This is also strange:
sage: (zeta1092^13) == zeta84
True
sage: zeta84^7 == zeta12
True
sage: (zeta1092^13)^7 == zeta12
False
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I've run into similar issues building development branches on other
platforms. Is there a generic workaround I should know about?
Kiran
On Friday, May 15, 2015 at 12:28:28 AM UTC-7, Volker Braun wrote:
>
> There were some changes to how we host the tarballs, get sage-6.7.rc0
> instead (which yo
Have you tried:
sage: RR.=PolynomialRing(RR)
sage: p= -51813033263*X^2+(-1291618080*sqrt(23)*sqrt(91)-7932964704*sqrt(91
)*sqrt(2)-16045600662*sqrt(23)-13979137536*sqrt(2))*X+1551583008*sqrt(23)*
sqrt(91)*sqrt(2)-296053>
sage: p.roots()
[(-1968/51813033263*sqrt(91)*(328155*sqrt(23) + 2015489*sqrt(
sage: zeta84 in Q1092
True
sage: zeta12 in Q84
True
sage: zeta12 in Q1092
False
sage: Q12.embeddings(Q1092)
[
Ring morphism:
From: Cyclotomic Field of order 12 and degree 4
To: Cyclotomic Field of order 1092 and degree 288
Defn: zeta12 |--> zeta1092^91,
Ring morphism:
From
sage: zeta84 in Q1092
True
sage: zeta12 in Q84
True
sage: zeta12 in Q1092
False
sage: Q12.embeddings(Q1092)
[
Ring morphism:
From: Cyclotomic Field of order 12 and degree 4
To: Cyclotomic Field of order 1092 and degree 288
Defn: zeta12 |--> zeta1092^91,
Ring morphism:
From
Hello,
I'm having difficulties with evaluating polynomial with symbolic
coefficients. I'm newbie to Sage and I have no idea how to tackle this.
Let's say, I have polynomial, where coefficients are symbolic. Let's call
this polynomial f. I need to perform a function on f, let's say
function(f):
On Tuesday, April 26, 2016 at 7:41:44 AM UTC-7, Laurent Decreusefond wrote:
>
>
> What does mean log(-1+e^(-2*t)) since the argument is negative ?
>
For t<0 that expression takes real values, so there the answer even makes
sense in a real setting. The answer is generally correct for complex valu
Hi everybody,
here is the result of my session on Sage 7.2 beta0 (but I guess the problem is
not specific to that version)
> sage: var('t')
> t
> sage: integrate(exp(-2*t)/(1-exp(-2*t)),t)
> 1/2*log(e^(-2*t) - 1)
What does mean log(-1+e^(-2*t)) since the argument is negative ?
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On 25/04/16 17:49, William Stein wrote:
On Mon, Apr 25, 2016 at 12:06 PM, Volker Braun wrote:
Presumable its because the RR nan doesn't correctly convert to the SR nan:
sage: NaN.is_zero()
False
sage: SR(RR('nan')).is_zero()
True
Related and confusing/wrong/inconsistent:
sage: RR('nan').is_
In a publisged paper [1] I gave a reference to a Sage script which
could reproduce the results of the paper. The output of this (using
sagetex) is also in the ArXiV version of the paper [2].
That was 3 years ago, and I just tried to see if that Sage script
would still work. It didn't. In the sc
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