On Sep 24, 6:56 pm, kcrisman kcris...@gmail.com wrote:
If I make a polynomial ring using
sage: b = PolynomialRing(ZZ, 'x')
I get some odd behavior. Namely,
sage: bool(b(x)==x)
True
I personally find this slightly worrisome, but this was a design
decision (equality respects automatic
On Fri, Sep 24, 2010 at 6:56 PM, kcrisman kcris...@gmail.com wrote:
If I make a polynomial ring using
sage: b = PolynomialRing(ZZ, 'x')
I get some odd behavior. Namely,
sage: bool(b(x)==x)
True
sage: b(x)
x
sage: type(b(x))
something about element of the ring
sage: type(x)
symbolic
On Fri, 24 Sep 2010 18:56:14 -0700 (PDT)
kcrisman kcris...@gmail.com wrote:
sage: a = FractionField(PolynomialRing(ZZ, 'x'))
sage: a(1/x)
weird error that seems to imply it has not coerced x to the
polynomial ring
Did I do something wrong, or is this a bug? Because of the initial
This is the only possibility, because the var('x') command executed
by default at startup did the assignment
x = SR('x')
and you haven't bound x to any other object. Once you execute
x = b.0
[ or one of its implicit forms like b.x=PolynomialRing(ZZ,'x')] then
x is no longer referencing
On Sat, Sep 25, 2010 at 10:51 AM, kcrisman kcris...@gmail.com wrote:
This is the only possibility, because the var('x') command executed
by default at startup did the assignment
x = SR('x')
and you haven't bound x to any other object. Once you execute
x = b.0
[ or one of its implicit
