Hi William
On Wed, Sep 02, 2009 at 10:31:01PM -0700, William Stein wrote:
Is this the intended behaviour?
sage: z=1.+sqrt(-1); print z; z.base_ring()
1.00 + 1.00*I
Symbolic Ring
sage: z=1.+sqrt(-1.); print z; z.base_ring()
2009/9/2 Jan Groenewald j...@aims.ac.za
Hi William
On Wed, Sep 02, 2009 at 10:31:01PM -0700, William Stein wrote:
Is this the intended behaviour?
sage: z=1.+sqrt(-1); print z; z.base_ring()
1.00 + 1.00*I
Symbolic Ring
sage:
Hi William
On Wed, Sep 02, 2009 at 11:18:40PM -0700, William Stein wrote:
If you take any integer (or rational) alpha such that alpha is not a
perfect square, and try to compute sqrt(alpha), Sage promotes alpha to the
symbolic ring (SR) and takes the square root there. Thus the
I'm the originator. In fairness to Jan, I must say that I only showed
him the code and output with no other comment than that I hoped that
the students would not ask me to explain it.
I've in the meantime found a way of illustrating the point I meant to
make more clearly.
sage: z=1.+sqrt(-1)
2009/9/2 Dirk dirk.lau...@gmail.com
I'm the originator. In fairness to Jan, I must say that I only showed
him the code and output with no other comment than that I hoped that
the students would not ask me to explain it.
I've in the meantime found a way of illustrating the point I meant to
Hi William,
On Sep 3, 8:18 am, William Stein wst...@gmail.com wrote:
I am not sure what something like integers with I adjoined is?
I guess that means the complex numbers of the fomr a + bI with a, b
integers, or Z[I] (the Gaussian Integers). Mathematica prides itself
to be able to apply
2009/9/3 javier vengor...@gmail.com
Hi William,
On Sep 3, 8:18 am, William Stein wst...@gmail.com wrote:
I am not sure what something like integers with I adjoined is?
I guess that means the complex numbers of the fomr a + bI with a, b
integers, or Z[I] (the Gaussian Integers).
On Sep 3, 9:36 am, William Stein wst...@gmail.com wrote:
Sage has the Gaussian integers, and I'm sure the basic arithmetic and
functionality is as good or better than Mathematica already.
Sure, what I meant (sorry if I wasn't very clear) is to make an
straightforward way to access it, kind of
2009/9/3 javier vengor...@gmail.com:
On Sep 3, 9:36 am, William Stein wst...@gmail.com wrote:
Sage has the Gaussian integers, and I'm sure the basic arithmetic and
functionality is as good or better than Mathematica already.
Sure, what I meant (sorry if I wasn't very clear) is to make an
is this not just a curiosity? Maybe a useful one for teaching,
though, and implementing this would certainly be possible.
Very useful. I had to resort to some annoying crutches (i.e., using
the theorem in the code instead of discovering the theorem via the
demonstration of the code) to do
On Sep 3, 12:36 am, William Stein wst...@gmail.com wrote:
Sage has the Gaussian integers, and I'm sure the basic arithmetic and
functionality is as good or better than Mathematica already.
sage: R.I = ZZ[sqrt(-1)]; R
Order in Number Field in I with defining polynomial x^2 + 1
Okay, this
On Thu, Sep 3, 2009 at 9:15 AM, John H Palmieri jhpalmier...@gmail.comwrote:
On Sep 3, 12:36 am, William Stein wst...@gmail.com wrote:
Sage has the Gaussian integers, and I'm sure the basic arithmetic and
functionality is as good or better than Mathematica already.
sage: R.I =
2009/9/3 John H Palmieri jhpalmier...@gmail.com:
On Sep 3, 12:36 am, William Stein wst...@gmail.com wrote:
Sage has the Gaussian integers, and I'm sure the basic arithmetic and
functionality is as good or better than Mathematica already.
sage: R.I = ZZ[sqrt(-1)]; R
Order in Number Field
On Wed, Sep 2, 2009 at 9:56 PM, Jan Groenewald j...@aims.ac.za wrote:
Hi
Sage-support did not solicit an answer.
Both of these seem wrong:
Is this the intended behaviour?
sage: z=1.+sqrt(-1); print z; z.base_ring()
1.00 + 1.00*I
Symbolic Ring
sage:
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