqrt(a)*sqrt(b)=sqrt(a*b) everywhere without
reaching a contradiction.
sage: bool( (sqrt(-2)*sqrt(-3)) ==
Thanks Volker for the tip, that does the job. More comments below:
On Sun, Jun 29, 2014 at 11:52 PM, John Cremona john.crem...@gmail.com wrote:
Be careful though:
sage: (sqrt(-2)*sqrt(-3)).simplify_radical()
-sqrt(3)*sqrt(2)
i.e. you cannot use sqrt(a)*sqrt(b)=sqrt(a*b) everywhere without
On Mon, Jun 30, 2014 at 9:29 AM, Ondřej Čertík ondrej.cer...@gmail.com wrote:
Thanks Volker for the tip, that does the job. More comments below:
Another comment. Evidently Sage uses **Maxima** for
rational_simplify, hence the integer factorization that is required to
do this is not-surprisingly
On Mon, Jun 30, 2014 at 11:23 AM, William Stein wst...@gmail.com wrote:
On Mon, Jun 30, 2014 at 9:29 AM, Ondřej Čertík ondrej.cer...@gmail.com
wrote:
Thanks Volker for the tip, that does the job. More comments below:
Another comment. Evidently Sage uses **Maxima** for
rational_simplify,
On Monday, June 30, 2014 10:24:39 AM UTC-7, William wrote:
On Mon, Jun 30, 2014 at 9:29 AM, Ondřej Čertík ondrej...@gmail.com
javascript: wrote:
Thanks Volker for the tip, that does the job. More comments below:
Another comment. Evidently Sage uses **Maxima** for
rational_simplify,
sage: sqrt(3)/sqrt(15)
1/15*sqrt(15)*sqrt(3)
sage: _.radical_simplify()
1/5*sqrt(5)
On Sunday, June 29, 2014 11:22:50 PM UTC-4, Ondřej Čertík wrote:
Hi,
How do I simplify the following:
sage: sqrt(3)/sqrt(15)
1/15*sqrt(15)*sqrt(3)
sage: simplify(_)
1/15*sqrt(15)*sqrt(3)
With
Be careful though:
sage: (sqrt(-2)*sqrt(-3)).simplify_radical()
-sqrt(3)*sqrt(2)
i.e. you cannot use sqrt(a)*sqrt(b)=sqrt(a*b) everywhere without
reaching a contradiction.
sage: bool( (sqrt(-2)*sqrt(-3)) == sqrt(2)*sqrt(3) )
False
On 30 June 2014 04:31, Volker Braun vbraun.n...@gmail.com
